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Quote from: Geezer on 08/11/2011 21:15:08Quote from: johan_M on 08/11/2011 20:43:01QuoteMax power in = 6.81 kWPower out = 3.0kwEfficiency = 44.1% I have'nt followed the whole thread, it's a bit convoluted. Please explain this efficiency part?Which part of it do you not understand?Is it possible that the missing link is "efficiency = power out/power in" ?
Quote from: johan_M on 08/11/2011 20:43:01QuoteMax power in = 6.81 kWPower out = 3.0kwEfficiency = 44.1% I have'nt followed the whole thread, it's a bit convoluted. Please explain this efficiency part?Which part of it do you not understand?
QuoteMax power in = 6.81 kWPower out = 3.0kwEfficiency = 44.1% I have'nt followed the whole thread, it's a bit convoluted. Please explain this efficiency part?
Max power in = 6.81 kWPower out = 3.0kwEfficiency = 44.1%
What do you mean by displacement efficiency? Where does the lost energy go?can you give a simple example?
Quote from: Mootle on 06/11/2011 18:50:33Quote from: Geezer on 06/11/2011 01:29:43Yes, I did. As you didn't specify its displacement, I assumed it was twice the displacement of the two smaller ones. If you knew it was possible to generate the power output with half the total displacement, I would have thought you would have made that clear. My calculation was simply the energy output over the maximum energy input based on the displacements and the tide.I thought I did (3rd time lucky):'Therefore, there is scope to engineer an arrangement such that both Storage Vessels operate from one Pontoon, which carries a number of operational and financial advantages.'If you show your workings I can review further. The problem I have is that even when you are presented with irrefutable evidence you still don't concede points so I have no intention of trying to second guess what you have calculated.OK - here you go.QuoteBased on a 25:1 gearing ratio each Pontoon volume would be ca. 7,500m3Tidal range is assumed as 2m.Total displacement 2 x 7500 = 15,000m3, or 15,000,000kg (ignoring the salt in the water)Therefore, max force is 147.2MNMax work in 24 hours is 147.2 x 4 = 588.6MJ = 588,600kJMax work per second is 588,600/86,400 = 6.81kJMax power in = 6.81 kWPower out = 3.0kwEfficiency = 44.1%(Or are you assuming one of the pontoons is going to spring a leak and sink?)
Quote from: Geezer on 06/11/2011 01:29:43Yes, I did. As you didn't specify its displacement, I assumed it was twice the displacement of the two smaller ones. If you knew it was possible to generate the power output with half the total displacement, I would have thought you would have made that clear. My calculation was simply the energy output over the maximum energy input based on the displacements and the tide.I thought I did (3rd time lucky):'Therefore, there is scope to engineer an arrangement such that both Storage Vessels operate from one Pontoon, which carries a number of operational and financial advantages.'If you show your workings I can review further. The problem I have is that even when you are presented with irrefutable evidence you still don't concede points so I have no intention of trying to second guess what you have calculated.
Yes, I did. As you didn't specify its displacement, I assumed it was twice the displacement of the two smaller ones. If you knew it was possible to generate the power output with half the total displacement, I would have thought you would have made that clear. My calculation was simply the energy output over the maximum energy input based on the displacements and the tide.
Based on a 25:1 gearing ratio each Pontoon volume would be ca. 7,500m3Tidal range is assumed as 2m.
Now I challenge you to answer the question in a straightforward manner or leave.How will you make this rig cheap enough that the revenue will, at least, service the loan for building it?
Quote from: Geezer on 06/11/2011 19:47:53Quote from: Mootle on 06/11/2011 18:50:33Quote from: Geezer on 06/11/2011 01:29:43Yes, I did. As you didn't specify its displacement, I assumed it was twice the displacement of the two smaller ones. If you knew it was possible to generate the power output with half the total displacement, I would have thought you would have made that clear. My calculation was simply the energy output over the maximum energy input based on the displacements and the tide.I thought I did (3rd time lucky):'Therefore, there is scope to engineer an arrangement such that both Storage Vessels operate from one Pontoon, which carries a number of operational and financial advantages.'If you show your workings I can review further. The problem I have is that even when you are presented with irrefutable evidence you still don't concede points so I have no intention of trying to second guess what you have calculated.OK - here you go.QuoteBased on a 25:1 gearing ratio each Pontoon volume would be ca. 7,500m3Tidal range is assumed as 2m.Total displacement 2 x 7500 = 15,000m3, or 15,000,000kg (ignoring the salt in the water)Therefore, max force is 147.2MNMax work in 24 hours is 147.2 x 4 = 588.6MJ = 588,600kJMax work per second is 588,600/86,400 = 6.81kJMax power in = 6.81 kWPower out = 3.0kwEfficiency = 44.1%(Or are you assuming one of the pontoons is going to spring a leak and sink?)Ok, thanks for this. The idea that I was trying to get across was that (2) buoyancy engines working on this cycle would be able to share a single Pontoon owing to the sequencing of the loading of the Pontoon. This wouldn't be the optimum efficiency in terms of revenue generation for the system but it might be useful to suit certain demand profiles. The combined Pontoon would need to have an increased volume over (1) 7,500m3, maybe 10,000 - 12,000m3 would be possible with the main factor being distribution of stresses vs VfM. This would be subject to a detailed scaled design but since I haven't got the luxury of a design team behind me I will stick to the unitary system for now. There are too many unknown variables at this point but I would anticipate that compared with other renewable energy systems the seasonal efficiency of a working system will be quite impressive.
Quote from: Bored chemist on 06/11/2011 20:58:43Now I challenge you to answer the question in a straightforward manner or leave.How will you make this rig cheap enough that the revenue will, at least, service the loan for building it?As I've said (more than once,) I'm not ready to properly present and fully answer your question at this particular moment. Once I've developed the Scaled and Construction Animation sufficiently I will return.
Quote from: Mootle on 11/11/2011 20:38:42Quote from: Bored chemist on 06/11/2011 20:58:43Now I challenge you to answer the question in a straightforward manner or leave.How will you make this rig cheap enough that the revenue will, at least, service the loan for building it?As I've said (more than once,) I'm not ready to properly present and fully answer your question at this particular moment. Once I've developed the Scaled and Construction Animation sufficiently I will return.An animation will not make it cheaper,You could answer the question without that trouble.You have mentioned a few things you will not do, but not what you will do instead.I think you have absolutely no idea how you are going to make this idea economically viable.
Yes, I figured it was something like that.BTW, I think you really need to worry about the 25:1 pulley speed up ratio. I'm pretty sure there will be so much friction that that pontoon will not be able to exert sufficient force on the storage vessel to move it.In practice, even with a lot of anti-friction bearings (and super-flexible cable) I think you will discover there is no way around it. A small model of that part of the system might be a good investment. An even cheaper method would be to get a 25:1 gear setup and try to run it in speed-up mode. If you have really good bearings, the output might actually rotate 25 times faster than the input under no load (although it's also possible the gears will strip before it turns at all), but as soon as you put any load on it, it will very likely wedge.
Quote from: Geezer on 12/11/2011 01:50:03Yes, I figured it was something like that.BTW, I think you really need to worry about the 25:1 pulley speed up ratio. I'm pretty sure there will be so much friction that that pontoon will not be able to exert sufficient force on the storage vessel to move it.In practice, even with a lot of anti-friction bearings (and super-flexible cable) I think you will discover there is no way around it. A small model of that part of the system might be a good investment. An even cheaper method would be to get a 25:1 gear setup and try to run it in speed-up mode. If you have really good bearings, the output might actually rotate 25 times faster than the input under no load (although it's also possible the gears will strip before it turns at all), but as soon as you put any load on it, it will very likely wedge. Pulley's are still my preferred option as I haven't worked out how to make a gearbox solution work for this application but I'm still mulling that one over. I've recognised the need to maintain load and this would be achieved by not allowing the Storage Vessel to break the surface following the Ascent phase, as stated on the audio of the Schematic animation. However, I acknowledge this isn't what's shown so apologies for the misunderstanding.I agree that a lower ratio would be easier from an engineering perspective. The 25:1 ratio is a target driven by revenue optimisation. A pilot scheme is the next step but before I would look for scheme funding I need to be sure that there is a business case. If I can demonstrate a business case I would look to enter into consultation with specialists for a number of elements of the design where I'm not a practitioner. The pulley system would be one such area.
http://en.wikipedia.org/wiki/Block_and_tackle#Friction
Quote from: Mootle on 13/11/2011 11:19:43Quote from: Geezer on 12/11/2011 01:50:03Yes, I figured it was something like that.BTW, I think you really need to worry about the 25:1 pulley speed up ratio. I'm pretty sure there will be so much friction that that pontoon will not be able to exert sufficient force on the storage vessel to move it.In practice, even with a lot of anti-friction bearings (and super-flexible cable) I think you will discover there is no way around it. A small model of that part of the system might be a good investment. An even cheaper method would be to get a 25:1 gear setup and try to run it in speed-up mode. If you have really good bearings, the output might actually rotate 25 times faster than the input under no load (although it's also possible the gears will strip before it turns at all), but as soon as you put any load on it, it will very likely wedge. Pulley's are still my preferred option as I haven't worked out how to make a gearbox solution work for this application but I'm still mulling that one over. I've recognised the need to maintain load and this would be achieved by not allowing the Storage Vessel to break the surface following the Ascent phase, as stated on the audio of the Schematic animation. However, I acknowledge this isn't what's shown so apologies for the misunderstanding.I agree that a lower ratio would be easier from an engineering perspective. The 25:1 ratio is a target driven by revenue optimisation. A pilot scheme is the next step but before I would look for scheme funding I need to be sure that there is a business case. If I can demonstrate a business case I would look to enter into consultation with specialists for a number of elements of the design where I'm not a practitioner. The pulley system would be one such area.Er, well, you might want to take a squint at this before you go much further, particularly the term that shows that the efficiency is related to the inverse of a value raised to the power of the number of sheaves. 25:1 is going to need a lot of sheaves. http://en.wikipedia.org/wiki/Block_and_tackle#Friction
Do you think the previous pulley systems were designed to be inefficient?
To be honest, I'm not going to be convinced by a scale model.I have no doubt the system could be built (on a small or large scale).I just don't think it will ever be built cheaply enough to be any use
He has to prove he CAN generate power first, by overcoming all the engineering problems. It must be simple and efficient. IF he achieve this ( a big if ), then he might raise money to build another small model off shore. Then he could scale the costs and prove that his system has a chance. If he is convinced, then he has to get working on it.
QuoteTo be honest, I'm not going to be convinced by a scale model.I have no doubt the system could be built (on a small or large scale).I just don't think it will ever be built cheaply enough to be any use He has to prove he CAN generate power first, by overcoming all the engineering problems. It must be simple and efficient. IF he achieve this ( a big if ), then he might raise money to build another small model off shore. Then he could scale the costs and prove that his system has a chance. If he is convinced, then he has to get working on it.