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As per sketch there is a box having a 10 kg.ball and counterweight mass is 10.2. This seesaw is slightly tilted towards counterweight. Now I want to know how much energy will be required as a input if I liftup the arm of 10 kg ball at 90 degree angle but remember the ball will be released only after when the arm get a certain height at 90 degree angle. The box is mounted at 45 degree angle Counter weight is permanently mounted The arm is 1 meter long The box length is 1 meter.I would like to tell that the ball will get back it's initial position due to the seesaw so there will be no need of extra energy in it.
If a ,10 kg ball fall down from 80 cm height then using mgh formula10*10*.80=80 joule
Dear Sir,The ball will fall freely in this mechanism.
You will easily understand the input as it will be very minimal.I have done it by sitting two children.Please do it.to clear your doubts regarding input energy.