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Care to show those calculations?That model doesn't work anyway, since we know that neutrons exist.and they aren't simply a proton plus an electron.
How much is the strong force?
why not decay to hydrogen-1?
Let's say an electron is placed in the origin of a coordinate. Three protons are arranged in equilateral triangle 1 length unit away from the electron in a flat plane. Thus, the distance between protons is https://upload.wikimedia.org/wikipedia/commons/1/11/Equilateral-triangle-heights.svgElectrostatic electric force by electron to each proton is attractive. The magnitude is inversely proportional to the square of the distance between electron and proton. In this case it's 1. The repulsive force between protons is thus 1/3.Combined repulsive force by other proton is
The existence of particles other than electron and proton, such as neutron, muon, as well as any other particles doesn't prove nor disprove the argument above, hence it's a non sequitur logical fallacy.
By the way, your model also violates conservation of lepton number. When a tritium nucleus decays into a helium-3 nucleus, it releases an electron and an electron anti-neutrino. If the atomic nucleus contains neutrons, this is not a problem. If, however, there is a proton and electron in the nucleus instead of a neutron, then the net lepton number before and after the decay are different.
Why do you refer to Uranium nucleus?
I don't know how you get those numbers
and how to isolate a single atom nucleus from interaction with its environment, including orbiting electrons and adjacent other atoms to measure the binding energy.
What are the lepton numbers of those particles?https://en.wikipedia.org/wiki/Lepton_number#Violations_of_the_lepton_number_conservation_laws
I know that the strong nuclear force is 36 orders of magnitude stronger than gravity, but could they be the same fundamental force? My thinking is that gravity on the scale of femtometers could obey the law of 1/r^19 (20 dimensions of space, 17 of which are too small to measure) which obeys the rules of how the strong nuclear force falls of significantly over minute distances. Once r is more than a few femtometers we are out of the realms of the tiny, curled up dimensions and into the three normal dimensions of space and the power of attraction is 36 orders of magnitude smaller.I am a layman, but I do wish to study physics. Please can you explain to me why this obvious (to me) solution is wrong? I am sure if it were this simple, it would have been proven a long time ago.