[scientizscht (OP)]

Hello

I have a graph that shows the concentration of a product increasing as a reaction takes place.

Let's say that graph is a straight link y=ax starting from zero at time = 0 and goes to 1M when time = 1 hour.

How can I calculate from that the amount of that product in the solution of 1L?

I was tempted to calculate the area under the line but that would give units of Mxh which does not make sense.

Any idea?

[evan_au]

In general, reaction rates are not a straight line.

In a closed container, as the reactants become more dilute, the reaction rates decline.

A negative-exponential rate is more realistic.

[scientizscht (OP)]

In general, reaction rates are not a straight line.

In a closed container, as the reactants become more dilute, the reaction rates decline.

A negative-exponential rate is more realistic.

I know but the whole point of the question is different.
As I said, let's assume a straight line.
How can the amount of the product be calculated from that graph?

[Bored chemist]

What does 1M mean in this?

goes to 1M when time = 1 hour.

[scientizscht (OP)]

What does 1M mean in this?

goes to 1M when time = 1 hour.

Molarity
(are you surely a chemist?)

[alancalverd]

I have a graph that shows the concentration of a product increasing as a reaction takes place.

So that well be moles/liter  (concentration) on the y axis, and hours on the x-axis, and the concentration at any time will be the y  value for that time.

[Bored chemist]

What does 1M mean in this?

goes to 1M when time = 1 hour.

Molarity
(are you surely a chemist?)

I'm a chemist, so it's obvious that I know what it means.
So it's clear that I'm not asking you so that I can find out.

Now, let's try again
What does the M mean, (or if you like, what does "molarity" mean)?

[Bored chemist]

I have a graph that shows the concentration of a product increasing as a reaction takes place.

Let's say that graph is a straight link y=ax starting from zero at time = 0 and goes to 1M when time = 1 hour.

How can I calculate from that the amount of that product in the solution of 1L?

I was tempted to calculate the area under the line but that would give units of Mxh which does not make sense.

Any idea?