[LB7 (OP)]

In the device:


vfz3.png (25.23 kB . 781x629 - viewed 3433 times)

It doesn't work with the friction, but only when I rotate the circle. If I rotate a little more than d2, I apply on the center of the circle a force that creates the energy d1*F and I lost d2*F.


vfd5.png (35.17 kB . 765x625 - viewed 3442 times)

And to identify d1 and d2 it is:


jh65.png (73.41 kB . 653x502 - viewed 3413 times)

Remember I measured with a real device the distance d2.

Replace the circle by a pinion and the red wall by a rack like that it is easy to give a force.

[Bored chemist]

What is F?
I guess it's a force, but what creates it and what does it act on?
What is its magnitude?
What is its direction?

[LB7 (OP)]

F, yes it is a force. The direction is the direction of the red wall. The magnitude, for example 10 N. It is a device controlled in position, I mean the rack is controlled like the pinion. It is like try to rotate a little more the pinion, I can't sure, but I apply a force F.


dcj.png (10.6 kB . 522x449 - viewed 2435 times)

[LB7 (OP)]

The example:


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956.png (58.64 kB . 233x179 - viewed 2541 times)

[LB7 (OP)]

I added a fixed dot 'a' on the drawing:


bge663.png (61.41 kB . 951x758 - viewed 2262 times)

When I wrote "It doesn't work with the friction" in the first message, it is: IF the circle doesn't rotate at all around itself, in other case it could be ok.

[LB7 (OP)]

It is easy to recover the energy and the power can be very high easily. There is no energy needed/recover from the red wall (the rack). The force F (the value of F1 or F2) can be easily 1000 N, the limit is only the limit of material. Around 45° (for the rack relatively to the horizontal), the efficiency is 1.08 but arond 63°,the efficiency is 1.23, around 78° the efficiency is 2. I attached the numerical integration. So, around 78° for example, if the force F is equal to 10000 N, with the datas inside the program (radius of the circle at 0.1 m and the height of the device at 1 m), the energy recover for xsup-xinf = 10 cm is 170 J and the energy given is 76 J.


For the calculations from 45° to 30° for example:

The distance of translation of the circle lg measured is 131 mm (the drawing)
The integral of cos(x) from 45° to 30° is 0.79
The distance d2 measured is 94 mm
The efficiency is 131*0.79/94 = 1.10
The energy recovered depends of the value of the force F. It is better to use electromagnetic waves to increase the limit of the force I think. With the mechanics due to the breaking limit of the material but at worst it is easy to build, to repair, and DIY device (not dependant of the governement).