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does it?
Since photons are never at rest, the rest mass of a photon probably isn't what was being asked about.
A photon has no rest mass, which implies that the Minkowskian norm of its energy-momentum vector is zero. However, it does not follow that the components of its energy-momentum vector are all zero, because the Minkowskian norm is not positive-definite. For a photon we have E2 - px2 - py2 - pz2 = 0 (where E = hn), so the energy-momentum vectors of two photons, one moving in the positive x direction and the other moving in the negative x direction, are of the form [E, E, 0, 0] and [E, -E, 0, 0] respectively. The Minkowski norms of each of these vectors individually are zero, but the sum of these two vectors is [2E, 0, 0, 0], which has a Minkowski norm of 2E. This shows that the rest mass of two identical photons moving in opposite directions is m0 = 2E = 2hn, even though the individual photons have no rest mass.
I have read the article quoted by Lightarrow and my head is in a whorl, I am not going in future even to read any questions concerning mass, energy etc.
The principle of equivalence comes from the equation E^2 = m^2c^4 + p^2c^2 In which m is mass, p is defined as momentum, and c is an absolute velocity: It is generally accepted that electromagnetic phenomena have “momentum, but no mass”, the proof being E2 = 02c4 + p2c2therefore √E2 = √( p2c2)and so E = pc (1.0.1)and similarly “rest” mass has no momentum, therefore E2 = m2c4 + 02c2 E2 = m2c4 E = mc2 (1.0.2)
However, the definition of p, momentum, is mass x velocity,
albeit in this case the velocity has the absolute value “c”.So in SI units pc = Kg.(m.sec-1)(m.sec-1), and mc2 = (Kg.m2.sec-2) (1.0.3) These are dimensionally identical, so the solutions (1.0.1) and (1.0.2) do not seem to be legitimate, although they are claimed by experiment to be “proved”. If this is the case, and E = pc and E = mc2 are valid then either (pc)2 + (mc2) = E2 and-a-bit, or if equation (1.0) is to be upheld, the possibility has to be considered that m has to be non-zero, and c has to be variable.
Slightly tangential, but interestingly mass still remains the one SI unit that cannot yet be defined in terms of something else: 'mass' is DEFINED by the kilogram sample of platinum alloy kept in a box in Paris !
No-one really knows, at a fundamental level, what mass 'is.' You may as well ask what a quark is made of , or what a magnetic field is made of, these questions have no answers in current physics. Think of it like this: as a particle (say an electron) speeds up, it slowly gains mass according to GR.
just exactly how is this 'mass' added? - little tiny bits of electron magicking themselves out of nothing and sticking to the surface of the moving electron?!! Very unlikely. 'mass' at the particle level becomes a purely mathematical abstraction - don't let anyone kid you otherwise :-) Therefore for all intents and purposes a photon DOES have mass, purely by virtue of it's motion, i.e. its energy.
Last time I checked mass and energy were equivalent; doesn't that mean that light, which clearly has energy, must have mass?