[nilak (OP)]

The model is available below [1].

If we keep the energy of the same wave packet when changing frequency, the total energy U must be divided by λ.
If we use the QM model, U must be divided by  λ². However, this violates the energy conservation.
I'll try to further investigate the first option, unless you find an error in the concept.

https://dwgtheory.quora.com/The-energy-of-a-particle   [1].

[nilak (OP)]

I've made the assumption that the energy of the wave increases as it travels down in a gravity well, as all theories say and I've got a new modified equation for energy. It is interesting that the frequency of the wave increases, which is also an assumption based on experimental facts, but also amplitude of the wave must increase.

Now, my model predicts an increase in amplitude, which should be measureable using an experimental setup. I don't know how QM can explain this.

If you fire a single photon at h1 down to h0, if the amplitude of an radio wave increases, then in the case if photons you should detect more photons at the bottom. However, a single photon will not divide nor by QM neither classically, therefore as a single pulse this wave should be able to knock out an electron from a stronger bond exactly like a higher frequency photon does.
In conclusion, this photon should behave like a higher frequency photon but QM will not be able to explain the amplitude increase.

 It might be a QM breakdown.

https://dwgtheory.quora.com/The-energy-of-a-particle