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  4. Field objects moving at the speed of light, maybe photon or neutrino?
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Field objects moving at the speed of light, maybe photon or neutrino?

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Offline compuAI (OP)

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Re: Field objects moving at the speed of light, maybe photon or neutrino?
« Reply #20 on: 13/10/2022 18:50:31 »
Quote from: paul cotter on 13/10/2022 15:53:55
∇ΧE=-μ ∂H/∂t
Mathematically it is correct. With some remarks:
1. At the "pure field" level, where fields are not produced forcefully by motions of macroscopic objects, ∂H/∂t is the consequence, ∇ΧE is the cause, not vice versa, according to the principles of locality and causality.
2. H (or B) is not fundamental field, but vector potential A. We can also find some law how changes ∇·A with the time, as we did with curl (H or B).
« Last Edit: 13/10/2022 19:02:09 by compuAI »
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Offline paul cotter

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Re: Field objects moving at the speed of light, maybe photon or neutrino?
« Reply #21 on: 13/10/2022 19:34:14 »
∇•A=-εμ∂V/∂t
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Offline compuAI (OP)

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Re: Field objects moving at the speed of light, maybe photon or neutrino?
« Reply #22 on: 14/10/2022 07:17:30 »
Quote from: paul cotter on 13/10/2022 19:34:14
∇•A=-εμ∂V/∂t
Exactly. At least in our Universe, as linear approximation.
In another hypothetical world can exist longitudinal waves mixed with transverse, instead of scalar potential:
H = 1/μ0 · rot A
d = 1/μ0 · div A
∂E/∂t = 1/ε0 · rot H - 1/ε0 · grad d
∂H/∂t = - 1/μ0 · rot E
∂d/∂t = - 1/μ0 · div E
energy density u = ε0/2 · E2 + μ0/2 · H2 + μ0/2 · d2
enerdy flux S = [E X H] + (E · d)
∂u/∂t = - div S

Although I meant other thing:
∂/∂t (1/μ0 · div A) = 1/μ0 · div (∂A/∂t) = - 1/μ0 · div E - 1/μ0 · div grad a
« Last Edit: 14/10/2022 16:33:31 by compuAI »
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