[scientizscht (OP)]

1 eV =    96.487 kJ/mol

Thanks so the 0.0591x(pH difference) calculates eV? So two solutions of 1mol of HCL each with pH difference equal to 1, can generate 0.0591x96.487 kJ of electricity?

[Bored chemist]

Thanks so the 0.0591x(pH difference) calculates eV

Near enough.
Strictly it's an integral of the voltage as the concentration changes.

[scientizscht (OP)]

Thanks so the 0.0591x(pH difference) calculates eV

Near enough.
Strictly it's an integral of the voltage as the concentration changes.

Okay will have a look, and how do I calculate the proton concentration from pH? It's been ages since I did these at school.

[Bored chemist]

The pH is the log of the reciprocal of the hydrogen ion concentration (Strictly, the H+ ion activity- but they are pretty close).
For molar HCl the pH is close to zero; for 0.5M it's close to 0.3 .

[scientizscht (OP)]

Oh then the energy is miniscule, but power is V x I, so even if voltage is small, cannot you extract more power if you have a bigger cable where protons flow in larger quantities?

[Bored chemist]

Oh then the energy is miniscule,

What energy is released from mixing two bottles with 1M of HCl and 0.5M of HCl?

Not much.