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The N-field

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guest39538

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Re: The N-field
« Reply #80 on: 04/11/2017 15:14:38 »
Quote from: Bored chemist on 04/11/2017 15:09:49
Quote from: Thebox on 04/11/2017 14:54:52
https://en.wikipedia.org/wiki/Coulomb%27s_law

Do you accept this to be factual science and true?

Yes.

We are both in agreement , I also accept this to be factual science. 

Now a question for you , can this law  also be applied to magnetic field polarity ?

Can we say:
The magnitude of the electromagnetic force of attraction between two point charges is directly proportional to the product of the magnitudes of polarities and inversely proportional to the square of the distance between them. The force is along the straight line joining them?
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Offline Bored chemist

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Re: The N-field
« Reply #81 on: 04/11/2017 15:22:16 »
Quote from: Thebox on 04/11/2017 15:14:38
Can we say:
The magnitude of the electromagnetic force of attraction between two point charges is directly proportional to the product of the magnitudes of polarities and inversely proportional to the square of the distance between them. The force is along the straight line joining them?

No, we can't, because polarity doesn't have a magnitude.

That's why you need to start by learning some science.
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guest39538

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Re: The N-field
« Reply #82 on: 04/11/2017 15:28:05 »
Quote from: Bored chemist on 04/11/2017 15:22:16
Quote from: Thebox on 04/11/2017 15:14:38
Can we say:
The magnitude of the electromagnetic force of attraction between two point charges is directly proportional to the product of the magnitudes of polarities and inversely proportional to the square of the distance between them. The force is along the straight line joining them?

No, we can't, because polarity doesn't have a magnitude.

That's why you need to start by learning some science.

You are now my teacher , hopefully I and you are going to develop my theory and make it truthful in every way by me learning what I need to learn to make my theory.

Can you start by please explaining why polarity does not have a magnitude? 

I thought/think that if we start with a single atom it has a polarity of 1e and 1p

If we then had two atoms we have a polarity of 2e and 2p


so 1 atom = 1 neg and 1 pos

two atoms = 2 neg and 2 pos

How is two of something not a greater magnitude?

added- The ''magnitude'' of polarity is directly proportional to the mass?

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Offline Bored chemist

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Re: The N-field
« Reply #83 on: 04/11/2017 15:56:41 »
You are using the word "polarity" for something which is similar to "charge".
Do you man charge?
If so, why not say so?

The polarity of a charge is a binary variable; positive or negative. It has no magnitude.
It's like left handed and right handed. It barely makes sense to ask how left handed someone is; they are or they are not.

If you started out by learning some science you would understand things like this.
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guest39538

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Re: The N-field
« Reply #84 on: 04/11/2017 16:01:33 »
Quote from: Bored chemist on 04/11/2017 15:56:41
You are using the word "polarity" for something which is similar to "charge".
Do you man charge?
If so, why not say so?

The polarity of a charge is a binary variable; positive or negative. It has no magnitude.
It's like left handed and right handed. It barely makes sense to ask how left handed someone is; they are or they are not.

If you started out by learning some science you would understand things like this.
No I mean polarity. 

But if it helps lets stick to charge a minute and the polarity of charge.

q- and q+

So you are saying if had a ''group'' of q- and q+    , that the magnitude of polarity does not change?   


q+q+q+q+
q-q-q-q-

Meaning it does not matter how big the object is the polarity will always be the same ?
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Offline Bored chemist

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Re: The N-field
« Reply #85 on: 04/11/2017 16:07:29 »
If you have a hydrogen atom with a single proton and a single electron ten overall, it has no charge.
Also because the electron density is spherically arranged round the proton it has no polarisation.

You say " that the magnitude of polarity does not change? "   when I have already explained that, like handedness, polarity does not have  a magnitude.
What's the point of this if you don't accept reality?

It's like asking if 123 is a more odd number than 12209?
Or is 2 more even than 64?
The odd- or even-ness doesn't have magnitude.
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guest39538

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Re: The N-field
« Reply #86 on: 04/11/2017 16:10:10 »
Quote from: Bored chemist on 04/11/2017 16:07:29

What's the point of this if you don't accept reality?

I have not said I do not accept your answer, I am just questioning your answer deeper.

Can we say that the + and - polarity is directly proportional to the mass?

charge is not attracted or repulsed by charge, the polarities are what do the attracted and repulsing?
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Offline Bored chemist

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Re: The N-field
« Reply #87 on: 04/11/2017 16:13:54 »
Quote from: Thebox on 04/11/2017 16:10:10
Can we say that the + and - polarity is directly proportional to the mass?
No, we can't.
For two reasons.
The first is that polarity isn't a "quantity"
Things are not going to progress until you get that into your head.

The other point is that the charge isn't proportional to mass either. That's been explained at length before.
The simplest way to demonstrate it is that a positron has the same charge as a proton, but is about 2000 limes less massive.
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guest39538

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Re: The N-field
« Reply #88 on: 04/11/2017 16:19:16 »
Quote from: Bored chemist on 04/11/2017 16:13:54
The first is that polarity isn't a "quantity"
That would be untrue, there is two polarities, two is a quantity.

So let me get this right ,

You are saying that the polarity of m1 is directly proportional to m2, a quantity of 2 polarities in each?
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Offline Bored chemist

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Re: The N-field
« Reply #89 on: 04/11/2017 16:27:19 »
OK, lets start out by clarifying what sort of variable  polarity is.
There are an infinite number of integers.
Each one is either odd or even.
That property- oddness or evenness- is  called parity.
All integers have a parity- it's either odd or even.
So, for example, the parity of 10 is "even"
But "even" is not a number, it's a description.
You can't multiply it by something.

And all numbers have just one parity.
A collection of numbers doesn't have a defined parity.
(is 3,4,5 even or odd?- it's impossible to say).

Polarity is like parity. It is not a number, it's a description.

OK.
Lets move on to charge- all objects have a charge. That charge may be zero, it may be big  or small .
Whether the charge is big or small, it also has a polarity- either positive or negative.

So it isn't the object that has a polarity, it is the charge on that object which (unless it is zero) has a polarity.

No object can have more than 1 charge (overall) so no object can have more than 1 polarity.
« Last Edit: 04/11/2017 16:30:27 by Bored chemist »
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guest39538

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Re: The N-field
« Reply #90 on: 04/11/2017 16:35:48 »
Quote from: Bored chemist on 04/11/2017 16:27:19
OK, lets start out by clarifying what sort of variable  polarity is
Thank you , your post is certainly something new to me, parity is something I am not familiar with and will have to look up to gain more knowledge on it.

However you said that polarity does not have a magnitude but then say it is a variable which seems contradictory and is confusing to me. Only quantities can be variables but admittedly I do not understand parity in which you are probably explaining a difference , however it is too soon for the information to have ''sunk'' in yet.

Quote
There are an infinite number of integers.

What do you mean by integers?
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Offline Bored chemist

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Re: The N-field
« Reply #91 on: 04/11/2017 17:26:31 »
Integers are the "whole numbers" 0,1,2,and so on, and also the negative whole numbers.

It's a variable that has one (and only one) of two (and there are only two) values.
The polarity of a charge is either positive or negative.
Those are properties, not numbers.
So you can't add them or do other arithmetic with them.
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Offline Kryptid

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Re: The N-field
« Reply #92 on: 04/11/2017 21:26:02 »
Quote from: Bored chemist on 04/11/2017 15:22:16
No, we can't, because polarity doesn't have a magnitude.

I wouldn't be too sure about that. Some molecules are more polar than others and can have those polarities measured as a dipole moment.

Not that it makes Thebox's hypothesis correct, though.
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Re: The N-field
« Reply #93 on: 04/11/2017 21:49:16 »
Quote from: Kryptid on 04/11/2017 21:26:02
Quote from: Bored chemist on 04/11/2017 15:22:16
No, we can't, because polarity doesn't have a magnitude.

I wouldn't be too sure about that. Some molecules are more polar than others and can have those polarities measured as a dipole moment.

Not that it makes Thebox's hypothesis correct, though.
I know.
But polarity is not the same as a dipole moment.
It's the difference between polarity of a material- like water or the polarity of a thing, like an electron.
As it stands, Thebox is confused enough without adding that.
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guest39538

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Re: The N-field
« Reply #94 on: 05/11/2017 10:48:17 »
Quote from: Bored chemist on 04/11/2017 21:49:16
Quote from: Kryptid on 04/11/2017 21:26:02
Quote from: Bored chemist on 04/11/2017 15:22:16
No, we can't, because polarity doesn't have a magnitude.

I wouldn't be too sure about that. Some molecules are more polar than others and can have those polarities measured as a dipole moment.

Not that it makes Thebox's hypothesis correct, though.
I know.
But polarity is not the same as a dipole moment.
It's the difference between polarity of a material- like water or the polarity of a thing, like an electron.
As it stands, Thebox is confused enough without adding that.

Ok, to clarify this, you are saying no matter how big a mass is or how small a mass is , the polarities in both masses are equal and proportional and equal and proportional attracted and repulsed by polarity?
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Offline Bored chemist

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Re: The N-field
« Reply #95 on: 05/11/2017 13:15:17 »
Quote from: Thebox on 05/11/2017 10:48:17
Ok, to clarify this, you are saying no matter how big a mass is or how small a mass is , the polarities in both masses are equal and proportional and equal and proportional attracted and repulsed by polarity?
You think that's a clarification?

Anyway. No.
Nobody said anything like that. You made it up.
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guest39538

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Re: The N-field
« Reply #96 on: 05/11/2017 15:16:38 »
Quote from: Bored chemist on 05/11/2017 13:15:17
Quote from: Thebox on 05/11/2017 10:48:17
Ok, to clarify this, you are saying no matter how big a mass is or how small a mass is , the polarities in both masses are equal and proportional and equal and proportional attracted and repulsed by polarity?
You think that's a clarification?

Anyway. No.
Nobody said anything like that. You made it up.
No, thats more or less what you are telling me.
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Offline Bored chemist

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Re: The N-field
« Reply #97 on: 05/11/2017 16:48:07 »
Quote from: Thebox on 05/11/2017 15:16:38
No, thats more or less what you are telling me.
Why are you pretending that you know what I'm saying, better than I do?
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guest39538

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Re: The N-field
« Reply #98 on: 05/11/2017 16:58:47 »
Quote from: Bored chemist on 05/11/2017 16:48:07
Quote from: Thebox on 05/11/2017 15:16:38
No, thats more or less what you are telling me.
Why are you pretending that you know what I'm saying, better than I do?

Interpretation is not pretending .
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Re: The N-field
« Reply #99 on: 05/11/2017 17:32:13 »
Quote from: Thebox on 05/11/2017 16:58:47
Interpretation is not pretending .

Bored Chemist isn't the one proposing that polarity has anything to do with how one mass attracts another.
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