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Suppose we know the vapor pressure of a liquid (by itself in a sealed container) at a specific temperature, and likewise the vapor pressure of another liquid, when likewise isolated, at the same temperature. Suppose further that the two liquids are miscible at that temperature without undergoing a chemical change. Is there any simple formula for calculating the overall vapor pressure of a mixture of the two liquids at that temperature?
Whew... haven't done that for a few years.But, I think you simply multiply the vapor pressure (or partial pressure?) times the percent (volume) of each liquid, and add up the results.