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Any *fixed* region of space containing an energy E has a mass E/c2.
Quote from: lightarrow on 23/09/2009 19:55:18Any *fixed* region of space containing an energy E has a mass E/c2.Hi lightarrow! How goes it? I found this response from you to be unexpected. Normally in the passt you have used the term "mass" to mean proper mass. Here you use it to mean relativistic mass. Is there a reason for this that I'm not aware of? Thanks.Pete
Quote from: Pmb on 30/09/2009 02:19:50Quote from: lightarrow on 23/09/2009 19:55:18Any *fixed* region of space containing an energy E has a mass E/c2.Hi lightarrow! How goes it? I found this response from you to be unexpected. Normally in the passt you have used the term "mass" to mean proper mass. Here you use it to mean relativistic mass. Is there a reason for this that I'm not aware of? Thanks.PeteNo, it's proper = invariant mass even here. If the region of space is fixed, then the total momentum is zero, so from E2 = (cp)2 + (mc2)2 we can infer that m = E/c2.
Quote from: lightarrow on 30/09/2009 07:41:53Quote from: Pmb on 30/09/2009 02:19:50Quote from: lightarrow on 23/09/2009 19:55:18Any *fixed* region of space containing an energy E has a mass E/c2.Hi lightarrow! How goes it? I found this response from you to be unexpected. Normally in the passt you have used the term "mass" to mean proper mass. Here you use it to mean relativistic mass. Is there a reason for this that I'm not aware of? Thanks.PeteNo, it's proper = invariant mass even here. If the region of space is fixed, then the total momentum is zero, so from E2 = (cp)2 + (mc2)2 we can infer that m = E/c2.You'd make this so much easier if you would just shorthand this to having gamma next to Mc^2.
You know, relativistic forumla that come in the form E= \gamma Mc^2. No need for the messy definitions concerning mass.
Quote from: Mr. Scientist on 01/10/2009 02:36:44You know, relativistic forumla that come in the form E= \gamma Mc^2. No need for the messy definitions concerning mass. But I can't understand what exactly you mean. I proved that a system which is not moving in a specific frame of reference and which has energy, also has invariant mass. Relativistic mass is a different concept, that is, is just energy divided by c2, *always*.
Quote from: lightarrow on 01/10/2009 13:11:21Quote from: Mr. Scientist on 01/10/2009 02:36:44You know, relativistic forumla that come in the form E= \gamma Mc^2. No need for the messy definitions concerning mass. But I can't understand what exactly you mean. I proved that a system which is not moving in a specific frame of reference and which has energy, also has invariant mass. Relativistic mass is a different concept, that is, is just energy divided by c2, *always*. No, its not. reltivistic mass invokes M= \gamma m. This means that it has zero mass. A reativistic mass is never simply E/c^2=M.
Look into this: http://en.wikipedia.org/wiki/Mass_in_special_relativityRelativistic mass is an outdated concept.
You can either listen or not. But I can assure you one last time; relativistic mass is not correct under E=Mc^2, or any algebraic manipulation.
Quote from: Mr. Scientist on 01/10/2009 20:49:33You can either listen or not. But I can assure you one last time; relativistic mass is not correct under E=Mc^2, or any algebraic manipulation.Ok. So, can you please give me the definition of relativistic mass of a photon?
Quote from: lightarrow on 02/10/2009 13:29:00Quote from: Mr. Scientist on 01/10/2009 20:49:33You can either listen or not. But I can assure you one last time; relativistic mass is not correct under E=Mc^2, or any algebraic manipulation.Ok. So, can you please give me the definition of relativistic mass of a photon?The mass of a photon in relativity is zero but has itself, a non-zero energy:E=M^2c^4+p^2c^2
Plugging in the appropriate values, one finally assumes that for Mc^2, we actually have:E= \gamma Mc^2
Quote from: Mr. Scientist on 03/10/2009 01:43:11Quote from: lightarrow on 02/10/2009 13:29:00Quote from: Mr. Scientist on 01/10/2009 20:49:33You can either listen or not. But I can assure you one last time; relativistic mass is not correct under E=Mc^2, or any algebraic manipulation.Ok. So, can you please give me the definition of relativistic mass of a photon?The mass of a photon in relativity is zero but has itself, a non-zero energy:E=M^2c^4+p^2c^2 This is correct.QuotePlugging in the appropriate values, one finally assumes that for Mc^2, we actually have:E= \gamma Mc^2This is *not* correct for photons. What does infinite multiplied by zero means?
It is correct for photons, because M is the rest mass, and \gamma makes the value of matter to zero. That is why the rest energy of a photon is given by: E=\gamma Mc^2. You can learn this stuff quite independantly and easily on web sites spralled all over the place.
Quote from: Mr. Scientist on 03/10/2009 17:17:53It is correct for photons, because M is the rest mass, and \gamma makes the value of matter to zero. That is why the rest energy of a photon is given by: E=\gamma Mc^2. You can learn this stuff quite independantly and easily on web sites spralled all over the place.And how much is gamma for a photon?You shouldn't base your knowledge on internet sites only, you should also go to school, at least...
Talking about ''infinities'' did nothing for the conversation. And I dont need more school. I've had a shitload of it so far; i have education and certificates in physics too.
Quote from: Mr. Scientist on 04/10/2009 14:10:50Talking about ''infinities'' did nothing for the conversation. And I dont need more school. I've had a shitload of it so far; i have education and certificates in physics too.Well, so you should know that m*gamma is meaningless for a photon.At high school they call it "Indeterminate form":http://en.wikipedia.org/wiki/Indeterminate_form