0 Members and 1 Guest are viewing this topic.
No need. I googled it.
Can ‘Theory of Ideal Gas’ be model of Vacuum ?========== ./ John /#I think the ideal gas is a good analogy of the vacuum except the ideal gas sub-particles all travel at the speed of light C. / jerrygg38 /
Can ‘Theory of Ideal Gas’ be model of Vacuum ?========== .Comments.#Hi Sadovnik 4). In any rate, even if modern physics were 100% wrong, that would be no evidence of God's existence, let alone for the truth of any particular religion. 6). Physics WORKS. It allows us to make predictions and experiments an engineering feats. If it were deeply wrong, your computer would not work, for example. Religion doesn't work. It cannot reliably predict, it cannot be tested, it passes no experiments. 7). For this reason, it is very likely that physics is approximately true, while religion is not.
You should see some of my other stuff.SophiecentuarAre you proud of it? I would sooner feel smug if I persuaded someone with reasoned argument.
Quote from: socratus on 21/06/2009 05:26:38Can ‘Theory of Ideal Gas’ be model of Vacuum ?========== ./ John /#I think the ideal gas is a good analogy of the vacuum except the ideal gas sub-particles all travel at the speed of light C. / jerrygg38 / This does not mean that they are all traveling at a linear speed of C. Some ideal gas subparticles may be in standing wave patterns. Some spinning around at C. Some oscillating spherically, while spinning, and moving in a linear motion. The total energy in that case would be constant. thus the space molecule would have a constant energy E= MC2 The momentum would be conserved in that (Spherical + Angular + Linear) = Constant Therefore we have a tradeoff between spherical, angular, and linear momentum. A photon has mostly linear momentum. A proton has a combination of spherical and angular momtum.
========== .S.!!!========= .jerrygg38except the ideal gas sub-particles all travel at the speed of light C.======== .S.Sorry.What are parameters of your ‘‘ the ideal gas sub-particles’ ?[quote}=========== .JGG: They are my dot-waves. The high energy dot-wave has an energy: Ed = 1.616252E-28 The number in front of the exponent is the same as Planks radius exponent. This energy is the result of a plus dot of charge of 5.391237E-37 combining with a minus dot of the same charge at the Plank radius. Ed = K Qd Qd/ Rpl The energy of the low energy dot-wave depends upon the circumference of the universe E = hC/ 2pi Ru = 2.427E-52 joules The universe is filled with both low energy and high energy dot-waves======= .S. Can you show ‘the ideal gas subparticles’ and ‘ the ideal wave patterns ‘ and interaction between them ?====== . Plus dots attract minus dots. They combine to form bipolar dots. Plus dots repel minus dots. However once they are within the Plank radius, they combine. Thus at the big bang we got huge numbers of plus and minus dots all combined together. In general we will not find subparticles composed of only plus dots. They form combinations of equal numbers of plus and minus dots with additional numbers of plus or minus dots. In space combinations of dots are continually combining and breaking apart. ========= .S.After mixing all motions together(Spherical + Angular + Linear) we have = Constant = a constant energy E= MC2Not exactly clear …but interesting …. !!!The Heisenbery uncertainty principle shows that linear momentum is not conserved. The reason is that at any interaction linear momentum can transform into angular momentum. However my dot-waves also oscillated from a radius to the Plank radius. The contraction and expansion of the dot-wave either in a plane surface or a spherical surface I call spherical momentum. Therefore in order to conserve momentum and agree with the Heisenbergy principle, it is clear that one solution is that the total sum of all momentums is constant, Therefore when two dot-waves interact or two particles interact, we cannot tell what direction the particles will go within the uncertainty. A photon can enter the electron, the energy of the photon becomes part of the energy level of the electron. However the momentum is not guaranteed.
Quote from: socratus on 22/06/2009 16:20:29========= .S.After mixing all motions together(Spherical + Angular + Linear) we have = Constant = a constant energy E= MC2Not exactly clear …but interesting …. !!!The Heisenbery uncertainty principle shows that linear momentum is not conserved. The reason is that at any interaction linear momentum can transform into angular momentum. However my dot-waves also oscillated from a radius to the Plank radius. The contraction and expansion of the dot-wave either in a plane surface or a spherical surface I call spherical momentum. Therefore in order to conserve momentum and agree with the Heisenbergy principle, it is clear that one solution is that the total sum of all momentums is constant, Therefore when two dot-waves interact or two particles interact, we cannot tell what direction the particles will go within the uncertainty. A photon can enter the electron, the energy of the photon becomes part of the energy level of the electron. However the momentum is not guaranteed.=============#jerrygg38The Heisenberg uncertainty principle shows that linear momentum is not conserved.====.S.!!!========== .jerrygg38 The reason is that at any interaction linear momentum can transform into angular momentum. ========== .S.And vice versa.=============== . jerrygg38However my dot-waves also oscillated from a radius to the Plank radius.========= .S.Is it possible to say what this process goes around the Plank radius ?========== .jerrygg38 The contraction and expansion of the dot-wave either in a plane surface or a spherical surface I call spherical momentum.======== .S.Is this process goes around the Plank radius (spherical surface ) ?Is this spherical momentum connected with spherical surface ?========= .jerrygg38 Therefore in order to conserve momentum and agree with the Heisenberg principle, it is clear that one solution is that the total sum of all momentums is constant,========== .S.Something here is wrong.Why?You say:1.The Heisenberg uncertainty principle shows that linear momentum is not conserved.2.The reason is that at any interaction linear momentum can transform into angular momentum. It means that according to Heisenberg principle neither linear momentum nor angular momentum are constant parameters. But you try to conserve momentum.Why?Is it because from school we were studied about the law of momentum’s conservation, energy conservation . . etc ?And then you say: ‘it is clear that one solution is that the total sum of all momentums is constant,’.But the law is named : " The law of conservation and transformation energy / mass"And nobody in the school taught us : ‘What does the Law of transformation energy / mass means according to one single quantum of light or one single electron ?’============= .jerrygg38 Therefore when two dot-waves interact or two particles interact, we cannot tell what direction the particles will go within the uncertainty.===== .S.In my opinion the Heisenberg principle shows that particles can have different momentums.========= .jerrygg38 A photon can enter the electron, the energy of the photon becomes part of the energy level of the electron. ======= .S.Questions:Can photon and electron be one and the same particle in different conditions ? Can the difference between photon and electron depends only from frequency ?Answer:May 23, 2009.I think not just frequency, but phasing and polarity will differ. David M. Rountree, AESScientific Paranormal InvestigativeResearch Information and Technologywww.spinvestigations.orgSo. Not just frequency, phasing , but momentum also will be differ when electron ( or photon) changes its behavior. =============================== . . .jerrygg38 However the momentum is not guaranteed.====== .S.However the conversation of momentum is not guaranteed and is not constant parameter .========== .Best wishes. Israel Sadovnik. / Socratus. ============== .
========= .S.After mixing all motions together(Spherical + Angular + Linear) we have = Constant = a constant energy E= MC2Not exactly clear …but interesting …. !!!The Heisenbery uncertainty principle shows that linear momentum is not conserved. The reason is that at any interaction linear momentum can transform into angular momentum. However my dot-waves also oscillated from a radius to the Plank radius. The contraction and expansion of the dot-wave either in a plane surface or a spherical surface I call spherical momentum. Therefore in order to conserve momentum and agree with the Heisenbergy principle, it is clear that one solution is that the total sum of all momentums is constant, Therefore when two dot-waves interact or two particles interact, we cannot tell what direction the particles will go within the uncertainty. A photon can enter the electron, the energy of the photon becomes part of the energy level of the electron. However the momentum is not guaranteed.