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Moving the wire in the same direction(or the reverse) as the current flow will not affect the charge. All other movements will have some affect.
Quote from: hamdani yusuf on 05/06/2024 14:35:04Let's make a test case to make it clear and unambiguous. A small metal ball charged with +1 Coulomb is hung up and stationary in the frame of a lab. No, it isn't.Let's imagine a "small" metal ball about the size of a football pitch- 100 metres in diameterThe capacitance of an isolated sphere is given byso its capacitance C=4πε0RSo, with R= 50 C= 5.6 picofarads.Q = C V so if Q=1 and C= 5.6 X 10^-9, V= 178 MV.Where do you plan to get your 178 megavolt power supply from?(and it gets worse if you reduce the size of the ball.)
Let's make a test case to make it clear and unambiguous. A small metal ball charged with +1 Coulomb is hung up and stationary in the frame of a lab.
You seem to be unaware that the electric current is alternating. The frequency is 50 Hz.
Quote from: alancalverd on 05/06/2024 10:47:37For many purposes you can treat an electrolytic cell as a near-constant-current device, I have seen plenty of batteries with a voltage written on them. But I don't think I have seen one which purports to deliver a constant current.
For many purposes you can treat an electrolytic cell as a near-constant-current device,
I also see a voltmeter connected between the stands?
I can't figure out the purpose of this setup or where this could lead to a conflict with standard theory. Also why two different electrolytes?
Quote from: hamdani yusuf on 05/06/2024 14:54:01You seem to be unaware that the electric current is alternating. The frequency is 50 Hz.Ohm's Law still applies. If the wire is a perfect conductor (and you haven't suggested otherwise) the voltage across it will be zero at all times.
Either earth potential or the two cans of electrolyte which are connected together by a piece of wire. V = 0 in either case.
Collinear travel of the wire does not move the B field: if it did one would expect simple rotation of the magnet in the homopolar generator to produce an output- it does not.
Quote from: paul cotter on 05/06/2024 16:41:55Moving the wire in the same direction(or the reverse) as the current flow will not affect the charge. All other movements will have some affect.What about moving the charged ball in the same direction(or the reverse) as the current instead?
I was looking at the drawing in Reply #224 above.
Quote from: alancalverd on 06/06/2024 10:41:41Either earth potential or the two cans of electrolyte which are connected together by a piece of wire. V = 0 in either case.Then you model doesn't represent physical reality, because in reality, the voltmeter shows non-zero value. And it changes when the current is flowing through the liquids.
There are some patterns identified in the third table. Positive values mean that positively charged test particle will be pushed away from the wire. While negative values mean it will be pulled towards the wire. Zeros mean that the test particle doesn't experience any force. It happens when the current is 0, or the speed of the wire is 0.There are more positive values than negative values. Thus if the velocities of particles in the wire are random, it's more likely for the test particle to be pushed away. When the electrons in the wire are kept stationary, the Lorentz force to the test particle is proportional to the square of wire's speed. Can these patterns be explained using length contraction and time dilation?
(1) the B field does not move with the wire, lengthways(collinear).
(2) how can there be more positives than negatives in a neutral piece of matter?
Quote from: Bored chemist on 05/06/2024 16:58:26Quote from: alancalverd on 05/06/2024 10:47:37For many purposes you can treat an electrolytic cell as a near-constant-current device, I have seen plenty of batteries with a voltage written on them. But I don't think I have seen one which purports to deliver a constant current.HY's diagram shows a driving voltage source outside of the cells, and gives no details of the electrodes which we must therefore assume to be identical, so no "battery" is involved. The current is partly determined by the area of the electrodes.
You need to learn some basic physics. PS: I give up, this is utterly pointless, I don't know why I rejoined the argument. I'm out.