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then how to explain the maintenance of the distance of the earth from the sun, if the sun does not turn on itself?
Quote from: Kartazion on 03/11/2021 18:43:29then how to explain the maintenance of the distance of the earth from the sun, if the sun does not turn on itself?......
I do not understand the question.
I use the magnitude of the value of the potential to claim therein a barrier of energy of potential. As a result, the object at a sufficient distance from the earth, keep by shape memory the position at the distance of r whether it is moving or not.
Clearly, if the object does not fall, it is because it is retained by this barrier of potential.
Quote from: Bored chemist on 03/11/2021 18:46:14Quote from: Kartazion on 03/11/2021 18:43:29then how to explain the maintenance of the distance of the earth from the sun, if the sun does not turn on itself?......@Bored chemist this was how to explain it other than the potential energy barrier produced by the deformation of the potential field due to gravity. It's nice to cut the sentence out of context
Nothing to do with Mandlebrot set, which is a map of complex numbers with a certain property.
It didn't matter how much of your nonsense I clipped or quoted; it's still nonsense.
My reply is still valid; we can address the question you asked by using science.Orbital mechanics- the stuff learned as a teenager- works just fine.
Why do you reject this obvious explanation?https://en.wikipedia.org/wiki/Newton%27s_cannonball
I should have presented the Exact image i was referring to in Reply #25.
But He somehow flipped the image over, like rotated it, top spinned and then like connected it...or rather showed it to be Consistent & part of a Mandelbrot Set.
So why doesn't the moon collapse on earth?
By what mechanism is it retained?
Must admit that there is a barrier to something that holds it back
But my quest remains. Please, how does the moon stay at a distance without collapsing to earth with an answer for everyone?
Who tells you that I reject it?
I am not inventing anything new. I'm just making the point of a gravitational potential energy barrier.
Because of its tangential velocity relative to earth.
See above.
See the answer to the first question.
We must admit you don't know what you are talking about.
You do.
That is pseudoscience garbage. There is no repulsive force from the earth on the moon to keep it in orbit. You are simply confused.
A potential barrier is a high level of energy that a mechanical object must temporarily possess in order to follow a trajectory along which overall less energy is required, the part beyond the barrier being impossible for it if it does not. not reach that level.Case of gravityLet be an object of mass m moving on a curve located in a vertical plane. Gravity is g. We have dealt with the case of potential cuvettes (cf. potential well) and we have introduced the “turning points” such that mgH (s) = E.In the case of a potential barrier,either the particle has an energy mgH °> mg Hmax, and the particle crosses the barrier and is found with a probability = 100% on the other side: T = 1.either the particle does not have sufficient energy and it is reflected by the barrier: R = 1.An innocuous remark by Corinne (1757?), Taken up by Appell (CRAS 1878), involves the following symmetry: if we change g to - g, the basin is transformed into a barrier. But if we change t in an imaginary time it, then we find the solution of the barrier as an analytical extension of the solution for the cuvette.The obvious example is that of the bridge-shaped cycloid, therefore symmetrical to the isochronous Huygens cup-cycloid: instead of finding solutions in sin t and cos t, we will find solutions in sh t and ch t.Appell made the same remark for the case of the simple pendulum: he then found the double periodicity of sn z, cn z and dn z, which Jacobi (and partially Abel) had found long before.This remark by Corinne will serve Wick to understand Gamow's “semi-classical” tunnel effect and very quickly find the famous tunnel transmission laws, so useful in radioactivity, in thermoelectric effect, in thermonuclear fusion, in spintronics, in quantum chemistry. : this effect of the particle-wave will be due to the evanescence of its action S (E).
Tangential velocity does not explain the physical mechanism of why gravity is no longer exerted.
It reminds me that Einstein equivalence principle said that acceleration makes us subject to gravity.
So if acceleration turns it into gravity
It doesn't say that.
Nonsense.If you would just read about orbital mechanics you would see that your ignorant pseudoscience is trying explain something that is already understood. This is something that has been understood for 400 years!
Ignorant. The equivalence principle in theory of general relativity says that well.
Even since the relativity of Einstein? Well done. I understand why you are unable to make the link between GR and QM. The OP must try to make this link.
The equivalency principle doesn't state this:"It reminds me that Einstein equivalence principle said that acceleration makes us subject to gravity."
... For example, passing over a black hole would have an enormous gravitational potential energy. Simply. I say that passing over a black hole would draw the curve of the Higgs field.
With the equivalence principle and in the small regions of space time, you cannot tell the difference between upward acceleration and downward gravity.
Now, Mr. is playing on words
You will tell me, explain the Higgs field as I explain it (with a level 101) can scare the compared to the total confusion of the interpretation of the QM with a endless list of formulas, while the the explanation of the universe remains very simple and you already know it.
Simple and wrong.
Quote from: Kartazion on 09/11/2021 00:12:58... For example, passing over a black hole would have an enormous gravitational potential energy. Simply. I say that passing over a black hole would draw the curve of the Higgs field.Simple and wrong.
As usual you do not justify the reason of your negation. Why the black hole does not have enormous gravitational potential energy?
Simply. I say that passing over a black hole would draw the curve of the Higgs field.
Quote from: Kartazion on 10/11/2021 05:28:47As usual you do not justify the reason of your negation. Why the black hole does not have enormous gravitational potential energy?An isolated black hole would have no potential energy, that follows from the definition of gravitational potential energy.
However the main issue with your statement is this:Quote from: Kartazion on 10/11/2021 05:28:47Simply. I say that passing over a black hole would draw the curve of the Higgs field.That is simply gibberish.