[Kryptid]

Reactionless drives should be possible.

Even if it was possible, this particular design doesn't work.

And yes, the math needs to be there.

I've done the math many times over in different posts demonstrating that he is wrong. Go look at replies #177, #188 and #208. Anyone who can do algebra can confirm it.

Whoops , rushed .  Still more than one pound though .
P.

Your machine can't accelerate 600,000 pounds in one second. It's limited to micrograms.

[Bored chemist]

Reactionless drives should be possible.

No, they should not.
Things that are mathematically impossible don't happen.

(Please don't mention bees)

[Bored chemist]

Whoops , rushed .  Still more than one pound though .
P.

And it's still the wrong answer.
The right answer is about a pound

[Professor Mega-Mind (OP)]

..........Jumbo Jet Comparison
 .8 GW = ~ 1.1Mhp.
This maintains 11 747-200s at cruising speed and altitude .  Thrust therein is 550Klbs.
Conceptual translation : 200,000 strong shotgun blasts per second .
Actual thrust would vary according to system efficiency .
P.M.

[Bored chemist]

And yet, it still won't work.

[Kryptid]

..........Jumbo Jet Comparison
 .8 GW = ~ 1.1Mhp.
This maintains 11 747-200s at cruising speed and altitude .  Thrust therein is 550Klbs.
Conceptual translation : 200,000 strong shotgun blasts per second .
Actual thrust would vary according to system efficiency .
P.M.

You're failing to take into account the enormous difference in the amount of mass moved between a 747 and your "engine". The 747 moves orders of magnitude more mass per second.

[Professor Mega-Mind (OP)]

.....................Balance .
Orders of magnitude SLOWER than the RELATIVISTIC electrons .  In the end , kinetic energy equals kinetic energy .  The trick is how to capture/manipulate that energy .
P.M.

[Kryptid]

Orders of magnitude SLOWER than the RELATIVISTIC electrons . 

It doesn't make up for the difference. Not even close.

In the end , kinetic energy equals kinetic energy . 

And momentum equals momentum.

The trick is how to capture/manipulate that energy .

Nature can't be tricked.

[Bored chemist]

In the end , kinetic energy equals kinetic energy

Actually, in the end, kinetic energy degrades to heat.
But momentum is still momentum.
And that's essentially why you are wrong.
Why not study some  high school physics so you can avoid making foolish statements like that?

[Professor Mega-Mind (OP)]

..............To Reply # 287
The logic chain dictates that it MUST balance out .  Here is why ; Replacing each HEX-ray with a relativistic electron immediately produces an electron stream with .8GJ of kinetic energy per second .  THAT is Compton Scattering .  If properly captured , it can produce as much push as a group of cruising jumbo-jets .  The trick is the extreme oscillation energy of the photons , being converted into lateral kinetic energy of electrons .  Nothing is conserved because the EMR is not conserved .  It is nothing , that came from nothing .  It does NOT obey the same laws of physics as actual matter , because , in essence , IT is not there !  Think of imaginary , immaterial matter that can affect "real" matter , and you start to  get the idea .
To actual science enthusiasts only.
P.M.

[Kryptid]

The logic chain dictates that it MUST balance out . 

Then your logic is flawed because the math clearly demonstrates that a few micrograms of electrons accelerated to relativistic velocities in one second produces less than one pound of thrust. The only refutation against my calculations you have given is your intuition. Intuition loses against the laws of physics.

If properly captured , it can produce as much push as a group of cruising jumbo-jets .

See reply above.

Nothing is conserved because the EMR is not conserved .

Wrong. Momentum is still conserved.

It is nothing , that came from nothing .

You clearly don't know what photons are.

It does NOT obey the same laws of physics as actual matter , because , in essence , IT is not there ! 

It obeys conservation of momentum.

[Professor Mega-Mind (OP)]

First , you are putting words in my mouth  (paragraph 1 , reply 290).  I said zilch about "accelerating a few micrograms" of anything .  The photon-electron energy transfer is an instantaneous translation of energy to a form which can produce significant impact forces .  Read Reply # 289 ; classical momentum restrictions do not apply .
P.M

[Kryptid]

I said zilch about "accelerating a few micrograms" of anything .

You didn't have to. I calculated earlier that the maximum possible mass of electrons that you can accelerate in one second due to Compton scattering when you have a 1 gigawatt laser firing 1 MeV photons is about 5.6 micrograms. It's an inevitable consequence of the way that you have set up your device. If you want to accelerate more mass than that, then you either have to increase the power of the laser or lower the energy of each individual photon. It's an unavoidable trade off.

The photon-electron energy transfer is an instantaneous translation of energy

Maybe when you have only one photon and one electron that's approximately true. If you are trying to accelerate many electrons, however, then you have to wait for all of the needed photons to arrive before you can get all of your electrons accelerated. For a given laser power, you have to wait longer in order to accelerate more electrons.

to a form which can produce significant impact forces .

If you consider about 1.4 pounds of impact force significant, that is.

Read Reply # 289 ; classical momentum restrictions do not apply .
P.M

You're wrong, of course. I calculated earlier that the photon-electron system has the exact same momentum before and after the collision. The restrictions absolutely do apply and I've already proven it.

[Bored chemist]

I said zilch about "accelerating a few micrograms" of anything . 

Yes you did.
It's just that you didn't understand what you said.

Why not study some  high school physics so you can avoid making foolish statements like that?

To actual science enthusiasts only.

Your enthusiasm is great.
Your understanding of science isn't

Were you referring to those whose enthusiasm for science is so great that that actually learn some?
hat would exclude you from your own discussion

[Professor Mega-Mind (OP)]

.No ASSUMPTIONS , LOGIC ONLY !
First , this "engine" is an ideal construct .  This means we can assume 180° impacts between each pair of photon/electrons .  The precise # of photons is actually unimportant .  What matters is that the number of photons necessary to transmit 1GW of power , is matched by an equal number of electrons .  A steady stream of electrons would be injected , to match the photons , and absorb .8 GW from them .  That equates to the .8 GJ steady impact described above .
Now then , about the personal insults : I consider that a naked demonstration of the quality of your thought processes .  Most embarrassing even to be associated with , and likely the reason why heavy-thinkers like myself are avoiding these threads .  It's too bad you can't appreciate just how pathetic your feces-chucking is to them .  I would expect much better quality control , from an institution of Cambridge's reputation , and standing .  You fool no one , but shame yourselves .
P.M. 

[Bored chemist]

Now then , about the personal insults

Like what?

[Kryptid]

No ASSUMPTIONS , LOGIC ONLY !

All logical arguments require starting assumptions.

This means we can assume 180° impacts between each pair of photon/electrons .  The precise # of photons is actually unimportant .  What matters is that the number of photons necessary to transmit 1GW of power , is matched by an equal number of electrons .  A steady stream of electrons would be injected , to match the photons , and absorb .8 GW from them .  That equates to the .8 GJ steady impact described above .

My calculations reflect those exact circumstances. The resulting thrust still did not increase above that of a laser by itself.

[Professor Mega-Mind (OP)]

Since the construct has the entire 1 GW consumed by the electrons , or reflected backwards , where exactly do you see the 1GJ per sec of kinetic energy going ?
P.

[Kryptid]

Since the construct has the entire 1 GW consumed by the electrons , or reflected backwards , where exactly do you see the 1GJ per sec of kinetic energy going ?

Most of it goes into the electrons while a little is reflected back as weakened photons. Although the rate of kinetic energy transfer is high, the mass flow is very low. Mass is a very important factor in impact force, hence why the force is so low despite the large amount of energy involved.

[Professor Mega-Mind (OP)]

.8 Gigajoules in one second is an enormous amount of kinetic energy .  It is a helluva shove , no matter WHAT does it !  The trick is finding a good catch mechanism .
P.