[witsend]

Vern, you know what - I think this thread has become way too big and it's getting off topic.  And no-one's really interested in that circuit.  That's why I introduced it.  I'd quite like to start another to deal with the concepts in the model. 

For anyone who still reads this thread - here's the thing.  Read the paper.  It's the pdf file at the top of that blog.  It really does work.  The history - as a reminder - is that the IET wont forward this paper for review.  Probably because it's way too amateurish.  Whatever.  I sort of hoped that reviewers would help me get it into shape to get it published.  Anyway.  Try it out.  It costs nothing.  It needs to be disproved and I can't get it to an academic forum.  Well I can - but not through the respectable medium of journal publication.  And until then the academics wont be associated.

It's based on an idea that current flow is really just magnetic fields that use circuit components to adjust their spin or charge.  If you can get it onto applications - feel free.  No need to apply for patent rights. And with energy being so big - it should at least merit a trial test.

Just know - for those electrical engineers - the waveform is NOT periodic.  But if you prefer to measure with periodic waveforms - the same benefit using inductors in series with loads.  over unity ranges between 80 to 600% measured - but nowhere near as extraordinary as using a really inductive resistor by itself.  That benefit we've measured at 16 COP.  Then also you don't need that 555 switch.  You can use a functions generator. 

sorry - I forgot to post the link
http://rosemaryainslie.blogspot.com/

edit - Just as a reminder - if you haven't waded through this thread - sweep the frequency range until it starts oscillating.  That's usually its optimum frequency.  You'll need a fairly stable switch to manage those duty cycles.  And the best way to check the benefit quickly is to use a dual function oscilloscope. I used a 123 Fluke scopemeter.  It handles high frequency measurement.  But the real advantage is that it displays DC and AC rms voltage.  Measure across the load and display both functions.  When DC is lower than ACrms you'll be at roughly the right point.  The thinking is that DC is a fair measure of the energy delivered by the battery - because it's not discharging during the 'off' period of the duty cycle.  So that below zero spike goes back to the battery.  The energy dissipated = the product of both cycles - above and below zero, less small losses associated with phase shift and heat losses at sundry circuit components.  Then fine tune those measurements.  We used carbon shunts and checked wattage dissipated against temperature rise - platinum based temperature probes linked to digital displays.

edit - sorry yet again.  If you can find an application - there are no patent restrictions.  Just go for it.

edit - promise it'll be the last.  Any academics reading this - it needs publication.  Get your students to test and publish.  Feel free.

[lyner]

So it oscillates and you use a chopper but it's not periodic?
What does that mean?

[witsend]

Hi Socphiecentaur.  By not being periodic I mean that the one waveform is not the same as the next.  You need to average your results.  Purists don't like to do this.  So - to make it periodic - use a transformer in series.  Less efficient but a steady repeatable waveform.

cant resist asking. Are you going to test this?

[Vern]

Vern, you know what - I think this thread has become way too big and it's getting off topic.  And no-one's really interested in that circuit.  That's why I introduced it.  I'd quite like to start another to deal with the concepts in the model.

It might be interesting to know what is the link between the theory about Zipons and the circuit.

[jerrygg38]

Hi Socphiecentaur.  By not being periodic I mean that the one waveform is not the same as the next.  You need to average your results.  Purists don't like to do this.  So - to make it periodic - use a transformer in series.  Less efficient but a steady repeatable waveform.

cant resist asking. Are you going to test this?

Where is this circuit described? I don't see how to find it.
The other question I have is that you say you must average the results.
That may be a problem because in electrical theory you have to take the root mean square of all the different components and not the average.
  For example if one component has an average value of 100 and the other 1, the sum of the average components would be 101.
   However the true answer to the energy would be
  (100^2 + 1^2)^0.5 = 1.00005
 For this simple example not using the root mean square would imply a large effect for the 1 component while using the root mean square basically eliminates the 1 component.
   I do not know if this is a problem with your circuit because I have not seen the circuit.

[witsend]

Sophiecentaur.  The circuit is described in the paper, the pdf file that you access at the top of my blog.  I thought you'd read this.  The experiment is DETAILED in full.

Oh God.  I don't want to do this.  Just please, at least, read that paper. I think you'll see I've got a fair grasp of classical measurement requirements.

[lyner]

In series with what? A transformer is a four terminal device.
What determines the frequency of this, non-periodic oscillation? Is it the switch circuit?
The fluke 123 may give you RMS current but it assumes constant voltage.
The only way to be anything like sure of the actual energy delivered by the battery is to look at total discharge time and, to be sure that nothing special is happening in the battery, you would need to do it over many charge / discharge cycles. The battery could well be acting as a primary cell, in part. The energy coming from other than the recharging process.
What is "a really inductive resistor". What was its inductance? 10 or a few nH? It will have had an actual value - measurable or even calculable, roughly.

I wonder why you used carbon resistors. They are not stable or close tolerance - unlike metal film resistors. We never used carbon resistors after about 1970, in the Research Lab where I worked.

[jerrygg38]

Sophiecentaur.  The circuit is described in the paper, the pdf file that you access at the top of my blog.  I thought you'd read this.  The experiment is DETAILED in full.

Oh God.  I don't want to do this.  Just please, at least, read that paper. I think you'll see I've got a fair grasp of classical measurement requirements.

I am missing something. I do not see any PDF file listed on the starting paragraph.

[witsend]

You press the 'here' button.  It opens up the paper.

[jerrygg38]

You press the 'here' button.  It opens up the paper.

Well thank you, you gave me my morning laugh. It is hysterical!!!!

  My KIA air conditioning was fixed last week by the dealer for free. They give 60,000 mile warranty. I only have 44,000 miles. My daughter was driving it and said the lights are no longer on when you drive. They work if you turn the switch. But normally they go on in the daytime.
  I called the dealer and he told me that there was an on/off switch that could change them. He said it was in the manual. I thought a connect was pulled loose but he insisted the AC was on a different side.
  I studied the manual and looked all over for the switch. I did notice that the fog lights no longer are on. So now I have an appointment with him at 2 pm.
  So I do not have a manual for this website. Please explain how to find the "here button". I am not that computer literate.
  Perhaps my dealer can help me.
  Anyway I cannot stop laughing.

[witsend]

Open the blog.  You'll see the following - in yellow- 'Counter electromotive force enables...'

Directly under that 'in white' it says "PLEASE DOWNLOAD THE PDF FILE FROM 'HERE'  The here button is in lilac.  Put your cursor on that button and left click.

Glad to have amused you. 

[Vern]

Open the blog.  You'll see the following - in yellow- 'Counter electromotive force enables...'

Directly under that 'in white' it says "PLEASE DOWNLOAD THE PDF FILE FROM 'HERE'  The here button is in lilac.  Put your cursor on that button and left click.

Glad to have amused you especially if it gets you out of attack mode. 

jerrygg38: I modified the witsend quote and inserted a link the Blog.

[witsend]

Thanks Vern. I would not have known how to do it. 

[witsend]

Jerrygg38 - let me add to the general merriment.  I thought that I was talking to Sophiecentaur.  But I've got a shrewd idea he has also not read the paper.  I'd love to hear your opinion on it.

[witsend]

Sophiecentaur - I assume you've read the paper.  Can you please confirm this?

You can use single wound, double wound, any.  We used hefy single wound transformers but it's not necessary. The idea is to put the transformer in series with the load and before the switch.  The diode is then in parallel to both the inductor and the load resistor.

Yes, the switch determines the rate of oscillation.

I cannot understand what you mean by the Fluke 'assuming a constant voltage'.

We've done those tedious tests related to battery draw downs.  I've actually explained it to you in this thread.  Have you forgotten or did you read it?

The level of inductance of the resistor is explained in the paper.

Please read the paper and you'll see that the carbon resistors are used to determine the battery 'draw down' rate.

[jerrygg38]

Open the blog.  You'll see the following - in yellow- 'Counter electromotive force enables...'

Directly under that 'in white' it says "PLEASE DOWNLOAD THE PDF FILE FROM 'HERE'  The here button is in lilac.  Put your cursor on that button and left click.

Glad to have amused you especially if it gets you out of attack mode. 

jerrygg38: I modified the witsend quote and inserted a link the Blog.

I found the blog. I quickly went through it and it says the circuit is in the appendix.

   How do you find the appendix link??? I could not find it.

[jerrygg38]

jerrygg38: I modified the witsend quote and inserted a link the Blog.
[/quote]

I found the blog. I quickly went through it and it says the circuit is in the appendix.

   How do you find the appendix link??? I could not find it.
[/quote]

 PS: I do not know if this is applicable but in the past and probably today, you can get free power from the power company with a diode. The watthower meter does not respond to DC currents.
  So if the measuring device requires an AC signal in voltage and current, it will not read DC components.
 

[witsend]

Jerrygg38 - I'm emailing you a copy of that paper.  Watch out for it.

[jerrygg38]

Jerrygg38 - I'm emailing you a copy of that paper.  Watch out for it.

I will look for it. Hopefully it will come before I go to the dealer in one hour. Then I can start to study it while I wait for the car.

[witsend]

Hi Jerry, you should have got it.  I sent it some time back.

Edit - just realised I sent it to the wrong address.  Sorry Jerry and apologies Sophiecentaur.