The rate of evaporation of a BH is dependent upon its temperature, which is inversely dependent **upon its size;**** the smaller a BH is, the hotter it is. Relativity too, showed us that what may seem to be intuitively ridiculous doesn't mean that it's impossible.**

I think it needs to be remembered that any theory of space-time that limits it to being exclusively four-dimensional is setting that limit arbitrarily. While it's difficult to conceive of lower and higher order space-time geometries, there's no intrinsic reason why they shouldn't exist; relationships between any number of dimensions seem to be pretty straightforward and it's not difficult to work with them. Indeed, all of the Superstring theories require > four-dimensional space-time.

Therefore, if we accept that there is no fundamental limit to the number of dimensions of space-time, we should also accept that objects that exist within that space-time need not just be three dimensional, for in a > four-dimensional Superstring space-time environment every three-dimensional body that exists in our apparent four-dimensional space-time must have either zero-size in the extra dimensions, or that their size is 'curled up' to quantum sizes, and would seem to be of quantum density in those dimensions.

The Occam's Razor solution is that objects need not have a non-zero size in every dimension. Personally, I think that the family of massless particles may be an indicator of objects in our four-dimensional space-time that have less than three spatial dimensions e.g. light may only be two-dimensional, and that what is at the center of a Black Hole may actually be a zero-sized point.

The level of energy on that scale is astronomically high. A black hole need to be of Planck Mass at smallest size 2x10^-8kg. The Compton Wavelength given as lambda=h/mc=2pi(h/mc) of a black hole is proportional to its Schwartzchild Radius 1 / (2M − r); very small black holes are very hot. This is because the decrease in size and magnification of density makes these little things extremely hot. A typical micro black hole would have a temperature of 10^16 K, which is 200 GeV.

An extremal black hole will have a ground state of mass that is proportional to its charge and angular momentum. This means that the black hole will either radiate particle pairs at a much slower rate, or they won’t emit the particles at all. The following equation describes the curvature of spacetime round a massive spherical body;

ds^2=-c^2(1-2GM/c^2r)dt^2+(1-2GM/c^2)^-1_dr^2+r^2d^2

The curvature produced by this weak sea of black holes i predict would sufficient to stabilize the gravitational forces needed. Black holes are predicted to form from the collapsed states of certain large stars, about several times larger than our star. They do so, because of gravitational acceleration, given by the formula;

a=(GM_ ß)/d^2=mg

Remember, a free falling object will have the force of gravity totally cancelled out as it’s that weak. We know that from Newton’s Force Equation is derived as f= ma, where this also shows an inertial system to derive the acceleration due to gravity, and thus;

g=(GM)/d^2

So the gravitational acceleration is the mass of a gravitationally warped object M, and the distance d from it. Also, instead of working out the mass of a black hole in the conventional way, you could measure it against the gravitational acceleration formula, by;

M=gd^2/G

We use the same method to work out the mass of the earth. The G is Newtons universal gravitational constant (6.7×10-11 m3/(kg sec2). We find the Earth's mass = 9.8 × (6.4×106)2 / (6.7 × 10-11) kilograms = 6.0 × 1024 kilograms. To make an accurate measure of the gravitation being produced in the hidden dimension, we would need to take the content of the proposed dark matter, which is about 25% of matter in the universe (as predicted by NASA), and spread that out in a uniformal distribution throughout the dimension, take the gravitational affects of the black holes, but we are dealing here with very small calculations for each extremal black hole. We would need to work out how many of these micro black holes would be needed, and if they represent particles, then the sea of black holes would have a finite number of particles consistent.

The gravitational acceleration, is then simply given as g=(GM)/d^2, and calculating the mass is gd^2/G.