0 Members and 1 Guest are viewing this topic.
Happy to have alerted you to the continued presence of the website. I simply copied and pasted your description and it was the first item.
You would do well to review your understanding of atomic clocks, but the mechanism of the clock is irrelevant if you use the GR approach.
What’s wrong with Schild’s argument? First one needs to be careful when interpreting the statement "The frequency of light decreases..." Caution must be exercised when using "the" when discussing relativity. The frequency reckoned but which observer?
........the electron spin vector is only quantised by interacting with the magnetic moment of the nucleus , which isn't changed by gravitation. If it was, then the bandwidth as well as the observed centre frequency would change with gravitational potential.
Electron transitions, and more importantly in the case of atomic clocks, hyperfine spin-spin transitions, are associated with the absorption or emission of photons, from x-rays through the visible spectrum and down to microwaves. However you observe the characteristic photon of an atomic clock, it appears to have a higher energy if the clock is at a higher gravitational potential than the observer. Why "appears to"? (a) because that's a statement of experimental observation and (b) the electron spin vector is only quantised by interacting with the magnetic moment of the nucleus , which isn't changed by gravitation. If it was, then the bandwidth as well as the observed centre frequency would change with gravitational potential.
Maybe it'll eventually click, maybe it won't...
Which choice of reference frame would result in equating a wavelength the size of the universe?
Quote from: jeffreyH on 15/07/2017 00:16:59Maybe it'll eventually click, maybe it won't...If you are indeed responding to my post, and not someone else's...Maybe what will eventually click Jeff?
Quote from: timeyWhich choice of reference frame would result in equating a wavelength the size of the universe?EM waves have the problem that the universe has at certain times been opaque to them, which effectively prevents them from being the width of the universe.But if we move away from just EM waves, some researchers are searching for gravitational waves that were once almost the size of the universe. It is thought that quantum fluctuations in the early universe (microseconds after the Big Bang) would have produced gravitational waves. Because the universe would have become transparent to gravitational waves in this early epoch of the universe, they might be detectable now (with the right detectors).Some teams are trying to build detectors that would pick up relic gravitational waves that have frequencies as high as 1011 Hz (compared to the 50-1000Hz detectable by LIGO).But the theory of cosmic inflation suggests that the very early universe expanded faster than the speed of light for a short time, and so since that time, no waves could be formed that are the width of the universe.See: https://en.wikipedia.org/wiki/Inflation_(cosmology)
:Lee SmolinAn oscillation at a wavelength of the scale R takes up a huge part of the sky - about 60 degrees; consequently we see only a few wavelengths, and there are only a few pieces of data, so what we are seeing may just be a random statistical fluctuation. The chances of the evidence for a preferred direction being a statistical anomaly have been estimated at less than 1 part in 1000. But is may be easier to believe in this unlikely bad luck than to believe that the predictions of inflation are breaking down.
Doppler shift: the origin or base frequency (determined by design and settings of emitter) remains constant, but perceived frequency varies with motion of emitter or detector or both.
A clock is a frequency so why should there be any difference from photon to clock?
Light loses energy in leaving the surface of a mass.
Doppler shift: the origin or base frequency (determined by design and settings of emitter) remains constant, but perceived frequency varies with motion of emitter or detector or both.Measure the freq approaching as f1. Measure the freq receding as f2. Base freq f=sqrt(f1*f2).In a g-field, observing a static clock A results in a perceived doppler shift depending on observer position relative to A. Moving A to a different position changes it's base frequency. A clock is a frequency so why should there be any difference from photon to clock?Light loses energy in leaving the surface of a mass. A clock runs slower on the surface than above it, so what's the difference? And then there's the light clock! (it’s a clock and it’s light)What do you think?
A clock is a frequency so why should there be any difference from photon to clock?Light loses energy in leaving the surface of a mass. A clock runs slower on the surface than above it, so what's the difference?
:Alan, post 45Electron transitions, and more importantly in the case of atomic clocks, hyperfine spin-spin transitions, are associated with the absorption or emission of photons, from x-rays through the visible spectrum and down to microwaves. However you observe the characteristic photon of an atomic clock, it appears to have a higher energy if the clock is at a higher gravitational potential than the observer. Why "appears to"? (a) because that's a statement of experimental observation and (b) the electron spin vector is only quantised by interacting with the magnetic moment of the nucleus , which isn't changed by gravitation. If it was, then the bandwidth as well as the observed centre frequency would change with gravitational potential.
What do you think?
Quote from: timeyWhich choice of reference frame would result in equating a wavelength the size of the universe?The assumption here is that in selecting a frame of reference relative to the photon, it does not affect the size of the universe.
the clock according to GR is increasing in frequency in the higher gravity potential, and the light according to GR is decreasing in frequency in the higher gravity potential.