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In my other thread, I concluded that temperature of an object represents its internal kinetic energy
My hypothesis which I want to test using the experiment is that the water-ice mixture has dynamic equilibrium, which means that ,conversions occur in both direction at the same rate, instead of static equilibrium, which means that no conversion occurs at all.
Quote from: hamdani yusuf on 07/06/2022 07:58:14In my other thread, I concluded that temperature of an object represents its internal kinetic energySo you made a mistake.
Quote from: hamdani yusuf on 07/06/2022 07:58:14My hypothesis which I want to test using the experiment is that the water-ice mixture has dynamic equilibrium, which means that ,conversions occur in both direction at the same rate, instead of static equilibrium, which means that no conversion occurs at all.That is entirely obvious, since neither body has zero internal kinetic energy. On another thread we discussed the possibility of a block of ice changing shape with no net exchange of mass.
What's the correct conclusion?
temperature of an object does not represent just its internal kinetic energy
The only person expressing any disagreement is yourself, apparently based on a meaningless and irrelevant experiment and a failure to comprehend "average".
Do you have any idea to make the experiment meaningful?
If you have ice and water at equilibrium, in a closed vessel surrounded by ice and water, what other temperature can it be apart from 0C?Consider the following before you answer.(1) That if you add heat to the system, you won't change the temperature, you will just met some ice.(2) That if you remove heat from the system, you won't reduce the temperature, you will just freeze some water(3) Since the ice and water inside the container is at the same temperature as the ice and water outside it, there is no temperature gradient across the container wall, and therefore no heat transfer.So, if there was a transfer of heat, the temperature wouldn't change, and there's no mechanism for a transfer of heat anyway.
The average of n samples of x is ( xi)/n. At least it was when I was alive, but this thread seems to be some kind of scientific purgatory.
But when absolutely ****ing well everything under consideration is at 0oC, the average is zero, regardless of what definition you use.
If I mix the meat from one horse and one chicken, is it a 50:50 mixture?
He knew that the light thing and the heavy thing had to fall at the same speed- because he had considered what would happen if you tied a heavy ball to a light ball and dropped both.
Quote from: hamdani yusuf on 08/06/2022 07:24:51Do you have any idea to make the experiment meaningful?Yes.That's why I posted it.Quote from: Bored chemist on 04/06/2022 15:46:30If you have ice and water at equilibrium, in a closed vessel surrounded by ice and water, what other temperature can it be apart from 0C?Consider the following before you answer.(1) That if you add heat to the system, you won't change the temperature, you will just met some ice.(2) That if you remove heat from the system, you won't reduce the temperature, you will just freeze some water(3) Since the ice and water inside the container is at the same temperature as the ice and water outside it, there is no temperature gradient across the container wall, and therefore no heat transfer.So, if there was a transfer of heat, the temperature wouldn't change, and there's no mechanism for a transfer of heat anyway.
All you need are the laws of thermodynamics and the phase diagram for water to predict the outcome. The op, in my opinion, thinks the laws of thermodynamics are some sort of scientific 'dogma'. The laws of thermodynamics are probably the most solid and incontrovertible of all the laws of science. They have been tested and tested to the n+1 degree again and again and again(longer than this discussion).