[alright1234 (OP)]

So you cannot mathematically depict something that does not physically exist.


How do you know mathematics to use?

[Kryptid]

So you cannot mathematically depict something that does not physically exist.

Did you forget this already?

Engineers do this all the time whenever they design something that hasn't been built yet.

How do you know mathematics to use?

By studying the laws of physics to see which equations work and which ones don't work.

[alright1234 (OP)]

By studying the laws of physics to see which equations work and which ones don't work.

Hey but if you do not know what it is how do you apply the laws of physics. The laws of physics require that you know what it it.

[Kryptid]

Hey but if you do not know what it is how do you apply the laws of physics. The laws of physics require that you know what it it.

Isaac Newton didn't know the mechanism behind gravity, but he was able to derive highly-accurate equations about its behavior anyway. So did Johannes Kepler.

[alright1234 (OP)]

Hey but if you do not know what it is how do you apply the laws of physics. The laws of physics require that you know what it it.

Isaac Newton didn't know the mechanism behind gravity, but he was able to derive highly-accurate equations about its behavior anyway. So did Johannes Kepler.

That's my point Newton gravity equation and the centripetal force equations do not function.

[Kryptid]

That my whole point Newton gravity equations do not function.

They work well enough for most purposes.

[alright1234 (OP)]

Newton's gravity equation is applied to an astronaut with a mass of 50 kg in the space station that is 249 miles (400,727 m) from the surface of the earth. The distance r which represents the distance from the center of the earth to the space station is,



r = (earth's radius) + (height) = (6.371  x 106 m) + (.4  x 106 m) = 6.771  x 106 m......................................69


Using the distance for r (equ 70) in Newton's gravity equation forms,




F = (G m1 m2)/r2  = (6.7 × 10-11) x (50kg) x (6 x 1024kg) / (6.771  x 106m)2 ≃ 438.4 N or 44.7 kg .........................70



According to Newton's gravity equation, a 50 kg astronaut in the space station forms a 44.7 kg gravitational force pointed at the earth. The centripetal force CF is used to justify the weightlessness of an astronaut in the space station is calculated,



CF = mv2/r = (50 kg)(7672 m/s)2/ (6.771 x 106 m) = 437 N or 44.56 kg..........................................71



The gravitational and centripetal forces form an equilibrium that produces the weightless astronaut yet when a force is applied to an astronaut outside the space space and the astronaut propagates at a velocity of 100 km/hr in the direction opposite to the angular velocity, the described astronaut does not propagate towards the earth which proves the gravitational and centripetal forces do not function for a 50 kg astronaut propagating around the earth. Also, the space stations is orbiting the earth at approximately 400 km miles above the surface of the earth. The 450 ton space station cannot orbit the earth at a height of 1000 miles above the surface of the earth which proves the gravitational and centripetal forces do not function for the space station at the height of 1,600 km. In addition, the centripetal force for a 50 kg mass on the surface of the earth propagating around the Sun is calculated,


CF = mv2 /r = (50kg)(30,462 m/s)2 / (1.5 x 1011 m) = .31 N...72


At 12:00 am (midnight), the centripetal force produced by the 50 kg mass on the surface of the earth propagating (30,000 m/s) around the Sun is .31 N pointed away from the earth which represents the decrease in the weight of the 50 kg mass yet at 12:00 am (noon) a .2908 N ( v = 29,648 m/s) centripetal force would be pointing in the direction of the earth that would represent a .6 N weight variation every 24 hours which is not experimentally observe and proves the centripetal force does not function for a 50 kg mass on the surface of the earth propagating around the Sun.

[Kryptid]

the astronaut propagates at a velocity of 100 km/hr in the direction opposite to the angular velocity

What exactly are you trying to say here? How can an object move in the opposite direction of its own angular velocity? That's an oxymoron.

The 450 ton space station cannot orbit the earth at a height of 1000 miles above the surface of the earth

If it was traveling at the right speed it would. Why do you not think so?

At 12:00 am (midnight), the centripetal force produced by the 50 kg mass on the surface of the earth propagating (30,000 m/s) around the Sun is .31 N pointed away from the earth which represents the decrease in the weight of the 50 kg mass yet at 12:00 am (noon) a .2908 N ( v = 29,648 m/s) centripetal force would be pointing in the direction of the earth that would represent a .6 N weight variation every 24 hours which is not experimentally observe and proves the centripetal force does not function for a 50 kg mass on the surface of the earth propagating around the Sun.

You're forgetting something important. When the Sun is below the mass (on the other side of the Earth(, it will be pulling on it with its gravitational field (increasing its weight). When it is above the mass, it will decrease its weight instead. Redo your calculations with that in mind.

[alright1234 (OP)]

It would be negligible.

[alright1234 (OP)]

Good point though. I have to think about it but I would guess that it would mostly cancel.

[Kryptid]

It would be negligible.

Demonstrate it.

By the way, the Moon's gravity would also affect the weight, as would the fact that the Earth moves around the Earth-Moon barycenter: https://en.wikipedia.org/wiki/Barycenter

[alright1234 (OP)]

I have to think about it and maybe draw a picture or something or make something up but I have to go and take a nap, bye bye since tomorrow is my wedding and I will be going on my honeymoon to Hawaii with her to some deserted park without any bikinis girls--- what fun. Marriage sounds like so much fun. At least she can cook, clean and has good hygiene. Early sabbatical. Harvard is so generous in those regards. Just what I needed. Who ever heard of a Wednesday wedding but its supposed to be good luck. Just what I needed.

[Kryptid]

I have to think about it and maybe draw a picture or something or make something up but I have to go and take a nap, bye bye since tomorrow is my wedding and I will be going on my honeymoon to Hawaii with her to some deserted park without any bikinis girls--- what fun. Marriage sounds like so much fun. At least she can cook, clean and has good hygiene. Early sabbatical.

Okay.

Have a good time!

[alright1234 (OP)]

Thanks alot

[evan_au]

At the beginning of April, LIGO (2 gravitational wave detectors in USA) and VIRGO (1 detector in Italy) resumed observations after being upgraded to improve sensitivity.

Since then, they have reportedly detected around 1 candidate merger event per week, which will quickly increase the sample size of these spectacularly energetic events.
See: https://www.ligo.caltech.edu/news/ligo20190326

They describe the increase in sensitivity using the example of a neutron star merger; one that they previously could detect at 360 Million Light-Years will now be detectable at 550 MLY. This 50% increase in range may not sound like a big boost, but it represents a much larger volume of space - 3.5 times larger than previously. They should detect about 3 times as many events. as previously.

[Colin2B]

tomorrow is my wedding and I will be going on my honeymoon to Hawaii with her to some deserted park without any bikinis girls--- what fun.

What wen’t wrong?
Why didn’t you go away to Hawaii??

Early sabbatical. Harvard is so generous in those regards.

We get a lot of people posting here and claiming to be something they are not. Usually they give themselves away very quickly. You did it faster than most.

[Bored chemist]

He could be posting from a honeymoon in Hawaii.
Or he could be lying.
I know which I think is more likely.

[Colin2B]

He could be posting from a honeymoon in Hawaii.
Or he could be lying.
I know which I think is more likely.

I’ll give you a hint, he isn’t posting from Hawaii.

[evan_au]

Harvard is so generous

The university isn't Harvard, but it does start with a "H"...

And Hawaii isn't the location, but there are some volcanoes a short flight away...

[Colin2B]

Harvard is so generous

The university isn't Harvard, but it does start with a "H"...

And Hawaii isn't the location, but there are some volcanoes a short flight away...

I noticed that. At least H was his ‘current’ location