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My question for the pundits is, how much information is there in a scientific theory? Can it be compressed, transmitted and received, this information, which would be a necessary thing for it to "be" information . . . ?
....... after a bit of thought, the idea that a scientific theory can be reduced to a set of equations is perhaps an idea of simplification, but I don't know that that can be true: without some contextual language a page of equations can't convey that much. Suppose Einstein had *simply* written his famous formula (a system of equations!) for gravity in one line and published it.
As far as I am concerned, "information" is only meaningful if it applies to a specified system, whilst an equation is not specific. Same difference between a definition of momentum = mv and the actual momentum of a moving car - only the latter is information. So "theoretical information" either means a test input (as distinct from real data) to an information processing system, or nothing at all.
Can anyone name any other equations whose form appears to be independent of the physical context (?)
What this particular scientific lemma or equation ( s = ut + ?at2 ) is telling us is that, provided we have constant acceleration.... and ignore a bunch of other things (air resistance and most of real life).
you can't set aside the mathematical fact that distance covered is the integral of the velocity vector over time.
This equation is a statement of absolute fact, not an approximation or idealisation.
My point is that any actual numbers you use for u, a and t constitute information, but the equation doesn't
Suppose you originally thought s = ut ; s = 0 ; s = (1/2)at2 or s = ut + (1/2)at2 would be the right relationship, with equal probability for each of these. So you had 4 possibilities with a probability 1/4 for each. Then you're given the equation s = ut + (1/2)at2 So I(E) = - Log2 (1/4) = Log2 (4) = 2. The Shannon information content is 2 (they tend to use Log to the base 2 and then declare the value of I(E) to be in "bits", 2 bits of information have been learnt). Suppose we already knew that s = ut + (1/2)at2, So the probability for this being the relationship is 1, Then we are given the equation s = ut + (1/2)at2, So I(E) = Log2 (1) = 0 and we gained 0 bits of information.
So if there's a chink in the wall here, we see a duality in the wave-particle model(s) because of a constraint or restriction (or maybe it's really an obstruction of an embedding of ... something).
Common misconception. There is no "duality" inherent in the phenomenon, but we need two distinct models to describe different aspects of it.
, we know how to make an interference pattern appear, and how to make it disappear, with measurements.
Absurd, if commonplace, statement!Time moves in one direction. If you observe an interference pattern, it must have been formed somewhere in space and time before you observed it. How did the wave know it was going to be observed?
If you modify the physics of one slit, i.e. "observe" particles passing through it, you obviously can't expect to see the same resulting pattern.
When you say "wavelengths are known" you actually mean that wavelengths have been assigned to the wave model that predicts the spatial distribution downstream. But when you detect the photons/electrons/whatever downstream of the slits, they turn up one-by-one with the same energy as the source, i.e. the interaction with a detector follows a particle model.
The problem with "duality" is that it presupposes classical continuum mechanics to apply to all phenomena, then invokes magic to explain what actually happens. Far better to start with the quantum observation and state that we use two distinct mathematical models to describe propagation and detection.