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If we have an observer standing on the top of a skyscraper and another observer freefalling past how do they both experience time with respect to each other?
Quote from: jeffreyH on 22/11/2014 23:19:42If we have an observer standing on the top of a skyscraper and another observer freefalling past how do they both experience time with respect to each other?The free-fall frame will have a local time which runs faster or slower hen the top of skyscraper frame due to gravitational effects. There will also be time dilation effects due to the speed of the falling frame.
That doesn't answer the question properly.
Is the falling frame's time faster or slower than that of the observer on the skyscraper?
Quote from: jeffreyHThat doesn't answer the question properly.I disagree. It sure does explain it properly. Quote from: jeffreyHIs the falling frame's time faster or slower than that of the observer on the skyscraper?This is where you're confused and what led you to believe that time throughout the falling frame should all run faster and all slower than the skyscraper frame. That's not true. The relation ship is more complicated than that because what I said that came to believe is not true.
...at the point where the two observers are at the same instantaneous elevation how is time behaving for each one with respect to the other? It is a simple enough question.
If relativity can't answer it what use is it?
Quote from: jeffreyH...at the point where the two observers are at the same instantaneous elevation how is time behaving for each one with respect to the other? It is a simple enough question.You didn't mention in previous posts that they had the same location at the moment when you compare clocks. That makes things much easier. At that moment the two rates are related by the same expression given in SR.Quote from: jeffreyHIf relativity can't answer it what use is it?I never suggested that relativity can't answer it. Of course it does.
Quote from: PmbPhy on 23/11/2014 01:44:59Quote from: jeffreyH...at the point where the two observers are at the same instantaneous elevation how is time behaving for each one with respect to the other? It is a simple enough question.You didn't mention in previous posts that they had the same location at the moment when you compare clocks. That makes things much easier. At that moment the two rates are related by the same expression given in SR.Quote from: jeffreyHIf relativity can't answer it what use is it?I never suggested that relativity can't answer it. Of course it does.Are there any experimental observations to back that up?
Jeffrey: the falling guy is moving fast, so he's subject to SR time dilation. In addition he's lower than the guy on top of the skyscraper, so he's subject to GR time dilation too.
No, it's just addition.