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New Theories / Re: Perpetual motion Device...
« on: 03/07/2006 15:09:26 »quote:
how can you get the fluid to move through a magnetic shield?
The shield is on the outside of the tube.
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how can you get the fluid to move through a magnetic shield?
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The ferro fluid is going to go everywhere, it will coat the ball and be transfered to places you dont want it lowering the level more and more in the part where the ball needs to rise and jump out.
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with this ferrofluid design of spillage. Bottom line youve got to forces. the magnet and gravity which ever one is stronger is where the ferrofluid would hang out, slanting towards the weaker force, it has no reason to spin or start spinning.
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by the magnet pulling up on the fluid with more force than gravity pulls down causes the object to not be bouyant. It doesn't need to "stop" gravity or whatever you were suggesting I was saying. In this case the ferrofluid is suspended in the air, more than counteracting the force of gravity, which caused the bouyancy in the first place. To elaborate, lets say you had a cup full of ferrofluid, a magnet on the bottom which pulled the ferrofluid twice as hard as gravity. If you measured the bouyant force, when the cup was upside down, the force would be negative, or the object would move downwards against gravity, if you turned it rightside up, the bouyant force would be three times the usual all upward acting.
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Also look how big your big steel shipping buoys need to be to attain the required internal volume in order for them to have a lower density than the water their displacing due to their dry weight and for your design to revolve any buoys incorporated in it would need to be small and slim line otherwise your going to have a nightmare trying to design the components which the buoys have to pass through or over .
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You can’t use gravity to overcome your friction loses as the buoys will then be to heavy to be buoyant.
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And how many of them large steel shipping buoys do you think will be needed to lift the dry weight of the four in your drawing that are rising and are not in the water
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you’re not lifting buoys in water as they are lifting themselves. what you have to lift is the dry weight of the buoys that haven’t entered through the seal yet and the buoys which have exited the water but haven’t reached TDC yet.
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Try it.
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I think you will find that the specific gravity of water changes with its temperature.
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specific gravity, ratio of the weight of a given volume of a substance to the weight of an equal volume of some reference substance, or, equivalently, the ratio of the masses of equal volumes of the two substances.
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So since this ferrofluid resists the force of gravity using the magnets
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Nice illustration, btw
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Oh dear; can you not see that your 'tube' filled with water is almost exactly the same as a 'hosepipe' with sealed inner sections, which I used as an illustration in a previous post? It does not work!!
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Nope, you are wrong. They are equally balanced. The inner buoys will be *pulling* the exterior buoys down
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Don't be silly. That's like a piston. The buoys will have to 'lift' the water as well as themselves.
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This is another mistake in your reasoning. You forget that both sides of the line contain the same amount of buoys and are therefore equal in 'weight'.
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You can’t use gravity to overcome your friction loses as the buoys will then be to heavy to be buoyant. You can’t have weight and buoyancy in your system.
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Yes it is, your buoys are all connected to one line,one continuous circuit. The only difference is that the buoyancy force is more evenly spread with the tube.
Also a bouyancy force is created when the density of the submerged object is less than that of the fluid that it is displacing.
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Your sitting their thinking that an air filled buoy or ten air filled buoys will provide enough buoyancy to overcome all the energy loses without measuring or knowing the actual loses involved or at what points your loses are made,if you were look at the design properly you would realize that at every single point of the buoys travel around the system energy is being lost or should i say converted, even their movement through the air will cause the system to lose something, in some places they maybe minor and not measurable by you but add everything together and you would see that in order for the loop of buoys to turn energy would have to be added to the system from an outside source.
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This plus the weight of the water pushing against the buoy trying to enter the tank would be enough to halt the system alone. Also a volletball may rise quickly in water but imagine trying to push a volley ball through a open volleyball size hatch in a submarine with ten foot of water above you trying to come in.
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Start from the beginning, using only two buoys -- one entering the base of the liquid, and one just about to descend. Would that work? Of course it wouldn't!
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maybe if you did a normal fluid, without magnets, and the balls are passing through some sort of a funnel that will let the ball through one way, but will not let the water out. Any water spilled when the ball goes through can be collected in a drain and brought back to the top somehow. That requires no magnetism, and the only energy used to pump the spilled water could be generated by the wheel istelf, and excess energy will be used in whatever you are powering.
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That will not work because as soon as the ball enters the fluid through the one-way valve, it displaces a volume of that fluid which is equal to its own volume. It does so at the point of highest pressure, meaning that it must do work on the fluid equal to that pressure times its volume. Then it floats up, recovering exactly this energy (less viscous drag as well as the mgh figure for the ball, etc) by the time it reaches the top. Result: Zero net energy generated.
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how can you get the fluid to move through a magnetic shield?