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You talk a lot about vacuum.Gravity works just fine in air.
Also, please explain how gravity affects the path of light.
Gravitational time dilation clearly demonstrates that you are wrong. That's a distortion of time caused by a gravitational field.
It doesn't demonstrate I'm wrong
My explanation is a photon have twice its measured energy, one is its kinetic energy the other one is its contained energy, so gravitational force on it is twice
hidden space doesn't exist it is imaginary
It does if you claim that gravity can't distort time.
That would violate conservation of energy.
Secondly, photons having double the expected energy would do nothing to change gravitational lensing. It's for the same reason that a bowling ball falls at the same rate in a vacuum as a ping pong ball.
Not that it matters, as there is no requirement for a "hidden space" to explain gravity. The arc you are talking about is an arc in space-time. Time is an essential part of the equation.
I didn't claim anything about time.
Gravity is not caused by space -time curvature
It doesn't .A mass could have energy equivalent to its mass and kinetic energy of its motion.
It's not about the rate of falling it's about the bending proccess, two objects with different masses will have different bending angles its simple mechanics.
Still I need explanation of difference between space we see and space which is curved.
You did when you said this:"Gravity is not caused by space -time curvature"
All of the energy of an object contributes to mass, including its kinetic energy. The faster an object moves, the more massive it becomes: https://en.wikipedia.org/wiki/Mass_in_special_relativity#Relativistic_mass
No it doesn't. Photons have a relativistic mass that is determined by their energy. A photon with a higher energy therefore has more mass. If what you claimed about mass and path bending was true, then more energetic (bluer) photons would be more strongly affected by gravitational lensing than less energetic (redder) photons. They aren't. Both red and blue photons are deflected by the same amount: http://curious.astro.cornell.edu/about-us/140-physics/the-theory-of-relativity/general-relativity/1029-is-light-of-different-colors-affected-differently-by-gravity-intermediate
There is no difference: you can see the effects of a distortion in space if you know where and how to look. The anomalous precession of Mercury's perihelion is one such detectable example, as is the geodetic effect and gravitomagnetism.
There is not space-time curvature but there is time dilation, I agree there is time dilation but that doesn't mean it's only explained by the idea of space-time curvature
matter is frozen energy,
I claim the only energy that is measure for a photon is its contained energy, kinetic energy is not measured
But all rays are one entity
I don't understand what you are talking about .Could you give me simple and detailed explanation?
This is demonstrably wrong, as we can measure the kinetic energy of light. It pushes things, and we can measure that push: https://en.wikipedia.org/wiki/Radiation_pressure
"But all rays are one entity"Obviously not, otherwise two different people wouldn't be able to see the same object at once. Each person must be seeing their own ray of light. One photon can be absorbed while another in the same beam of light keeps going.
All three of those things refer to different measurable changes in an object's orbit due to the distortion of space around that object: https://en.wikipedia.org/wiki/Geodetic_effect https://en.wikipedia.org/wiki/Gravitoelectromagnetism#Gravitomagnetic_fields_of_astronomical_objects https://en.wikipedia.org/wiki/Tests_of_general_relativity#Perihelion_precession_of_Mercury
Could you focus in my example and explain the problem I am asking about?
I missed a word all color rays
OK, good, if the contained energy is equal to kinetic energy, then when light pushes a surface it will lose its kinetic energy and its contained energy , then photons disappear and won't reflect"
but I claim its kinetic energy is different from its contained energy it will lose its kinetic energy without effect in its contained energy so that it will reflect again as photons.