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The spoon,See the sketch carefully.I have just changed the length of long tube .now it is 4 meter and it is mounted in middle with the Left arm of seesaw.Now calculate input and output.You please also calculate output from counterweight as I had forgotten to mention about it.Everything is same but I have just increased the length of tube so input will be same like previous design.But output?

I have already proved it mathematically.

Mgh= 10*10*2=200 joule at the time of tilting.Mgh=10*10*2=200 joule at the time of reversing.So total output is 400 joule but input will be almost free due to equilibrium position of seesaw.

The spoon,I have already proved it mathematically.you are not convinced that's why I asked you.otherwise you don't think that I don't know.everone know what will be input and output?Out put will be always greater than input.

The spoon,the minimal input is only 20 Joule if I take friction loss 10% but output is 200 Joule from a 10 kg falling ball from 2 meter height.so when ball will hit with upper part of tube at the time of tilting then kinetic energy is 200 joule.now minus the input 20 Joule from 200 JouleSo overall output is 180 Joule.But you are forgetting that the seesaw is getting back it's initial position without any extra energy so ball is again falling from 2 meter height then output is 200 Joule again.Why are you not considering the falling of ball at the time of reversing.

If you have viewed the sketch carefully.hope you will understand it.

your all doubts will be cleared immediately.

Kryptid,The part is ,to mounted generator on each side of tube.

it will not work, because it can not work.If you don't understand that fact then it is you who needs to do the calculations.