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Holes covered by mirrors..
So, if it's not you, who states all those things, then who is it? Should I understand, that you don't associate with your own claims?
Quote from: CrazyScientist on 11/06/2021 19:52:33What defines the energy of EM radiation?The product of the number of photons and the energy which each photon has.And, in your opening gambit, you kept increasing the number of photons.Once you have added C^2 worth of energy you will have increased the mass by 1Kg.It doesn't matter if that's microwave photons or visible photons which is why thisQuote from: CrazyScientist on 11/06/2021 19:52:33It's because the difference of the wavelenght/frequency of EM radiation.is nonsense.Go away and don't come back until either you have learned some science, or until you are prepared to learn some.
What defines the energy of EM radiation?
It's because the difference of the wavelenght/frequency of EM radiation.
Ok, I should be more specific:What is the difference between emission of light and emission of thermal radiation? Are there any substantial differences between both mechanics?
So you say, that a constant emission of light inside a perfect spherical cavity will lead to the constant increase of the energy in the system, until a critical level is reached and cavity explodes or a BH is formed
Quote from: CrazyScientist on 11/06/2021 21:08:45Holes covered by mirrors..The sides of lasers are not covered by mirrors.Stop making up nonsense.
Quote from: Bored chemist on 11/06/2021 21:17:10Quote from: CrazyScientist on 11/06/2021 21:16:00So you say, that a constant emission of light inside a perfect spherical cavity will lead to the constant increase of the energy in the system, until a critical level is reached and cavity explodes or a BH is formedNo.Stop doing that.I never said that.Quote from: CrazyScientist on 11/06/2021 20:34:49I am treating it as an increasing number of photons (and, accordingly, and increasing mass of photons).
Quote from: CrazyScientist on 11/06/2021 21:16:00So you say, that a constant emission of light inside a perfect spherical cavity will lead to the constant increase of the energy in the system, until a critical level is reached and cavity explodes or a BH is formedNo.Stop doing that.I never said that.
I am treating it as an increasing number of photons (and, accordingly, and increasing mass of photons).
you were talking about the inner surface of the cylinder
Stop doing that.I never said that.
QuoteQuote from: Bored chemist on Today at 21:17:10Quote from: CrazyScientist on Today at 21:16:00So you say, that a constant emission of light inside a perfect spherical cavity will lead to the constant increase of the energy in the system, until a critical level is reached and cavity explodes or a BH is formedNo.Stop doing that.I never said that.Quote from: CrazyScientist on Today at 20:34:49I am treating it as an increasing number of photons (and, accordingly, and increasing mass of photons).
Quoting me out of context is also dishonest.You just tried to pretend that I was talking about a source inside the sphere when the actual discussion point was a source outside the sphere with the light (and mass) going in through a hypothetical valve..You really need to stop making false statements.
"Imagine a source of light, like a led lamp (almost no emission of heat), which is enclosed inside a hollow sphere with a perfect mirror as it's inner surface. What do you think will happen, if that source will continuouslly emit light with a constant intensity and frequency, which will be then continuously reflected inside the sphere? Keep in mind, that there won't be no absorption of energy by the inner surface (100% of energy reflected from the perfect mirror)..."
OK, the inside of the sphere is perfectly-reflecting, and there's an ideal optical diode to let light in but keep it inside
Do you know what a diode does?It's a one way valve.Quote from: CrazyScientist on 07/06/2021 12:37:40OK, the inside of the sphere is perfectly-reflecting, and there's an ideal optical diode to let light in but keep it inside
BTW Can you please explain me, why the location of source is here so important, that it completely changes the supposed outcome of photons trapping in a cavity?
Ok, so let's now assume, that the battery is actually placed somewhere outside of the spherical cavity and is powering up a source of heat (thermal radiation), allowing it to maintain a constant temprature of 1000°C. Can you explain the mechanism, which in this case could possibly lead to creation of a BH out of the thermal radiation, which is constantly emitted by the source of heat inside the cavity?
Honestly, I don't know,why he included it in his answer, since the question was about a source placed INSIDE a spherical mirror.
, the source won't absorb any energy from the cavity
What do you think will happen, if that source will continuouslly emit light with a constant intensity and frequency, which will be then continuously reflected inside the sphere? Keep in mind, that there won't be no absorption of energy by the inner surface (100% of energy reflected from the perfect mirror)...
Quote from: CrazyScientist on 12/06/2021 15:58:08, the source won't absorb any energy from the cavityIf the source is able to emit at some wavelength then it will absorb at that wavelength.The size, shape, cost or colour of the cavity don't affect that.
In this article we theoretically study the phase shift a single atom imprints onto a coherent state light beamin free space. The calculations are performed in a semiclassical framework. The key parameters governingthe interaction and thus the measurable phase shift are the solid angle from which the light is focused onto theatom and the overlap of the incident radiation with the atomic dipole radiation pattern. The analysis includessaturation effects and discusses the associated Kerr-type non-linearity of a single atom.
The fluctuating electromagnetic field in a cavity with perfectly conducting walls is generally composed of two kinds of modes: electric (TM) and magnetic (TE). Conventional wisdom says that if the cavity volume is made smaller, the eigenfrequencies rise. Here, a counterexample is demonstrated: if the cavity is spherical and has annular form (inner radius a and outer radius b), then the eigenfrequencies for the lowest electric modes decrease monotonically if the region is made shallower. This abnormality is of quantum mechanical interest. Thus, if an excited two-level atom of free-space emission frequency 0143-0807/19/4/001/img1 satisfying the condition 0143-0807/19/4/001/img2 is situated in the (vacuum) cavity, the atom will be unable to radiate the photon for a = 0. If a now increases, meaning that the cavity takes an annular form, a point will be reached at which emission is permitted. This abnormal behaviour is characteristic of the spherical geometry and is not present in the analogous cylindrical geometry.
Sorry to inform you, that you couldn't be more wrong. Didn't you learn in high-school, that photons can interact with atoms only at couple specific energy states of the system?
OK now we compress the ball spherically so the density increases. (That's obviously somewhere between impractical and impossible, but never mind.- it's just a thought experiment and I will present a way round it presently)At some point we will squeeze it inside its own Schwarzschild radius and at that point it will become a black hole