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New Theories / Re: What makes Riemann's Hypothesis Hard to Prove?
« on: Today at 03:27:58 »For every nontrivial zero of Zeta function, ζ(s) =0,
Re(Y(s)) = - ~ (negative infinity)
Im(Y(s) = undefined (due to switching between two different, discontinuous values)
The plot of Y function suggests that those conditions can only be satisfied where Re(s) = 1/2, as Riemann predicted.
The trivial zeros of Riemann's Zeta function are entirely defined by the sine function in the functional equation. Zeros on non-negative integers are canceled by the simple poles of the Gamma function.