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We can arrive at imaginary time……
This question comes about when trying to conceive of an absolute time scale.
Quote from: Chiral This question comes about when trying to conceive of an absolute time scale. Could it be that there is no “absolute time scale”? We perceive our Universe as functioning in accordance with the “rules” of relativity, at least, on a scale that is meaningful in our everyday lives. Should we expect anything, other than “c”, to be “absolute”?
My intended meaning of "absolute" and "relative" is more akin to Kelvin vs Celsius temperature scales, in which "absolute" scales are referenced to a meaningful zero-point, whereas "relative" scales only concern themselves with the difference between two points.
If we define a universe in which no forces exist then all frames are inertial. However, if all inertial frames are in relative motion with each other then any particles traveling along with the frame will eventually collide with another particle. Therefore, these collisions act like a force. We have time. If all frames are at rest in relation to one another the same particles still exist but don't move. Where has time gone?
It would seem that when people invoke the Big Bang as "the beginning of time" that they are declaring some sort of absolute scale, in which everything that can be observed is t > 0, and that all t ≤ 0 is fanciful.
My hope is to do away with this boundary condition by exploring the possibility of a temporal dimension that is not the same as what is currently defined as time, which has no bounds.
If it has no bounds; wouldn’t that make it infinite?
Not necessarily... it just means there's no boundary. One could imagine a loop, or some other type of closed, but still unbounded time...
Fascinating piece of "history", Pete. If it were not for the comment about dating the discussion some twenty years back, it would have been interesting trying to work out when it was written.Shame about your other articles. Could you split them into postable size chunks?
An interesting but not very pertinent function is f(t) = (-t)^1.
If I have this right we need two conditions for the function.AndAnd the function should be continuous. Is this correct?
Quote from: jeffreyH on 03/05/2018 19:57:52An interesting but not very pertinent function is f(t) = (-t)^1.Is this not equivalent to f(x) = –x ? Perhaps there is a typo in your equation? f(x) = (–x)x is definitely an odd one! (all x < 0 are well defined, but then only odd positive integers get real outputs)