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There's no disagreement about frames of reference and co-ordinate systems.
(r,θ,φ) will be a natural spherical spatial co-ordinate system for them (centred at the black hole admittedly rather than being centred on themselves which is a bit unusual but not totally bizarre).
Not when the question is about what happens for the distant observer.
For the distant observer (holding constant r,θ,φ ), an infinite amount of time must pass before the rock reaches the horizon.
The rock will reach the horizon when co-ordinate t =∞
No. You're deliberately trying to slip something past people here by tacitly switching to the time experienced by the rock.
I knew "the last photon" would be mentioned before your reply appeared, it was just bound to be mentioned. I think the usual model assumes the emission of individual photons from the rock is random
Then the time when the last photon is received can't be predicted and the distant observer can't be sure that this was the last photon, there could always be one more.
the time when the last photon is received
They (co-ordinate systems) very much are abstract.
Suppose one person is using the co-ordinate system (x,y,z,t) which just turns out to be a set of co-ordinates that behave much as you'd expect. Specifically, their space is locally Minkowski space in those co-ordinates. Another person can choose to use different co-ordinates with this transformation between the co-ordinate systems:a =x ; b = y ; c = zT = x + t So that their co-ordinate system will be written as (a,b,c,T) with a,b,c exactly the same as x,y,z.
The scientist should have no difficulty identifying a suitable, natural set of co-ordinates because space won't be Minkowski space in very many co-ordinates.
Specifically, they can choose to use some arbitrary co-ordinates but they will know and can tell that the metric isn't Minkowski in those co-ordinates - it it will only take them a few experiments to determine that.
They will pick up a stop watch and set it going, they will say to themselves "that is time flowing in the positive direction".
For example they can pick up the stop watch again and try it but it doesn't record the passage of T, it only records the passage of t.
A scientist at a distance from a black hole (where the rock was heading into) can choose to use Kruskall co-ordinates but that doesn't mean that the scientist won't experience an infinite amount of time pass before the rock reaches the EH. I don't see that there needs to be an objective reality here.
I know you (Halc)
to phrase that another way, are you sure that you (Halc) aren't trying to be the absolutist and suggesting that there would be an objective reality.
Kindly accept my apologies below where I seem to be objecting to things that are perhaps not important here.
As for our distant scientist using Kruskal co-ordinates, it very much does mean that he'll experience finite time until the rock crosses the EH. That's what those coordinates are for.
Classically, there are objective events.
As you have implied in several earlier posts, the distant scientist cannot change the way her local space behaves or the laws of physics in her local space just by changing her co-ordinates.
However space isn't Mnkowski space in those new co-ordinates.
They can use Kruskal co-ordinates (T,R, Ω)
However they can't escape the fact that R=T is a surface where the Schwarzschild co-ordinate time, t is specified by t = +∞ and Schwarschild r = +2GM.
That Schwarzschild time, t, isn't unimportant or arbitrary to the scientist. That co-ordinate t is what they will experience as local time (if they hold still).
The event where the rock crosses the EH never falls inside a past light cone for an observer on the blue line of constant Schwarzschild radial co-ordinate r shown.
That's fine. Everyone agrees that there is an event with the rock on the event horizon.
But you are doing this in your prior posts, implying that 'the way space behaves' is a function of your frame dependent abstraction, and not a function of the physical geometry of the spacetime.
Is spacetime being locally Minkowskian an abstract choice, or are you referring to the fact that the physical spacetime is locally flat such that a Minkowskian metric can be meaningfully mapped to it?
That Schwarzschild time, t, isn't unimportant or arbitrary to the scientist. That co-ordinate t is what they will experience as local time (if they hold still).This is wrong. How does one 'experience' any kind of abstract time? One experiences proper time. That's the only time that's physical. One does not 'experience' the time for some worldline not in one's presence.
That is five and a half hours in French. At the very least, it's going to take me a long time to watch that. The subtitles might be automatically generated and therefore full of errors. To be quite honest, it's unlikely that I would finish watching it - but thank you for your time and effort. Someone else who speaks better French may very well enjoy that.
Space and the way things behave in space follows the physical laws of science. Changing co-ordinates can't change that.
Consider dropping a scientist and well stocked lab into some arbitrary place and time in the Universe. ...Specifically, they can choose to use some arbitrary co-ordinates but they will know and can tell that the metric isn't Minkowski in those co-ordinates - it it will only take them a few experiments to determine that.
However, some co-ordinate systems make things seem unnatural when expressed in those co-ordinates. E.g. Objects move around in circles in some some co-ordinates but physically they are always obeying Newton's laws, it's just that the chosen co-ordinates don't describe an inertial frame.
Quote from: Eternal StudentThat Schwarzschild time, t, isn't unimportant or arbitrary to the scientist. That co-ordinate t is what they will experience as local time (if they hold still).This is wrong. How does one 'experience' any kind of abstract time? One experiences proper time. That's the only time that's physical. One does not 'experience' the time for some worldline not in one's presence.
As shown on the Kruskal diagram (which was produced in paintbrush and took what seemed like hours before you criticize it again for not showing irrelevant details like the singularity).
Anyway, the event with the rock crossing over the EH is never in the past light cone of the distant scientist
So that event never causes an effect for the distant scientist.
This is getting to the crux of matter: We orbit around Sagittarius-A* which seems to be a big black hole, so we are that distant scientist, following a worldline that lies (more or less) at constant Schwarzschild radius r. Is it possible for that black hole to engulf a rock and grow, so that it's mass parameter is now larger, during a finite amount of time for us scientists?
Will the mass parameter of Sgr-A ever change in my lifetime?
(Assuming that I do not ever get off planet earth and do something like travel fast or travel toward the black hole etc). It makes little practical difference if the gravity we experience from the centre of the galaxy is always caused by a black hole of Mass parameter M plus a small rock close to the event horizon with mass m, or if eventually we just experience the gravity from a Black hole with mass parameter M+m.
However, there is a small difference, one is symmetric, the other is not.
We seem to have a fundamental disagreement about the line between arbitrary abstraction and objective (and classical) physical fact.