[Bored chemist]

That's the problem....quantum theory is always EXPLAINING after the fact

No.
It made predictions and they were tested and found to be true.
For example
https://en.wikipedia.org/wiki/Stern%E2%80%93Gerlach_experiment

Just because you don't know the history of science doesn't mean that you can make it up.

[ron123456 (OP)]

Wave_Machine.png (95.59 kB . 401x161 - viewed 2267 times)  This picture only works in a medium for transverse waves....It won't work in a vacuum for an EM transverse wave......How are you going to oscillate the electron dipole polarity upon spontaneous emission of a photon from an atom in outer space / vacuum? The electron,  upon falling to a lower energy level has to circle the nucleus of the atom (2D for now) many times to oscilate the polarity of the formed dipole ......forget 3D just for now.....Once it is encircling the nucleus upon falling from a higher to a lower energy level ,then flip the 2D picture 90 degrees so the picture is coming out of the screen/page to see the oscillating dipole antenna's polarity change.....and the shape of the formed EM photon pulse emitted should have an initial large circumference leading edge of say E1(higher energy level) all the way to a decreasing circumference (E2 lower energy level) for it's trailing edge The frequency would be the # of times around the atom before reaching the lower level....

[Origin]

(95.59 kB . 401x161 - viewed 26 times)  This picture only works in a medium for transverse waves....It won't work in a vacuum......

So what, that's irrelevant.

.How are you going to oscillate the electron dipole upon spontaneous emission of a photon from an atom in outer space / vacuum?

You don't need to oscillate the dipole.

The electron,  upon falling to a lower energy level has to circle the nucleus of the atom (2D for now) many times to oscilate the polarity of the formed dipole

So according to this the electron can have less energy but at that lower energy level it still has not emitted a photon so it still has the higher energy.  How can on electron have 2 different energies at the same time.

Do you have any evidence for your idea or a way to experimentally show this is plausible?

[ron123456 (OP)]

Firstly I would like to apologize for stating that quantum theory is always explaining after the fact....
The picture is relevant because with that wave machine, one downward motion at one end will produce a wave in a medium but with no radiating involved .....An EM transverse wave is radiated from an antenna fed by an oscillator....Oscillation is required, not just one downward motion like a quantum jump from one level to the next.The other thing is that it is possible to have no medium in outer space where a single excited atom may radiate, ?

[Origin]

.Oscillation is required, not just one downward motion like a quantum jump from one level to the next.

You stated this a couple of times now.  So again I ask, do you have any evidence this is true?
 

The other thing is that it is possible to have no medium in outer space where a single excited atom may radiate, ?

Yes.

[Bored chemist]

Oscillation is required,

No, it is not.
Again, the problem here is your lack of knowledge.
Go and learn more.

[ron123456 (OP)]

Every antenna that I have seen has required an oscillating voltage fed to it......The far field (in phase) has broken away from the near field (reactive field) (90 degrees out of phase), due to that it cannot keep up with the frquency change of the alternating polarity of the dipole.

[Colin2B]

Every antenna that I have seen has required an oscillating voltage fed to it......

This situation is not an antenna. Oscillation of the trigger eg electron is not required.
Consider a stone dropped into a pond. The stone does not oscillate, but it transfers energy to the water by displacing it and the waves propagate outwards.
Consider also a pendulum. Your hand does not need to oscillate, it applies a displacement to the pendulum which returns towards its ‘at rest’ position etc.
Similarly the electron in moving from one energy level to another causes a displacement of the electric field strength from its 0 position etc.

[ron123456 (OP)]

 The stone dropped into a pond is a transverse wave propagating outward in a medium but will never radiate if it possibly could (but it can't in this example even with the remaining of this sentence) unless brought back up and dropped into the pond  again and again and again at such a high frequency that the wave will break up because it cannot keep up (oscillate)....In the case of an EM wave the break up field's trailing edge would be repulsed by the new non radiative (reactive) field and would radiate outward and propage with other Maxwell equations..........................In addition, the pond is a medium.....EM waves don't require a medium......

[ron123456 (OP)]

Well, I'm there......Everyones' interpretation is different from mine.......To me to transmit an EM wave,you require a transmitting antenna to release the wave...To me, everyone's interpretation only produces a non-radiative (reactive) field along the antenna and will not radiate outwards unless oscillations occur at a high frequency....Please inform me, one more time, if I'm wrong with or without an explanation.....Thx again guys.....I get it.....p.s I will attach one more  picture with my next response in a second...thx again

[ron123456 (OP)]

Here it is hopefully

[Colin2B]

I suspect that we are talking at cross purposes here.

The stone dropped into a pond is a transverse wave propagating outward in a medium but will never radiate

But it does radiate, that’s what propagating outwards is. However, I think you are using radiate to mean in all directions, whereas I would use it even for a directional case.
The point is that in the cases I mentioned an oscillating trigger is not required in order to create a wave.  If you if you apply a step input to an antenna you will get a pulse which propagates/radiates, and depending on the antenna, in all directions or in a particular direction.
In the case of atoms emitting emr, each electron transition creates a ripple (pulse) which propagates/radiates in one direction - what we measure as a photon. Multiple ripples from multiple atoms/electrons combine to create a wave effect. In the case of a tungsten filament these photons travel in all directions, in a laser only one direction.

if it possibly could (but it can't in this example even with the remaining of this sentence) unless brought back up and dropped into the pond  again and again and again at such a high frequency that the wave will break up because it cannot keep up (oscillate)....In the case of an EM wave the break up field's trailing edge would be repulsed by the new non radiative (reactive) field and would radiate outward and propage with other Maxwell equations..........................In addition, the pond is a medium.....EM waves don't require a medium......

This doesn’t make any sense at all.
Except that I agree “the pond is a medium.....EM waves don't require a medium” although I would say water is the medium rather than the pond.

[ron123456 (OP)]

Yes your philosophy will produce an EM but it will be local and will not breakaway and propagate....

[Colin2B]

Yes your philosophy will produce an EM but it will be local and will not breakaway and propagate....

The problem with your hypothesis is that it does break away and does propagate.
You need to show experimental evidence to show otherwise. The step pulse into an antenna is an experiment I have performed. With atoms, the experiment has been performed many times to generate single photon emr, now a standard technique in many labs.

[Bored chemist]

Please inform me

I did.

Oscillation is required,

No, it is not.
Again, the problem here is your lack of knowledge.
Go and learn more.

[ron123456 (OP)]

Colin2B:"In the case of atoms emitting emr, each electron transition creates a ripple (pulse) which propagates/radiates in one direction".....agreed somewhat.....but not with a quantum jump, straight down in one direction from a high energy to a lower energy level, which would ONLY produce the leading edge of a pulse.....To complete the trailing edge of the pulse, the electron has to return upward on the emulated dipole ( wihich would have changing polarity on it's ends).....The electron has to circle the nucleus on its way down to accomplish this...Probably one pulse would only produce inductive near field unless harmonics enter picture somehow?

[ron123456 (OP)]

Bored Chemist:   I'm just theorizing with one electron in an emulated changing polarity dipole instead of a fed oscillating dipole transmitter......Since I'm theorizing, let me state the setup......(2D) to simplify.......one electron instead of an oscillating fed current to an transmitting antenna.....The electron is assumed to circle the nucleus on its fall to a lower level of energy (2D).......The emulated dipole will be from the high level  above the nucleus to the low level beyond the nucleus (2D) with the electron circulating the nucleus upon falling.....Now rotate 90 degrees out of the page....We have an oscillating antenna of some sort.......This should build a near field and a far radiating field.....2D changing dimensional distance from the top and bottom of the antenna is used to vary the polarity of the ends of the emulated dipole (with a single electron upon a circular fall) from the top and bottom of the emulated antenna ....