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Yes.
But joules being equal to the mass in kg multiplied by the square of the speed of light in metres covered in a second. Is there any mathematical demonstration that would satisfy a power engineer?
Quote from: Petrochemicals on 04/12/2023 21:12:27But joules being equal to the mass in kg multiplied by the square of the speed of light in metres covered in a second. Is there any mathematical demonstration that would satisfy a power engineer?Yes.Ya know you google this question and get the answer in hardly any time at all.
As for a proof that would satisfy a power engineer, it is in the first lecture of Nuclear Reactors 101. But that was nearly 60 years ago so I won't attempt to recall it now.
If you wouldn't mind, the Wikipedia examples are not entirely convincing.
Quote from: alancalverd on 04/12/2023 22:59:09As for a proof that would satisfy a power engineer, it is in the first lecture of Nuclear Reactors 101. But that was nearly 60 years ago so I won't attempt to recall it now. They do the practical in the lecture, how exiting.
Then you asked for theoretical proof,
Is there any sort of practical example