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Quote from: simplified on 03/10/2010 15:19:26Recoil reduces energy of a photon. Your laser gun has no recoil. Therefore energy of your photons is not reduced.Ok, but what this has to do with what pushes away a photon from light source?
Recoil reduces energy of a photon. Your laser gun has no recoil. Therefore energy of your photons is not reduced.
Let's consider analogy to a lightning. A cloud beats ground by negative charge, in the answer the ground beats the cloud by positive charge. When a particle and an antiparticle meet, they beat radiator by gravitational charge. In the answer the radiator beats them by charge of energy.
Quote from: simplified on 09/10/2010 07:24:11Let's consider analogy to a lightning. A cloud beats ground by negative charge, in the answer the ground beats the cloud by positive charge. When a particle and an antiparticle meet, they beat radiator by gravitational charge. In the answer the radiator beats them by charge of energy.hmmm...maybe you should change your nickname from "simplified" to "complicated" []
Quote from: lightarrow on 09/10/2010 20:18:23Quote from: simplified on 09/10/2010 07:24:11Let's consider analogy to a lightning. A cloud beats ground by negative charge, in the answer the ground beats the cloud by positive charge. When a particle and an antiparticle meet, they beat radiator by gravitational charge. In the answer the radiator beats them by charge of energy.hmmm...maybe you should change your nickname from "simplified" to "complicated" []Then maybe you a ruddy critic with superficial judgement []
And so if a mass is a neutralized energy then energy is an activated mass []Photon has 100% of activated mass and 0% of usual mass.Usual object has usual mass and activated mass = (Lorentz's coefficient-1)* usual mass .Usual mass isn't relative thing. Activated mass is just relative thing.I only can not understand that why photons take and mass of Sun and energy of Sun? They must to take only mass,because mass turned into their energy.
Quote from: simplified on 17/10/2010 07:21:13And so if a mass is a neutralized energy then energy is an activated mass []Photon has 100% of activated mass and 0% of usual mass.Usual object has usual mass and activated mass = (Lorentz's coefficient-1)* usual mass .Usual mass isn't relative thing. Activated mass is just relative thing.I only can not understand that why photons take and mass of Sun and energy of Sun? They must to take only mass,because mass turned into their energy.I'm sorry to tell you, but if you talk of "neutralized energy" or "activated mass", you are not talking of physics.
A vertical force can never cause a horizontal displacement; thus, a vertical force does not do work on a horizontally displaced object!!
Quote from: yor_on A vertical force can never cause a horizontal displacement; thus, a vertical force does not do work on a horizontally displaced object!!Imagine a situation in which you are standing under an object which is on rails, such that it will move only horizontally. The underside of this object slopes. You use a pole to apply vertical force against that slope, and the object responds by moving horizontally. Is this not a vertical force causing horizontal displacement?
If your physics don't answer questions then I say.
Thanks Geezer. I tried thinking of a situation in which the poll is constrained to move only vertically, but I guess whatever was constraining it would be converting vertical to horizontal force; right?What about orbital motion, though. E.g. does the Earth's gravitational attraction not act perpendicular to the direction of motion of the moon?
The gravitational force between the Moon and the Earth just maintains the Moon in an orbit around the Earth.
Quote from: Ron Hughes on 08/10/2010 17:29:09Then the equation must be wrong? I agree that photons are massless, the equation only shows the energy required to produce that photon.That equation is wrong for photons. The correct one, valid for all particles and regardless if stationary or moving (in SR) is this:E2 = (mc2)2 + (cp)2p = momentum.For light, in classical EM, E = cp. If you apply it to photons (certainly you will agree on the fact this is allowed) you find:(cp)2 = (mc2)2 + (cp)2=> 0 = (mc2)2so m = 0.
Then the equation must be wrong? I agree that photons are massless, the equation only shows the energy required to produce that photon.
E=m'c² p=(m+m')* vE - energy for any objectp - momentum for any objectm - usual mass,this mass has gravitation fieldm'- activated mass(mass turned into energy),this mass has not gravitation fieldc - light speedv - speed of object
Quote from: simplified on 20/10/2010 03:51:59 E=m'c² p=(m+m')* vE - energy for any objectp - momentum for any objectm - usual mass,this mass has gravitation fieldm'- activated mass(mass turned into energy),this mass has not gravitation fieldc - light speedv - speed of objectnonsense.
Your definition is a law for dark people.