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It's all in the question apart from the fact that we are talking about the direction of motion or the direction of the gravitational field when considering the contraction. Meaning that the assumed increase will be in the same direction as the motion or the field.

Consider this Pete. Take a flat 1mm thick disk with the same mass as the earth. Place an object perpendicular to the plane of the disk at the centre of gravity and at a distance that is equal to the radius of the earth. Now what is the value of g coincident with this object? Is it 9.80665 m/s^2?

Quote from: jeffreyHConsider this Pete. Take a flat 1mm thick disk with the same mass as the earth. Place an object perpendicular to the plane of the disk at the centre of gravity and at a distance that is equal to the radius of the earth. Now what is the value of g coincident with this object? Is it 9.80665 m/s^2?I don't know. I'd have to calculate it. Would you like me to do this or do you know calculus well enough to do it yourself? If I do it I can do it up very nice and save me work in a PDF file and upload it to my website for you to download if you'd like. Or do you simply want the answer?

I would actually be very interested in the calculus. I'm sure others would be interested too. Thanks for the offer.

I have saved the equation and I'll work through it. I will have questions! It is an interesting exercise. I look forward to your formula for the gravitational field.

Thanks Pete that helped enormously.