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I post this topic because I need it for the discussion in the topic "Is Faraday's law of induction true?"
Quote from: Mitko Gorgiev on 24/02/2020 21:39:04I post this topic because I need it for the discussion in the topic "Is Faraday's law of induction true?"This was settled almost 200 years ago. You're tilting at windmills.
Let’s look now at this drawing: two separate magnets.png (1.76 kB . 370x126 - viewed 1251 times)In this drawing there are two separate identical magnets, placed so that the magnetic field between them is the same as in the figure(a) above. When the wire is moving down through this magnetic field, then it should happen the same as in the case of figure(a). But no, in this wire no current will be induced because this magnetic field has no vertical ‘component’.
Quote from: Mitko Gorgiev on 24/02/2020 21:39:04Let’s look now at this drawing: two separate magnets.png (1.76 kB . 370x126 - viewed 1251 times)In this drawing there are two separate identical magnets, placed so that the magnetic field between them is the same as in the figure(a) above. When the wire is moving down through this magnetic field, then it should happen the same as in the case of figure(a). But no, in this wire no current will be induced because this magnetic field has no vertical ‘component’.Have you tried this yourself?
We will see.
Let’s look now at this drawing: two separate magnets.png (1.76 kB . 370x126 - viewed 2629 times)In this drawing there are two separate identical magnets, placed so that the magnetic field between them is the same as in the figure(a) above. When the wire is moving down through this magnetic field, then it should happen the same as in the case of figure(a). But no, in this wire no current will be induced because this magnetic field has no vertical ‘component’.
What do you think would happen if one of those magnets is removed? Will electric current be induced in the wire?
Let us know if the result agrees with your expectation.
The induced current in the conductor flows away from us along the section AB. In the point B the current drops to zero. Then, in the section BC, begins a current flow in the contrary direction, that is, towards us. The graph will approximately look like this:
Quote from: Mitko Gorgiev on 26/02/2020 19:58:10The induced current in the conductor flows away from us along the section AB. In the point B the current drops to zero. Then, in the section BC, begins a current flow in the contrary direction, that is, towards us. The graph will approximately look like this:Says who?That's certainly not what Faraday's law says.
So, you are moving a wire through (ideally) a uniform field?So, a bit like the Earth inductors I asked you about.Well we have known what happens there for centuries.
You were so busy calling me an intellectual that you forgot to answer my question.
Quote from: hamdani yusuf on 26/02/2020 03:27:09What do you think would happen if one of those magnets is removed? Will electric current be induced in the wire?I think there would be only a slight difference compared to the case with two magnets. Please look at figure below:The upper and the lower arrow are slightly curved because of the small vertical component at the edges. This component is further smaller if we place two magnets as much as possible close to each other:If we let a straight conductor fall down perpendicularly through this field, then on the oscilloscope (the conductor is connected to it) I expect to see two little spikes:The first spike should happen in the moment when the conductor is entering the field, the second spike when it is leaving the field. The difference between the two variants of the experiment (that is, with one and with two magnets) should be only in the magnitude of the spikes. To make this experiment as much as possible ideally, one should take very broad magnets and let the conductor fall from point A to point B, that is, the movement is the whole time inside the field. Then no spikes, no current will be induced at all (figure below).