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In a sealed container, put some ice and water at 0 degree C (in atmospheric pressure). Is there a net heat exchange between them?
They are in a dynamic equilibrium (you can prove this with isotope tracing).
But it's not to do with the emissivity.Conductivity and random thermal fluctuations will do the job.
How is the isotope tracing done?
Do you think that emissivity has no effect here?
Do you mean they exchange phase? How is the isotope tracing done?
By definition in your question, at 0c everything is the same temperature. Unless one changes temperature no. No ice can form or melt without the exchange of energy in the form of kinetic energy of the molecules. Non nil nein nada negagive niet nix.
Fluctuations.The temperature is a property of the ensemble of molecules, but individual molecules are allowed to have different KE from the average.
What prevents the ice molecules touching the barrier from transferring the energy it just received to another molecules further from the barrier?
Quote from: hamdani yusuf on 18/03/2022 11:54:36What prevents the ice molecules touching the barrier from transferring the energy it just received to another molecules further from the barrier?Nothing.Nor will anything prevent energy transfer the other way.So the net effect will be nothing.
Ice melting is an endothermic process. The molecule undergoing this phase transition has local temperature lower than its surroundings where no phase transition is occurring
Energy will flow until equilibrium is achieved.
Quote from: hamdani yusuf on 19/03/2022 16:22:39 Energy will flow until equilibrium is achieved.It was already at equilibrium.
Quote from: hamdani yusuf on 19/03/2022 16:22:39Ice melting is an endothermic process. The molecule undergoing this phase transition has local temperature lower than its surroundings where no phase transition is occurringLike you said melting is endothermic, but there is no temperature difference so there is no bulk heat flow and hence no bulk melting. This has been said multiple time in multiple ways, so I am not sure where your problem is.