[Ve9aPrim3 (OP)]

(x,y,z)=(f(x)=x)+(f(x)≠x)±(<1/≥1)

IF
Top Space (X,Y,Z)s
z=(f(x)=x)

AND
Sub Space (X,Y,Z)t
z≠(f(x)≠x)±(f(x)=(x<1)/(x≥1))

THEN
Space ±(X,Y,Z)st
y=((z=(f(x)=x))±(Z≠(f(x)≠x)±(f(x)=(x<1)/(x≥1))))

ELSE
∅

...


We all know about Outer Space, that's where our bodies live!
But how does it tie in to the Quantum field (Sub space)?
Well, if Quantum is the shadow of the Physical (Top space), then we can conclude that they are two sides of the same coin.

Example:

IF
X=0
AND
Z=0
THEN
Y=Z
ELSE
∅

IF
X=5
AND
Z=7
THEN
Y=(7=(f(5)=5))±(7≠(f(5)≠5)±(f(5)=(5<1)/(5≥1)))
ELSE
∅

Conclusion
0=(y=(z=((f(x)=x)/(f(x)≠x)+(f(x)=((x<1)/(x≥1)))))
∅=∞

And voila, a Hypersphere.

P.s.: If dividing by zero DOESN'T break this equation, then it's probably true.

[guest39538]

IF
Top Space (X,Y,Z)s
z=(f(x)=x)

AND
Sub Space (X,Y,Z)t
z≠(f(x)≠x)±(f(x)=(x<1)/(x≥1))

THEN
Space ±(X,Y,Z)st
y=((z=(f(x)=x))±(Z≠(f(x)≠x)±(f(x)=(x<1)/(x≥1))))

ELSE
∅

...


We all know about Outer Space, that's where our bodies live!
But how does it tie in to the Quantum field (Sub space)?
Well, if Quantum is the shadow of the Physical (Top space), then we can conclude that they are two sides of the same coin.

Example:

IF
X=0
AND
Z=0
THEN
Y=Z
ELSE
∅

IF
X=5
AND
Z=7
THEN
Y=(7=(f(5)=5))±(7≠(f(5)≠5)±(f(5)=(5<1)/(5≥1)))
ELSE
∅

Conclusion
y=(z=((f(x)=x)/(f(x)≠x)+(f(x)=((x<1)/(x≥1))))

And voila, a Hypersphere.

Top space means nothing, look, I understand in your own head you are reading your abstract math like reading a book.  However if you present your ''book'' in a foreign language, nobody else in the word will be able to read your book. 
You need to define your terms in their language. 
R³ defines xyz for example in real numbers.

[guest39538]

https://en.wikipedia.org/wiki/Real_coordinate_space

Start here and work from there...

[Ve9aPrim3 (OP)]

Top space means nothing, look, I understand in your own head you are reading your abstract math like reading a book.  However if you present your ''book'' in a foreign language, nobody else in the word will be able to read your book. 
You need to define your terms in their language. 
R³ defines xyz for example in real numbers.

Fair..
I was having translating my ideas because TBH I don't even have a GED so my Mathlanguage is fairly basic.. But I think I can finally paint a clearer picture...

What I mean is...
The "Outer"verse can be described as:
(f(x)=x)

The "Inner"verse can then be described as:
(f(x)≠x)±(<1/≥1)

Superimpose them to get the "Uni"verse
(f(x)=x)+(f(x)≠x)±(<1/≥1)

And now you can find any point in 3D space!

[evan_au]

(f(x)=x)+(f(x)≠x)

Let's try to analyse this little fragment of mathematics, shall we?

Lets start by defining the range of values of x - is it a logical value, a positive integer, a real number, a complex number, a complex matrix, an infinite 3D field, the set of n^th order polynomials or the set of 4-legged animals?

f(x)=x

Is this the declaration of f(x)? ie f(x) = x for all values of x? If so, why mention f(x) at all? Just say x.

Or is this the subset of values of x for which f(x)=x? To make sense of this, you had better tell us the definition of f(x).

Or is this a comparison test, as in a programming language, to ask "Is f(x) equal to x?" - a lot of the other bits look vaguely like computer code with logical IF, AND, etc. The result of a logical test is a logical value, like TRUE or FALSE.

f(x)≠x

This is clearly not the declaration of f(x)! We are told explicitly that f(x)≠x!

Or is this the subset of values of x for which f(x)≠x? To make sense of this, you had better tell us the definition of f(x). In any case, it will include all values of x which were excluded by the previous expression.

Or is this a comparison test, as in a programming language, to ask "Is f(x) not equal to x?" In which case the answer will be TRUE where the previous expression was FALSE (and vice-versa).

(f(x)=x)+(f(x)≠x)

This is clearly not about declaration of f(x)!

If it is about adding subsets of the values of x, then you have just assembled all values of x. Mathematicians would just say "for all x", or "∀x".

If this is a comparison test, you have just calculated TRUE + FALSE; there is a logical equivalent of the mathematical "+", which is the OR function. TRUE OR FALSE = TRUE. Mathematicians would just say TRUE.

My conclusion is that this is just a mashup of mathematical and computing symbols.
See: https://en.wikipedia.org/wiki/Gibberish

[Ve9aPrim3 (OP)]

If this is a comparison test, you have just calculated TRUE + FALSE; there is a logical equivalent of the mathematical "+", which is the OR function. TRUE OR FALSE = TRUE. Mathematicians would just say TRUE.

YES!!! Thank  You!!!! A comparison test!
I don't know any calculus...
...I need help testing the test.

But it does mean (Oververse)-(Underverse)=(Universe)

I never finished high school, and it just bugged me that if X is a flat piece of paper, why do the equations only let me draw along the edge?
I want to warp 3D space to whatever shape I feel and work on THAT grid!
(x,y) is just so limiting...
I'm asking IF it's true.. because I don't know.

[Ve9aPrim3 (OP)]

Quote
(f(x)=x)+(f(x)≠x)
This is clearly not about declaration of f(x)!

Sorry, I'm Stupid/Smart
I forgot to mention what I was solving for as it's clear as day to me as I forgot to even mention it, not thinking it might not be so obvious to others..

(x,y,z)=(f(x)=x)+(f(x)≠x)±(<1/≥1)

[Colin2B]

I understand in your own head you are reading your abstract math like reading a book.  However if you present your ''book'' in a foreign language, nobody else in the word will be able to read your book. 
You need to define your terms in their language. 

These are very wise words and you would do well to heed them.

Currently the ‘maths’ you are posting could easily be the equivalent of the sentence “calage nence puntop nilit wartlow quil”

Describe what you are trying to say in words rather than maths symbols you clearly do not understand. Also, confine yourself to a single thread discussing your thoughts, creating multiple threads each containing similar mashups of symbols will lead to you being banned or the threads deleted.
Your choice.
 

[Colin2B]

OP has requested all further discussion be directed to https://www.thenakedscientists.com/forum/index.php?topic=72397.0

So this topic is now locked