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  4. Transitional Photon Torpedos
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Transitional Photon Torpedos

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guest39538

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Re: Transitional Photon Torpedos
« Reply #20 on: 20/04/2019 13:53:11 »
Quote from: Bored chemist on 20/04/2019 13:29:20
I already explained why it's wrong.
Unfortunately, you were too busy  telling me how clever you are, and how little I understand , to actually understand it.
Have another go.
https://en.wikipedia.org/wiki/Dimensional_analysis

Quote from: Thebox on 20/04/2019 13:25:27
I'd demonstrate it to you in person ever so easily .
Do it by video.
I could do a video , you don't seem to understand the danger of my notion though , it is not something that I should be openly discussing in full detail .

I understand security ...
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Offline The Spoon

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Re: Transitional Photon Torpedos
« Reply #21 on: 20/04/2019 19:19:05 »
Don't feed the idiot troll
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Marked as best answer by on 25/08/2025 20:52:01

guest39538

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  • Re: Transitional Photon Torpedos
    « Reply #22 on: 20/04/2019 19:56:37 »
    Quote from: The Spoon on 20/04/2019 19:19:05
    Don't feed the idiot troll
    We won't , we'll ignore you .
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    Offline jeffreyH

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    Re: Transitional Photon Torpedos
    « Reply #23 on: 21/04/2019 13:35:22 »
    Quote from: Thebox on 20/04/2019 01:37:07

    * for u.jpg (19.08 kB . 665x526 - viewed 5881 times)


    df1f664d7a7ef3ffbc05ad5203aa2e06.gif


    vcdca247f7994f232db1fb4da88755518.gif=c


    What does U represent? What does F represent? What does X represent? What does t represent? I ask because you make none of this clear. What are the units of each variable? What dimensional analysis did you use to arrive at these units?
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    guest39538

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    Re: Transitional Photon Torpedos
    « Reply #24 on: 21/04/2019 15:23:54 »
    Quote from: jeffreyH on 21/04/2019 13:35:22
    What does U represent? What does F represent? What does X represent? What does t represent? I ask because you make none of this clear. What are the units of each variable? What dimensional analysis did you use to arrive at these units?

    How can I explain it to you without giving it away totally ?  If I explain U , internal energy  and F force,  x obviously a vector and t is time , then everyone would have the idea and the worth is lost . 
    Can I PM you the process to see what you think ?

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    Offline Kryptid

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    Re: Transitional Photon Torpedos
    « Reply #25 on: 21/04/2019 17:51:59 »
    Quote
    How can I explain it to you without giving it away totally ?

    It makes no sense to try to talk about an idea if you aren't even willing to explain it well enough that other people can understand it. If I say, "Yu politu rety lo reon" and people don't know what I'm talking about while I'm unwilling to explain it, what have I accomplished?
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    guest39538

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    Re: Transitional Photon Torpedos
    « Reply #26 on: 21/04/2019 20:57:39 »
    Quote from: Kryptid on 21/04/2019 17:51:59
    Quote
    How can I explain it to you without giving it away totally ?

    It makes no sense to try to talk about an idea if you aren't even willing to explain it well enough that other people can understand it. If I say, "Yu politu rety lo reon" and people don't know what I'm talking about while I'm unwilling to explain it, what have I accomplished?
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    Offline jeffreyH

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    Re: Transitional Photon Torpedos
    « Reply #27 on: 21/04/2019 21:17:15 »
    Why the cube of force? What on earth does that even mean? Force is a vector. The square of a vector is a scalar, a single number. Multiplying the vector again by a scalar in this situation is meaningless. You would be better off learning about tensors. The inertia tensor would be your best place to start. Try applying some thought. Then maybe you might start having productive conversations.
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    guest39538

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    Re: Transitional Photon Torpedos
    « Reply #28 on: 21/04/2019 21:29:21 »
    Quote from: jeffreyH on 21/04/2019 21:17:15
    Why the cube of force? What on earth does that even mean? Force is a vector. The square of a vector is a scalar, a single number. Multiplying the vector again by a scalar in this situation is meaningless. You would be better off learning about tensors. The inertia tensor would be your best place to start. Try applying some thought. Then maybe you might start having productive conversations.
    Why a cube of force ? Because the force is isotropic
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    Offline jeffreyH

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    Re: Transitional Photon Torpedos
    « Reply #29 on: 21/04/2019 21:38:36 »
    Isotropic means the force is the same in all directions. Cubing it doesn't show that. You are cubing the force in only one particular direction. There are 3 orthogonal axes. These are x, y and z. You could call them x1, x2 and x3 respectively. Your vectors then consist of the three values [x1 x2 x3]. You then need to know how to manipulate the values to get a meaningful result.
    « Last Edit: 21/04/2019 21:42:33 by jeffreyH »
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    guest39538

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    Re: Transitional Photon Torpedos
    « Reply #30 on: 21/04/2019 21:50:37 »
    Quote from: jeffreyH on 21/04/2019 21:38:36
    Isotropic means the force is the same in all directions. Cubing it doesn't show that. You are cubing the force in only one particular direction. There are 3 orthogonal axes. These are x, y and z. You could call them x1, x2 and x3 respectively. Your vectors then consist of the three values [x1 x2 x3]. You then need to know how to manipulate the values to get a meaningful result.
    I know  the physics involved even if my math is not precise , the force is equal in all directions  and I can manipulate the force with a variable magnitude . 

    I think I could just say  33eca6234527e135d7257bdc2add3a6f.gif
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    Offline Kryptid

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    Re: Transitional Photon Torpedos
    « Reply #31 on: 21/04/2019 22:40:45 »
    Quote from: Thebox on 21/04/2019 20:57:39

    If that was supposed to be an answer, it didn't make sense either.
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    Offline jeffreyH

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    Re: Transitional Photon Torpedos
    « Reply #32 on: 22/04/2019 12:23:35 »
    Quote from: Thebox on 21/04/2019 21:50:37
    Quote from: jeffreyH on 21/04/2019 21:38:36
    Isotropic means the force is the same in all directions. Cubing it doesn't show that. You are cubing the force in only one particular direction. There are 3 orthogonal axes. These are x, y and z. You could call them x1, x2 and x3 respectively. Your vectors then consist of the three values [x1 x2 x3]. You then need to know how to manipulate the values to get a meaningful result.
    I know  the physics involved even if my math is not precise , the force is equal in all directions  and I can manipulate the force with a variable magnitude . 

    I think I could just say  33eca6234527e135d7257bdc2add3a6f.gif

    If U is energy then multiplying it with force makes no sense either. Force times distance equals work done equals energy. However, force is a vector quantity so it isn't quite so simple.
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    guest39538

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    Re: Transitional Photon Torpedos
    « Reply #33 on: 22/04/2019 13:24:01 »
    Quote from: jeffreyH on 22/04/2019 12:23:35
    Quote from: Thebox on 21/04/2019 21:50:37
    Quote from: jeffreyH on 21/04/2019 21:38:36
    Isotropic means the force is the same in all directions. Cubing it doesn't show that. You are cubing the force in only one particular direction. There are 3 orthogonal axes. These are x, y and z. You could call them x1, x2 and x3 respectively. Your vectors then consist of the three values [x1 x2 x3]. You then need to know how to manipulate the values to get a meaningful result.
    I know  the physics involved even if my math is not precise , the force is equal in all directions  and I can manipulate the force with a variable magnitude . 

    I think I could just say  33eca6234527e135d7257bdc2add3a6f.gif

    If U is energy then multiplying it with force makes no sense either. Force times distance equals work done equals energy. However, force is a vector quantity so it isn't quite so simple.


    To be honest it needs no maths ,  I can add the maths after the experiment .


    Place U in an isotropic vice and turn the vice handle  UF³ 


    The force is centripetal and isotropic , the 55648139d1d4c1dd67f7d3a54f16be36.gif  will decrease in volume but become more dense .

    MF³


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    Offline Bored chemist

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    Re: Transitional Photon Torpedos
    « Reply #34 on: 23/04/2019 14:33:37 »
    Quote from: Thebox on 22/04/2019 13:24:01
    Quote from: jeffreyH on 22/04/2019 12:23:35
    Quote from: Thebox on 21/04/2019 21:50:37
    Quote from: jeffreyH on 21/04/2019 21:38:36
    Isotropic means the force is the same in all directions. Cubing it doesn't show that. You are cubing the force in only one particular direction. There are 3 orthogonal axes. These are x, y and z. You could call them x1, x2 and x3 respectively. Your vectors then consist of the three values [x1 x2 x3]. You then need to know how to manipulate the values to get a meaningful result.
    I know  the physics involved even if my math is not precise , the force is equal in all directions  and I can manipulate the force with a variable magnitude . 

    I think I could just say  33eca6234527e135d7257bdc2add3a6f.gif

    If U is energy then multiplying it with force makes no sense either. Force times distance equals work done equals energy. However, force is a vector quantity so it isn't quite so simple.


    To be honest it needs no maths ,  I can add the maths after the experiment .


    Place U in an isotropic vice and turn the vice handle  UF³ 


    The force is centripetal and isotropic , the 55648139d1d4c1dd67f7d3a54f16be36.gif  will decrease in volume but become more dense .

    MF³



    You still have not fixed the problem I pointed out earlier.
    So you are still posting squiggles.
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    guest39538

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    Re: Transitional Photon Torpedos
    « Reply #35 on: 24/04/2019 10:11:05 »
    Quote from: Bored chemist on 23/04/2019 14:33:37
    Quote from: Thebox on 22/04/2019 13:24:01
    Quote from: jeffreyH on 22/04/2019 12:23:35
    Quote from: Thebox on 21/04/2019 21:50:37
    Quote from: jeffreyH on 21/04/2019 21:38:36
    Isotropic means the force is the same in all directions. Cubing it doesn't show that. You are cubing the force in only one particular direction. There are 3 orthogonal axes. These are x, y and z. You could call them x1, x2 and x3 respectively. Your vectors then consist of the three values [x1 x2 x3]. You then need to know how to manipulate the values to get a meaningful result.
    I know  the physics involved even if my math is not precise , the force is equal in all directions  and I can manipulate the force with a variable magnitude . 

    I think I could just say  33eca6234527e135d7257bdc2add3a6f.gif

    If U is energy then multiplying it with force makes no sense either. Force times distance equals work done equals energy. However, force is a vector quantity so it isn't quite so simple.


    To be honest it needs no maths ,  I can add the maths after the experiment .


    Place U in an isotropic vice and turn the vice handle  UF³ 


    The force is centripetal and isotropic , the 55648139d1d4c1dd67f7d3a54f16be36.gif  will decrease in volume but become more dense .

    MF³



    You still have not fixed the problem I pointed out earlier.
    So you are still posting squiggles.
    I have values Mr C  but I can't post them or the entire process will be given away .  I trust you Mr C , want me to PM them you ?
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    guest39538

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    Re: Transitional Photon Torpedos Hwe
    « Reply #36 on: 24/04/2019 12:53:11 »
    Hey , I thought of great name for my ''business'' ,

    IQually designed …

    Copyright declared .
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    Offline Bored chemist

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    Re: Transitional Photon Torpedos
    « Reply #37 on: 24/04/2019 19:28:46 »
    Quote from: Thebox on 24/04/2019 10:11:05
    Quote from: Bored chemist on 23/04/2019 14:33:37
    Quote from: Thebox on 22/04/2019 13:24:01
    Quote from: jeffreyH on 22/04/2019 12:23:35
    Quote from: Thebox on 21/04/2019 21:50:37
    Quote from: jeffreyH on 21/04/2019 21:38:36
    Isotropic means the force is the same in all directions. Cubing it doesn't show that. You are cubing the force in only one particular direction. There are 3 orthogonal axes. These are x, y and z. You could call them x1, x2 and x3 respectively. Your vectors then consist of the three values [x1 x2 x3]. You then need to know how to manipulate the values to get a meaningful result.
    I know  the physics involved even if my math is not precise , the force is equal in all directions  and I can manipulate the force with a variable magnitude . 

    I think I could just say  33eca6234527e135d7257bdc2add3a6f.gif

    If U is energy then multiplying it with force makes no sense either. Force times distance equals work done equals energy. However, force is a vector quantity so it isn't quite so simple.


    To be honest it needs no maths ,  I can add the maths after the experiment .


    Place U in an isotropic vice and turn the vice handle  UF³ 


    The force is centripetal and isotropic , the 55648139d1d4c1dd67f7d3a54f16be36.gif  will decrease in volume but become more dense .

    MF³



    You still have not fixed the problem I pointed out earlier.
    So you are still posting squiggles.
    I have values Mr C  but I can't post them or the entire process will be given away .  I trust you Mr C , want me to PM them you ?

    The problem isn't the values.
    The problem is that your equations are still wrong because the dimensions still don't tally.

    Come back to us when you have either fixed the problem or can explain in detail why this is wrong.

    https://en.wikipedia.org/wiki/Dimensional_analysis

    (BTW, it's right, so you will need to fix the problem)
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    guest39538

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    Re: Transitional Photon Torpedos
    « Reply #38 on: 24/04/2019 19:46:47 »
    Quote from: Bored chemist on 24/04/2019 19:28:46
    (BTW, it's right, so you will need to fix the problem)
    What problem ? I can make my device with no maths , why do you think I need maths ? The math is just ''show''
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    Offline Bored chemist

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    Re: Transitional Photon Torpedos
    « Reply #39 on: 24/04/2019 21:03:46 »
    Quote from: Thebox on 24/04/2019 19:46:47
    What problem ?
    The one I keep pointing out.
    Quote from: Bored chemist on 20/04/2019 13:11:24
    Quote from: Thebox on 20/04/2019 12:40:35
    Quote from: Bored chemist on 20/04/2019 12:36:46
    You seem to be trying to use this
    https://en.wikipedia.org/wiki/Bra%E2%80%93ket_notation
     and failing.
    In any event it would be impossible to say what you mean because, for example, ρ is used for 4 different things in physics and you haven't said which one you mean.

    So, what do you think the letters mean?

    M = mass
    D=density
    V=volume
    <=less than
    >=greater than
    ρ=density
    F=force

    My math does not fail in explanation Mr C


    added - ΔΕ=9.81j/m Δ 944.076141j/m  I think it is ..

    P.s Both of those results being a dependent variable , the design is a variable design considering safety aspects .



    OK, so, as usual, you are wrong by dimensional analysis.
    Nobody is going to invest in something which a bright schoolkid could show to be wrong.
    But that won't stop you getting a patent.

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