0 Members and 1 Guest are viewing this topic.

Well because Planck's h constant relates to the shift in frequency of light, .

Quote from: timey on 21/03/2017 04:49:39Well because Planck's h constant relates to the shift in frequency of light, .Except it doesn't. The fractional change in wavelength is L /L_{0}= 1-GM/rc^{2}Any mention of h cancels out, nothing on the right-hand side is quantised, and the effect is continuous. If you wish you can substitute f_{0}/f or E_{0}/E for L/L_{0} but the h's still cancel.

and where the value of p changes for already emitted light (in the gravitational field*) in relation to the h constant, this extra or lesser length in the wavelength isn't distance related anymore,

Yes according to the standard model. Is it possible the physics community is wording their responses with half truths to maintain their model? Although your h cancels out of your equation r is variable * c in different frames while your equation does not address the gamma term between frames in relativity mathematics.

Quote from: timey on 21/03/2017 14:21:50and where the value of p changes for already emitted light (in the gravitational field*) in relation to the h constant, this extra or lesser length in the wavelength isn't distance related anymore,Your obsession with h is worrying. p doesn't change "in relation to h". p changes because the photon's kinetic energy changes as it travels through a gravitational field gradient. The value of h is irrelevant to the fractional change in p, E, L or f, which are all related through c and given by the same equation (or its inverse, obviously).

where a is either increasing or decreasing due to a potential energy to kinetic energy conversion

(where relativistic mass in relation to kinetic energy for light in current physics remit ensures 0 acceleration/deceleration)