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Why should a wave itself act as a sourceof secondary waves? Why do we not include the secondary wave traveling in the backward direction from a given wavefront?
Quote from: Bored chemist on Today at 08:26:29Quote from: hamdani yusuf on Today at 06:26:05How can you say that it's the same as interference?Because the thing that causes the light to bend is interference.Is it the same as refraction and reflection?
newer versions of diffraction gratings don't involve diffraction
As regards his method, Aristotle is recognized as the inventor of scientific method because of his refined analysis of logical implications contained in demonstrative discourse,
Some theories which survived for thousands years turned out to be false.
Quote from: hamdani yusuf on 17/01/2023 08:59:00As regards his method, Aristotle is recognized as the inventor of scientific method because of his refined analysis of logical implications contained in demonstrative discourseDiscourse is not experiment, nor does Aristotelian discourse seek counterexamples to the prevailing hypothesis.
As regards his method, Aristotle is recognized as the inventor of scientific method because of his refined analysis of logical implications contained in demonstrative discourse
Nobody has falsified the hypothesis that human sacrifice guarantees good weather. And look what happens when you stop - global warming!
(a) because it doesn't - this is just a geometric construction
(b) because there is no evidence for a backward wave
Were any of them scientific theories, or are you just wasting time on irrelevances?
Quote from: Bored chemist on 17/01/2023 08:26:29Quote from: hamdani yusuf on 17/01/2023 06:26:05How can you say that it's the same as interference?Because the thing that causes the light to bend is interference.Is it the same as refraction and reflection?
Quote from: hamdani yusuf on 17/01/2023 06:26:05How can you say that it's the same as interference?Because the thing that causes the light to bend is interference.
How can you say that it's the same as interference?
Huygens says that forward propagation is the result of an infinity of infintesimal hemispherical wavelets interfering - the only nonzero resultant is "forwards".
If you truncate the infinity, say on the left, there is no source to the left to provide any destructive interference so to the left of the primary beam you can see the resultant of all the interfering wavelets from the right.
Quote from: Bored chemist on 09/01/2023 08:35:16Quote from: hamdani yusuf on 08/01/2023 23:20:45How does it explain non-diffractive edges?You still have to tell us what these are.I better show you. Quote from: hamdani yusuf on 31/03/2016 09:39:50//www.youtube.com/watch?v=FahdhYJSb9gvideo #4 Non-diffractive ObstacleQuote from: hamdani yusuf on 22/03/2017 05:18:47I have uploaded new video showing diffraction in microwave frequency.//www.youtube.com/watch?v=0NEsb8J9DroBasically, the experiment result leads us to conclude that diffraction comes from the material blocking the microwave path. When the obstruction is opaque enough, we find no diffraction. It's similar to my experiment using laser showing non-diffractive obstruction.This result is not widely known yet.
Quote from: hamdani yusuf on 08/01/2023 23:20:45How does it explain non-diffractive edges?You still have to tell us what these are.
How does it explain non-diffractive edges?
//www.youtube.com/watch?v=FahdhYJSb9gvideo #4 Non-diffractive Obstacle
I have uploaded new video showing diffraction in microwave frequency.//www.youtube.com/watch?v=0NEsb8J9DroBasically, the experiment result leads us to conclude that diffraction comes from the material blocking the microwave path. When the obstruction is opaque enough, we find no diffraction. It's similar to my experiment using laser showing non-diffractive obstruction.This result is not widely known yet.
What microwave wavelength were you using? I remarked previously that there is an increase in received signal at about 1:23, when the aluminum plate is to the right of the centerline, and I don't remember offering an explanation. Something to worry about!
A metal plate in a microwave field is potentially an emitter rather than "truncating" the beam.
I got diffracted microwave when the aluminum was shaped as a grid to allow some transmission.
Quote from: hamdani yusuf on 24/12/2022 23:42:32I've made a new video investigating diffraction of microwave using metamaterials. Previously, it was shown that an aluminum plate, which virtually reflects all of microwave power, didn't show any observable diffraction effect. This time, we tested if diffraction effect can be observed in a partially transparent obstacle which is constructed as metamaterial. The metamaterial obstacle is made from an array of aluminum stripes. There will be some follow up videos to eliminate some uncertainties around diffraction phenomenon.Here it is. I hope you enjoy it.//www.youtube.com/watch?v=CzftLbBb9Cc
I've made a new video investigating diffraction of microwave using metamaterials. Previously, it was shown that an aluminum plate, which virtually reflects all of microwave power, didn't show any observable diffraction effect. This time, we tested if diffraction effect can be observed in a partially transparent obstacle which is constructed as metamaterial. The metamaterial obstacle is made from an array of aluminum stripes. There will be some follow up videos to eliminate some uncertainties around diffraction phenomenon.
//www.youtube.com/watch?v=kEE3j9aeYU8Edge effect on diffraction of microwave.
The signal is due to reflection.
Stopping human sacrifice without causing significant change in the weather should be enough.