[mxplxxx (OP)]

All systems in Reality and  all components of systems likely have purposes. The purpose of a photon is to provide current systems with information about the past. One of the ways it may do this is via the magnetic field which seems to surround most systems. A photon intersecting with a magnetic field may induce a vibration in a "line" in the magnetic field. The vibration will have the same frequency and wavelength as the photon. The vibration then travels via the "line" to the "north pole" (i.e top) of the system and thence to its centre (which is often a black hole) via child/parent system relationships. At this point the original system becomes aware of a past event and may react in some way if the event is of consequence to it.

The reaction will occur firstly via the subsystems of the inner/central system. Asynchronously i.e. multiple systems will react at once. The reaction may stop at any point. It may also "bounce" at any stage in the process meaning an event may start travelling up a system's HFSM rather than down, giving rise to a process that can occur indefinitely (like life!). Bounced events are likely to travel to the south pole of the system (i.e bottom) to the "react" events meaning magnetic field lines operate in two directions.

If at any point in this process the top level of the inner system changes state, the reaction may continue (asynchronously) via the subsystems of the outer system (i.e. via parent/child relationships). Photons and w/z bosons will likely be involved in this process with Higgs bosons being exchanged where energy changes are involved.

Eventually the reaction will stop, possibly at the outer limits of the system with, if a change of state has occurred, a system photon being "created" for processing by the original system's parent.

Thus, it would seem, the purpose of magnetic fields is to transport event notifications between systems.

It is likely that changes of momentum will occur in the systems involved in the reaction process. In the end though, as per the conservation of momentum law, no overall change in the momentum of the original system can occur.

Chances are the process is geared so that the photon will react with only one "line" of the magnetic field and not be destroyed by the process. Thus, a photon may be eternal in nature. 

This process is very similar to the computer science process whereby events are handled in computer Apps. A react event in reality is equivalent to a function Call in an App, and a bounce event in Reality is equivalent to  "raised" event in an App.

[hamdani yusuf]

The vibration then travels via the "line" to the "pole" of the system and thence to its centre (which is often a black hole) via child/parent system relationships  at which point the original system becomes aware of a past event and may react in some way if the event is of consequence to it.

How often do you find black holes in the center of a system?

[mxplxxx (OP)]

The vibration then travels via the "line" to the "pole" of the system and thence to its centre (which is often a black hole) via child/parent system relationships  at which point the original system becomes aware of a past event and may react in some way if the event is of consequence to it.

How often do you find black holes in the center of a system?

https://science.nasa.gov/astrophysics/focus-areas/black-holes

[Bored chemist]

Also, the number of cases  COVID-19 seems to parallel the number of 5G installations in major cities.

It probably parallels the number of tins of dog food purchased too- for the same reason.

.

Nowhere is it mentioned that 5G signals are transmitted by Ultra-Short Lasers (lots of coherent photons packed together) of 30 Watts power.

Nowhere is it mentioned that 5G signals are transmitted by carrier pigeon.

That's because they don't use pigeons (or lasers) to broadcast the signal.
Lasers are used, but, of course, they are confined in fibre optic cables.

It's not helping anyone when you spread silly scare stories like this.
Don't do it again

[mxplxxx (OP)]

Recently I claimed that 5G was powered by lasers. This was dues to a headline by https://world-of-photonics.com/en/newsroom/photonics-industry-portal/technologies/ultrashort-pulse-lasers-5g/ that claimed that "Ultrashort pulse lasers pave the way for 5G". As far as  I can work out this is just a work in progress for the company and the headline is just plain wrong. 5G is powered by radio waves and relatively low frequency ones at that. Chances are it is a benign technology but the lack of testing by Telecoms is disturbing.

[Bored chemist]

the lack of testing by Telecoms is disturbing.

Just how is that going to work?
Do you think that the telecoms companies have cell biology labs or animal testing facilities?
Why would they have them?

And, if they did, would you be sure that the results were not influenced by the fact that the telecoms companies have a very clear interest in saying the tech is safe?
Wouldn't it be better if the testing was done independently?
(Perhaps paid for by a government which would pick up the bill for any health problems if the technology is not safe)

So, maybe the last thing we want is

testing by Telecoms

[mxplxxx (OP)]

the lack of testing by Telecoms is disturbing.

Just how is that going to work?
Do you think that the telecoms companies have cell biology labs or animal testing facilities?
Why would they have them?

And, if they did, would you be sure that the results were not influenced by the fact that the telecoms companies have a very clear interest in saying the tech is safe?
Wouldn't it be better if the testing was done independently?
(Perhaps paid for by a government which would pick up the bill for any health problems if the technology is not safe)

So, maybe the last thing we want is

testing by Telecoms

Fair enough.

[mxplxxx (OP)]

It is no wonder Photons cannot be directly measured. Like all bosons except possible Higgs particles they are not "observable". They are the equivalent of Events in computer science which also are not "observable". In computer science, we can raise an event and we can handle an event but we cannot otherwise access it.

It is likely that bosons are not observable because they do not "contain" energy (with the exception of HIggs particles). Energy seems to be required for distance, space and time to exist and may in fact be just different forms of these variables. In computer science, energy would be a polymorphic object.       

Higgs particles seem to straddle the space between a boson and a fermion, probably winking in and out of visibility depending on whether the associated fermion is being "observed" or not. No wonder they are hard to find:). Or maybe they are really fermions (see below).

In simulating a System, the Energy Property will be a Double. The Energy Property of a boson will equal Nothing.The Energy Property of a fermion will be a positive value > zero. It seems impossible for a boson to have a positive Energy Property since bosons would repel each other which is not allowed according to the Fermi Exclusion Principle. There are a number of other reasons why a boson cannot a positive Energy Property not the least being that a Photon travels at SOL and M=E/C2 and M would therefore be infinite for a Photon.

A boson is timeless,  "lives" in the present and is is the "shadow" of a past system at a particular time in that system's evolution. It has a frequency that represents amount of energy (E=hf) that the system has lost/gained in a past event. This frequency may trigger a distribution change in the energy of a current fermion system but the total amount of energy in the system must remain the same (as per conservation of energy). Energy changes in a system occur via collisions of fermions, not bosons.

On this basis, a Higgs particle will be a fermion, which makes a LOT more sense than the current theory.

In other words Spin defines a subset of a Boson or a Fermion. The primary differentiation between a boson and a fermion is that a boson does not "contain" energy and a fermion does "contain" energy.

So:

Class System
      Property Energy as Double = Nothing
      Property Frequency as Long Integer = Nothing
      Property Spin as Single = Nothing

Class Fermion
      Inherits System

      Property Overrides Spin as Single = s

 Class Higgs
     Inherits Fermion

    Property Overrides Energy as Double = E
    Property Overrides Frequency as Long Integer = Energy/h

Class Boson
    Inherits System     

    Property Overrides Spin as Single = 1
    Property Overrides Frequency as Long Integer = f

The big difference between Photons and other Bosons is that Photons can "travel" anywhere. All other Bosons "belong" to the 3dSystem that "created" them. Gluons will have subsystems that are the 3dSystems (2) that they "glue". W and Z bosons supply energy (via their frequency) to the 3dSystem that created them.

[Bored chemist]

It is no wonder Photons cannot be directly measured.

They can.
https://en.wikipedia.org/wiki/Gamma_spectroscopy
https://en.wikipedia.org/wiki/Photon_counting

Like all bosons except possible Higgs particles they are not "observable"

Carbon atoms are bosons.
They have been observed.

They are the equivalent of Events in computer science which also are not "observable". In computer science, we can raise an event and we can handle an event but we cannot otherwise access it.

That can not be reelevant, ince we can, in fact, observe bosons.

It is likely that bosons are not observable because they do not "contain" energy

It isn't likely that they are unobservable.
Because, they can, of course, be observed.

Higgs particles seem to straddle the space between a boson and a fermion,

Higgs bosons aer, obviously bosons.
Particles either are, or are not bosons.
It's not possible to be both.

[mxplxxx (OP)]

According to current physics theory, a photon travels at a constant speed of SOL. It may be more logical to think of a photon as stationary (its gyroscopic nature will keep it that way) and the 3dSystem that the photon is part of as travelling at SOL relative to it. A stationary photon is timeless.

It is also possible that, in the same way a photon is stationary, a neutrino may also be stationary. This gives rise to the possibility that a photon and a neutrino go hand-in-hand. The two are created together and together provide information about an "event" in Reality.

It may also be that the tiny amount of mass that is often attributed by physics to a photon may come from an accompanying neutrino.

Or, it may be that a neutrino is a reference to a "real" or "shadow"  particle. i.e., in the case of a photon, a stationary "shadow" particle/photon is created whenever a state change occurs in a particle and a neutrino is created to reference the photon. The mass of the neutrino in this case may hold the "universal id" of the photon (paralleling the "object id." of a reference object in a computer program).

In fact, it may be that all particles have a "Universal Id" meaning all particles have at least a tiny amount of mass.

[Kryptid]

The idea of a photon sitting still while the rest of the Universe moves around it at the speed of light falls apart as soon as you add a second photon moving in a different direction to the first.

[mxplxxx (OP)]

The idea of a photon sitting still while the rest of the Universe moves around it at the speed of light falls apart as soon as you add a second photon moving in a different direction to the first.

Thanks for your observation. My point is that Photons (and neutrinos) generally do not move. i.e. a second photon is also stationary. In any case, direction is relative. In the case of 3dAbstractions, a 3DSystem will be moving in a particular direction relative to a particular photon. The only direction of consequence for a photon is the direction of its intrinsic angular momentum. This is an absolute direction.

 From this perspective, a photon (and a neutrino) naturally stays in the present whilst the rest of the universe has to speed to catch up with the present:)

[Kryptid]

My point is that Photons (and neutrinos) generally do not move.

A point at odds with observation. There is no reference frame from which we can observe a photon not moving (at least in a vacuum).

The universe will have changed direction when the second photon is created.

And what if those two photons were created at the same time (for instance, when an electron and positron annihilate)? You realize that the Universe is currently filled with countless photons moving in different directions, don't you?

From this perspective, a photon (and a neutrino) naturally stays in the present whilst the rest of the universe has to speed to catch up with the present:)

This statement makes no sense.

[mxplxxx (OP)]

My point is that Photons (and neutrinos) generally do not move.

A point at odds with observation. There is no reference frame from which we can observe a photon not moving (at least in a vacuum).

The universe will have changed direction when the second photon is created.

And what if those two photons were created at the same time (for instance, when an electron and positron annihilate)? You realize that the Universe is currently filled with countless photons moving in different directions, don't you?

From this perspective, a photon (and a neutrino) naturally stays in the present whilst the rest of the universe has to speed to catch up with the present:)

This statement makes no sense.

Sorry, I should have been talking about 3dPhotons and 3dNeutrinos. Reference frames have been replaced by 3dSystems in my theory. 3dSystems is a simulation of Reality, as is Quantum theory. In any case, I make the following points about the photons of Quantum theory.

1. Would a photon not see itself as stationary (as per a Lorenz transformation)? Are you not stationary?
2. Photons cannot be observed.
3. If photons cannot be observed  who is is to say photons can be created simultaneously?
4. For an "observer", the present "happens" at the speed of light.
5. The spin angular momentum of a photon can supply the direction of travel of the photon (i.e. no need for a frame of reference). Not sure of this.

[Bored chemist]

1. Would a photon not see itself as stationary. Are you not stationary ?

Ignoring the philosophical question of what a photon "sees"...
If it sees anything then what it will see is that the journey it takes is compressed by fitzgerald contraction to zero distance.
And it covers that zero distance in zero time.
From the PoV of a photon (if it has one) the rest of the Universe does not exist.

[Bored chemist]

Photons cannot be observed.

Yes they can.
In particular, if a gamma ray photon hits your eye you might actually see the scintillation.

If photons cannot be observed

They can be.

who is is to say photons can be created simultaneously?

Logic.
They are brought into being by the same event. It follows that they happen at the same time.
There's also experimental observation of this - used every day throughout the world in medical imaging.
https://en.wikipedia.org/wiki/Positron_emission_tomography#Emission

Why are you pretending that reality doesn't happen?

[Kryptid]

4. For an "observer", the present "happens" at the speed of light.

That statement makes no sense. Time is not a velocity.

5. The spin angular momentum of a photon can supply the direction of travel of the photon (i.e. no need for a frame of reference). Not sure of this.

I can't make sense of this either.

[mxplxxx (OP)]

That statement makes no sense. Time is not a velocity.

A light year is related to velocity. A photon that is currently a light year away will create the present if it interacts with you in a year's time. i.e. the present is proceeding at the speed of light.     

 

Quote from: mxplxxx on Today at 07:23:37
5. The spin angular momentum of a photon can supply the direction of travel of the photon (i.e. no need for a frame of reference). Not sure of this.

I can't make sense of this either.

Not to worry, I am not sure about it myself. Maybe ResearchGate can help: https://www.researchgate.net/publication/327365074_Spin_and_orbital_angular_momentum_of_photons

[Kryptid]

A light year is related to velocity. A photon that is currently a light year away will create the present if it interacts with you in a year's time. i.e. the present is proceeding at the speed of light.     

That still doesn't make sense. Time is not a velocity. Being related to velocity is not sufficient.

Not to worry, I am not sure about it myself. Maybe ResearchGate can help: https://www.researchgate.net/publication/327365074_Spin_and_orbital_angular_momentum_of_photons

What I can't make sense of is why you think the photon's intrinsic angular momentum can supply its direction.

[Bored chemist]

A light year is related to velocity. A photon that is currently a light year away will create the present if it interacts with you in a year's time. i.e. the present is proceeding at the speed of light.

No, because
A light year "Bullet second" is related to velocity. A photon "Bullet " that is currently a second year away will create the present if it interacts with you in a year's second's time. i.e. the present is proceeding at the speed of light. a bullet.
Or a train, if it's important that you don't miss it.
Or an asbestos fibre, if that's what kills you.

What I can't make sense of is why you think the photon's intrinsic angular momentum can supply its direction.

I presume he thinks it travels like a corkscrew.