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  4. Does SR have it's own asymptotic freedom?
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Does SR have it's own asymptotic freedom?

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Offline jeffreyH (OP)

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Does SR have it's own asymptotic freedom?
« on: 28/12/2018 21:40:38 »
In QCD (quantum chromodynamics) there is the concept of asymptotic freedom. Where, as the energy increases and spatial separation decreases, particles are able to move more freely. When the spatial separation is increased and the energy decreased the reverse is true. In SR the faster an object moves it gets progressively harder to move it even faster. This assumes an increase in inertia. Can anything be learned from this similarity?
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Offline jeffreyH (OP)

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Re: Does SR have it's own asymptotic freedom?
« Reply #1 on: 28/12/2018 21:42:47 »
BTW I don't want to get bogged down in a discussion of frames of reference. It can be assumed I have thought that through.
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Re: Does SR have it's own asymptotic freedom?
« Reply #2 on: 29/12/2018 01:58:03 »
lets make this simple
two collinear point never actually touch each other.  proximity makes + - particle exchange conducive
SR assumes a particle has a charge, anything with a charge meets resistance and carries a current.

if a hadron has no charge, it meets no resistance and carries no current 
the higgs boson has no charge and no spin but it has mass
a boson having mass makes it a contradiction by any definition in physics. lol

the higgs boson also travels at the velocity of light, if not faster.

i know you said that you don't wish to discuss frames of references, and that it can be assumed that you have thought it through, but seriously doubt i could learn anything from your example
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Offline yor_on

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Re: Does SR have it's own asymptotic freedom?
« Reply #3 on: 29/12/2018 11:16:34 »
You better simplify it by stating what you think is the similarity here Jefrrey? I read asymptotic freedom as belonging to the very small, as QCD, and that it there is explained by the 'field' of 'virtual photons' inside a proton. The quarks are defined by 'colors' and so are the 'virtual particles' (gluons) that then pop up inside the 'proton barrier'. When quarks are further apart their color is thought to strengthen by the 'virtual particles' but as they move together this 'sea' of 'virtuality' diminish and so the quarks 'colors' are 'weaker' which means that any 'interaction'  between quarks also seem to diminish.
« Last Edit: 29/12/2018 11:19:16 by yor_on »
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Offline jeffreyH (OP)

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Re: Does SR have it's own asymptotic freedom?
« Reply #4 on: 29/12/2018 12:38:46 »
Think of an inertial frame with an object accelerating inside it. The change in inertia can be likened to the change in color for the quark. Separation by velocity stands in for spacial separation of quarks. This may be a tenuous and or invalid relationship. However, inertial mass is so far a mystery as it relates to gravitational mass. Gravity is reminiscent of color charge in some respects. If an object does not achieve escape velocity it is confined to the gravitational well. Inertial frames are very much like free falling frames and accelerating frames are like those on the surfaces of gravitating objects.
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Offline yor_on

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Re: Does SR have it's own asymptotic freedom?
« Reply #5 on: 29/12/2018 13:38:40 »
Whether it is a correct approach or not Jeffrey, I like your thinking.
Cool, let me get of the drugs and I'll be able to respond in a more meaningful way.
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Re: Does SR have it's own asymptotic freedom?
« Reply #6 on: 29/12/2018 16:48:33 »
One stumbling block to relating momentum to color charge is the fact that the electron is elementary and not composite. As are other particles. These behave exactly the same as composite particles under the influence of gravity. Another annoying thing is that electric charge does not relate directly to mass whereas gravity does.
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Offline Bill S

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Re: Does SR have it's own asymptotic freedom?
« Reply #7 on: 29/12/2018 16:57:24 »
Quote from: Jeffrey
Where, as the energy increases and spatial separation decreases, particles are able to move more freely. When the spatial separation is increased and the energy decreased the reverse is true. In SR the faster an object moves it gets progressively harder to move it even faster. This assumes an increase in inertia. 

Possibly I’m not interpreting this correctly, but it seems to say that in QCD inertia decreases as energy input increases.

If this is the case; any asymptotic freedom inherent in SR would display opposite properties. 

I realise the thread has progressed beyond this, but I'm catching up. :)
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Offline jeffreyH (OP)

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Re: Does SR have it's own asymptotic freedom?
« Reply #8 on: 29/12/2018 22:08:37 »
You have to remember the first part is talking about quarks and the second part about SR. I do not discuss inertia with respect to QCD. This wouldn't make sense.
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