0 Members and 1 Guest are viewing this topic.
Now I am going to put the cat right amongst the pigeons. Some of what John says above I agree with. Not in the way it is said but what it implies. So don't get excited John I am not exactly backing you up and I would appreciate you not promoting it that way.
You require energy to move an object against a field - or turn the field's potential energy into kinetic energy when you allow an object to "fall" in the field.
My understanding of the "negative energy" phenomenon of gravity is something along these lines:Imagine two photons of sufficiently high energy interact to produce an electron positron pair in some hypothetical otherwise empty universe. We can calculate the amount of energy the photons need to have for this to happen.Now imagine the same reaction occurs very near to a massive object (in a large gravitational field). The energy required for this to happen is going to be slightly less than the energy require in the absence of this gravitational field.Now, instead of having a pre-existing massive object, let us consider forming two electron-positron pairs simultaneously. The energy required for this is going to be (slightly) less the closer the two pairs are because of their gravitational interaction with each other.Finally let us ask the question: how close must these pairs be for the energy requirement to be zero? An overly simplified equation might read something like: E=m*c2–g*m2/(4*r) = 0; solve for r given a fixed m, or solve analytically for r as a function of m--I get r = m*g/(4*c2). If I take the mass of matter in the observable universe as 1053 kg, then r ≈ 2*1025 meters (2 billion light years), which is obviously wrong, but it shows that such a concept is, in principle, possible to consider, just with less simplistic models...
Imagine two photons of sufficiently high energy interact to produce an electron positron pair in some hypothetical otherwise empty universe. We can calculate the amount of energy the photons need to have for this to happen. Now imagine the same reaction occurs very near to a massive object (in a large gravitational field). The energy required for this to happen is going to be slightly less than the energy require in the absence of this gravitational field.
Now instead of having a pre-existing massive object, let us consider forming two electron-positron pairs simultaneously. The energy required for this is going to be (slightly) less the closer the two pairs are because of their gravitational interaction with each other.
Finally let us ask the question: how close must these pairs be for the energy requirement to be zero?
Consider Ke to be the positive kinetic energy of the particle. Then -Ke is the gravitational energy (sorry John )
If -Ke falls off with the inverse square of the field the particle gradually loses all forward momentum away from the source.
You then ultimately slow down the mass by more than 100% of its original velocity. This is not only the subtraction of forward momentum but also of internal kinetic energy. It can always be considered a process of slowing of momentum even when it causes an acceleration. However the acceleration is then a positive momentum in the negative direction. This does NOT mean that gravitation has negative energy. That one stumped Maxwell and others.
We just don't know the mechanism of this action yet.
Quote from: jeffreyH on 29/10/2014 20:05:41Consider Ke to be the positive kinetic energy of the particle. Then -Ke is the gravitational energy (sorry John )The kinetic energy is positive. So if the energy you added to the brick when you lifted it. When you dropped it, some of the mass-energy of the brick, the internal kinetic energy, is converted into external kinetic energy. Again there's no actual negative energy anywhere. None of the mass energy of the brick is lost at all. Its momentum changes and the rate of energy flux changes, that's all.Quote from: jeffreyH on 29/10/2014 20:05:41If -Ke falls off with the inverse square of the field the particle gradually loses all forward momentum away from the source.When you throw the brick up, external kinetic energy is converted into internal kinetic energy. Conservation of energy applies. What on earth is external kinetic energy? It has to have a source.Quote from: jeffreyH on 29/10/2014 20:05:41You then ultimately slow down the mass by more than 100% of its original velocity. This is not only the subtraction of forward momentum but also of internal kinetic energy. It can always be considered a process of slowing of momentum even when it causes an acceleration. However the acceleration is then a positive momentum in the negative direction. This does NOT mean that gravitation has negative energy. That one stumped Maxwell and others.This isn't clear.Mathematically it's very clear.Quote from: jeffreyH on 29/10/2014 20:05:41We just don't know the mechanism of this action yet.I think we do actually. It's down to the way light bends, and the wave nature of matter. See post number 2 on this thread for my stab at explaining it.
None of the mass energy of the brick is lost at all. Its momentum changes and the rate of energy flux changes, that's all.
What on earth is external kinetic energy? It has to have a source.
How does gravity affect a wave in such a way that it reverses momentum. If you can demonstrate a proof of that then you've cracked it.
But surely gravitational force is insignificant compared to the even the weak electric force like 10^25 so why try and balance the vacuum of space with gravity. Look to the electric force or EMF differences between solar objects. It can't be measured directly but surely you do not think the surface potential of Mars much less the sun is the same as ours on earth?
though, I think you're missing something citing this. Stephen Hawking defined it this way. "Two pieces of matter that are close to each other have less [positive] energy than the same two pieces a long way apart, because you have to expend energy to separate them against the gravitational force that is pulling them together"
If you take it as stated there is nothing wrong with his reasoning. As a 'system' in where you have to expend energy to move pieces from each other. Potential energy is not as I think of it 'locally defined', so experimentally existing, unless one first define a 'container' of some sort, and conservation laws, that need this bookkeeping to present our equilibrium.
where I differ it is avoiding the 'container' but wanting to keep the conservation laws. To do that I presume that it is possible to build dimensions and a universe from locality, which it is, locally and experimentally.
To me, if I now was unclear before (quite often I'm afraid) 'negative energy' is similar to that hole that needs to be filled in charge. There's something missing to get back to a balance, and the universe abhors imbalance.
When you say that the gravitational field can not be shielded you must be implying that the graviton has zero mass as even the very low mass Neutrino can be shielded against in theory.