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  4. What makes Riemann's Hypothesis Hard to Prove?
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What makes Riemann's Hypothesis Hard to Prove?

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Offline hamdani yusuf (OP)

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Re: What makes Riemann's Hypothesis Hard to Prove?
« Reply #80 on: 15/03/2024 13:29:00 »
For every nontrivial zero of Zeta function, ζ(s) =0,
Re(Y(s)) = - ~  (negative infinity)
Im(Y(s) = undefined (due to switching between two different, discontinuous values)
The plot of Y function suggests that those conditions can only be satisfied where Re(s) = 1/2, as Riemann predicted.
« Last Edit: 11/05/2024 03:21:43 by hamdani yusuf »
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Re: What makes Riemann's Hypothesis Hard to Prove?
« Reply #81 on: 15/03/2024 16:49:20 »
https://www.wolframalpha.com/input?i=plot+%7Czeta%281%2F2+%2B+s.+i%29%7C+from+0+to+30



https://www.wolframalpha.com/input?i=plot+%7Czeta%281%2F2+%2B+s.+i%29%7C+from+1000+to+1030


The plots above show that at higher imaginary part of s, the density of Zeta zero is higher. It reduces the space for anomalous zero. Thus the higher the imaginary part, the less likely we can find anomalous zero of Zeta function. It provides a stronger indication that Riemann's hypothesis is true.

* Screenshot 2024-03-18 194328.png (42.98 kB, 523x600 - viewed 449 times.)

* Screenshot 2024-03-18 194348.png (59.84 kB, 513x599 - viewed 409 times.)
« Last Edit: 18/03/2024 12:48:05 by hamdani yusuf »
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Re: What makes Riemann's Hypothesis Hard to Prove?
« Reply #82 on: 19/03/2024 07:26:28 »
It's now considered an established fact that non-trivial zero of Riemann's Zeta function cannot occur when Re(s)<0, or Re(s)>1, So we can ignore these area.

So far, all known non-trivial zero lie on critical line, Re(s)=1/2, up to |Im(s)|≈10^36



The shape of Y function is maintained no matter how big the imaginary part of its input. It supports the Riemann's hypothesis.

Unfortunately WolframAlpha refuses to plot the Y function for Im(s)>10^10

* Screenshot 2024-03-19 142123.png (45.24 kB, 687x564 - viewed 346 times.)

* Screenshot 2024-03-19 142205.png (39.71 kB, 689x577 - viewed 343 times.)
« Last Edit: 19/03/2024 07:36:30 by hamdani yusuf »
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Re: What makes Riemann's Hypothesis Hard to Prove?
« Reply #83 on: 26/03/2024 10:11:59 »
Quote from: hamdani yusuf on 15/03/2024 12:07:46
I'd like to introduce a function, which I call Y function, just because that's how its plot look like in complex plane. It can also called upsilon function, just to sound more geeky. It's defined as follow:
Y(s)=ln{ζ(s) - ζ(1-s*)}
I played around with this Y function, and found something interesting when 1 in the formula is replaced with other numbers. The plot looks simpler when s has high imaginary part.

This is the base case of Y function.

Next, the formula is modified by replacing 1 with another number, which I call m for mirroring constant. The mirror position is half of m, which can be conveniently called n. In the example below, m=40, hence n=20.


The value of m can also be negative.


The plot shows that when m is positive, the plot looks like it consists of straight lines which bent around the point of origin and point of mirroring. On the other hand, when m is negative, the bent is located only at the point of mirroring.

* Screenshot 2024-03-26 170255.png (49.79 kB, 724x577 - viewed 365 times.)

* Screenshot 2024-03-26 170334.png (44.31 kB, 716x567 - viewed 355 times.)

* Screenshot 2024-03-26 170416.png (47.67 kB, 747x578 - viewed 347 times.)
« Last Edit: 26/03/2024 10:27:42 by hamdani yusuf »
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Re: What makes Riemann's Hypothesis Hard to Prove?
« Reply #84 on: 26/03/2024 10:38:35 »
When m=0, the plot is symmetrical around y axis. The higher the imaginary part of s, the curve gets more straightened.


When m is small, then the bending doesn't not look that sharp.


When m =1, the low slope part isn't visible.

* Screenshot 2024-03-26 173652.png (47.32 kB, 832x616 - viewed 341 times.)

* Screenshot 2024-03-26 173438.png (46.97 kB, 834x623 - viewed 348 times.)

* Screenshot 2024-03-26 173520.png (49.41 kB, 826x614 - viewed 363 times.)
« Last Edit: 26/03/2024 10:45:42 by hamdani yusuf »
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Re: What makes Riemann's Hypothesis Hard to Prove?
« Reply #85 on: 30/04/2024 23:07:15 »
An important feature of the original Y function related to Riemann zeta function is the abrupt change of its imaginary part at reflection line/critical line. Other abrupt changes occur far away from critical strip.

Quote from: hamdani yusuf on 26/03/2024 10:38:35
When m =1, the low slope part isn't visible.
Quote from: hamdani yusuf on 26/03/2024 10:11:59
I played around with this Y function, and found something interesting when 1 in the formula is replaced with other numbers. The plot looks simpler when s has high imaginary part.

« Last Edit: 01/05/2024 05:04:33 by hamdani yusuf »
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Offline hamdani yusuf (OP)

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Re: What makes Riemann's Hypothesis Hard to Prove?
« Reply #86 on: 01/05/2024 05:35:30 »
Let's switch our attention to the imaginary part of Y function. At reflection line, the imaginary part abruptly changes by pi, but anywhere else, it changes by 2 pi, ie. it switches between positive and negative pi. These results are easier to understand by plotting the Y function in 3D to show its circular nature.
In polar coordinate, point at (r, pi) coincides with point at (r, -pi). While point at (r, theta) has the opposite direction from point at (r, theta +/- pi). It means that if a straight line is drawn between them, it crosses the origin.

If you wonder how logarithmic function works on a complex number.
Quote
The logarithm of a complex number z=log(r*e^(iθ)) is condensed as log(z)=log(r)+iθ, where r is the absolute value of z and θ is the argument of z. It is represented in polar coordinates.
« Last Edit: 01/05/2024 11:26:08 by hamdani yusuf »
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Re: What makes Riemann's Hypothesis Hard to Prove?
« Reply #87 on: 01/05/2024 05:54:12 »
Quote from: hamdani yusuf on 15/03/2024 12:47:56
when imaginary part of s is close to the smallest non-trivial zero of Riemann's zeta function
https://www.wolframalpha.com/input?i=plot+%28ln%28%28zeta%28s%2B14.134725+i%29%29+-+%28Zeta%281-s%2B14.134725+i%29%29%29+%29from+-22+to+23


Any larger value for the imaginary part of s don't change shape of the real part of Y function, only the imaginary part gets longer period.
https://www.wolframalpha.com/input?i=plot+%28ln%28%28zeta%28s%2B114.134725+i%29%29+-+%28Zeta%281-s%2B114.134725+i%29%29%29+%29from+-22+to+23

Another trend is that at larger value of Re(s), imaginary part of Y function has smaller period.

https://www.wolframalpha.com/input?i=plot+im%28log%28zeta%28x-125i%29-Zeta%281-x-125i%29%29%29from+1000+to+1040
Compared to
https://www.wolframalpha.com/input?i=plot+im%28log%28zeta%28x-125i%29-Zeta%281-x-125i%29%29%29from+100+to+140

It means that close to reflection line, imaginary part of Y function has largest period. It makes violation of Riemann hypothesis less likely.

It seems like Zeta function has more regularity than some of us might think.
« Last Edit: 01/05/2024 06:57:29 by hamdani yusuf »
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Re: What makes Riemann's Hypothesis Hard to Prove?
« Reply #88 on: 01/05/2024 09:54:43 »
Why greatest Mathematicians are not trying to prove Riemann Hypothesis?

Now we have tools like Wolfram Alpha and generative AI models which makes math more accessible to laypersons.
« Last Edit: 01/05/2024 09:57:56 by hamdani yusuf »
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Re: What makes Riemann's Hypothesis Hard to Prove?
« Reply #89 on: 04/05/2024 15:15:43 »
I think I have enough materials to make my own YouTube video on Riemann's hypothesis. While looking for free animations about it on Google, I found one that links to this video from quanta magazine.
Riemann Hypothesis, Explained
Quote
The Riemann Hypothesis is the most notorious unsolved problem in all of mathematics. Ever since it was first proposed by Bernhard Riemann in 1859, the conjecture has maintained the status of the "Holy Grail" of mathematics. In fact, the person who solves it will win a $1 million prize from the Clay Institute of Mathematics. So, what is the Riemann hypothesis? Why is it so important? What can it tell us about the chaotic universe of prime numbers? And why is its proof so elusive? Alex Kontorovich, professor of mathematics at Rutgers University, breaks it all down in this comprehensive explainer.


00:00 A glimpse into the mystery of the Riemann Hypothesis
01:42 The world of prime numbers
02:30 Carl Friedrich Gauss looks for primes, Prime Counting Function
03:30 Logarithm Function and Gauss's Conjecture
04:39 Leonard Euler and infinite series
06:30 Euler and the Zeta Function
07:30 Bernhard Riemann enters the prime number picture
08:18 Imaginary and complex numbers
09:40 Complex Analysis and the Zeta Function
10:25 Analytic Continuation: two functions at work at once
11:14 Zeta Zeros and the critical strip
12:20 The critical line
12:51 Why the Riemann's Hypothesis has a profound consequence to number theory
13:04 Riemann's Hypothesis shows the distribution of prime numbers can be predicted
14:59 The search for a proof of the Riemann Hypothesis

« Last Edit: 05/05/2024 05:58:30 by hamdani yusuf »
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Offline hamdani yusuf (OP)

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Re: What makes Riemann's Hypothesis Hard to Prove?
« Reply #90 on: 04/05/2024 17:33:56 »
Another result I got from searching.
Quote
Why is the Riemann Hypothesis hard? Just one reason (of very many): it's not an analytic question. Here are the values of zeta on the 1/2-line (where at least 40% of the zeros are, all should be) and the 4/5-line, where none should be. The latter gets arbitrarily close to 0, i.o.

https://www.johndcook.com/blog/2019/11/29/near-zeros-of-zeta/
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Re: What makes Riemann's Hypothesis Hard to Prove?
« Reply #91 on: 05/05/2024 06:12:36 »
Here's a modification from Y function, by using division instead of subtraction.
https://www.wolframalpha.com/input?i=plot+log%28%28zeta%28x%2B550.01i%29%29+%2F+%28Zeta%281-x%2B550.01i%29%29%29from+-20+to+21
https://www.wolframalpha.com/input?i=plot+log%28%28zeta%28x%2B550.01i%29%29+%2F+%28Zeta%281-x%2B550.01i%29%29%29from+0+to+1
Let's call it backslash function, for how it looks like. Note that at Re(s) =0.5, the value of backslash function is 0. It implies that zeta(s)=zeta(1-s*) at that point.
« Last Edit: 07/05/2024 12:10:06 by hamdani yusuf »
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Re: What makes Riemann's Hypothesis Hard to Prove?
« Reply #92 on: 08/05/2024 16:20:43 »
I'm trying to explore using these Y function and backslash function as visual proof for Riemann's hypothesis.
To be useful, a proof necessarily lies on the borderline between order and chaos. It reminds me of a famous quote.
Quote
Any idiot can build a bridge that stands, but it takes an engineer to build a bridge that barely stands.
« Last Edit: 09/05/2024 11:11:28 by hamdani yusuf »
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Offline hamdani yusuf (OP)

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Re: What makes Riemann's Hypothesis Hard to Prove?
« Reply #93 on: 08/05/2024 22:49:02 »
The proof can start from this implication.
Quote from: hamdani yusuf on 29/07/2022 00:23:37
when ζ(1-s)=0 → ζ(s)=0, ζ(s*)=0,  ζ(1-s*)=0
The sum and difference among those terms must also equal 0

If the plot is too orderly, it can't show non-trivial information, like in these plots.
Quote from: hamdani yusuf on 23/05/2023 22:34:47
Let's focus on the imaginary part of the addition equation.
https://www.wolframalpha.com/input?i=plot+im%28zeta%280.5%2Bis%29+%2B+zeta%280.5-is%29%29+from+0+to+30
And the real part of the subtraction equation.
https://www.wolframalpha.com/input?i=plot+re%28zeta%280.5%2Bis%29+-+zeta%280.5-is%29%29+from+0+to+30
They are always zero.

But if they are too chaotic, no pattern can be extracted.
Quote from: hamdani yusuf on 23/05/2023 22:34:47
Compare them to the value of s where the real part is slightly different from 0.5.
https://www.wolframalpha.com/input?i=plot+im%28zeta%280.5001%2Bis%29+%2B+zeta%280.4999-is%29%29+from+0+to+30

https://www.wolframalpha.com/input?i=plot+re%28zeta%280.5001%2Bis%29+-+zeta%280.4999-is%29%29+from+0+to+30
« Last Edit: 08/05/2024 23:02:32 by hamdani yusuf »
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Offline hamdani yusuf (OP)

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Re: What makes Riemann's Hypothesis Hard to Prove?
« Reply #94 on: 09/05/2024 02:11:29 »
Quote from: hamdani yusuf on 04/05/2024 17:33:56
Another result I got from searching.
Quote
Why is the Riemann Hypothesis hard? Just one reason (of very many): it's not an analytic question. Here are the values of zeta on the 1/2-line (where at least 40% of the zeros are, all should be) and the 4/5-line, where none should be. The latter gets arbitrarily close to 0, i.o.

https://www.johndcook.com/blog/2019/11/29/near-zeros-of-zeta/
Most previous works tried to find patterns in the plot of Zeta function on imaginary axis.

Quote from: hamdani yusuf on 15/03/2024 16:49:20
https://www.wolframalpha.com/input?i=plot+%7Czeta%281%2F2+%2B+s.+i%29%7C+from+0+to+30



https://www.wolframalpha.com/input?i=plot+%7Czeta%281%2F2+%2B+s.+i%29%7C+from+1000+to+1030


The plots above show that at higher imaginary part of s, the density of Zeta zero is higher. It reduces the space for anomalous zero. Thus the higher the imaginary part, the less likely we can find anomalous zero of Zeta function. It provides a stronger indication that Riemann's hypothesis is true.
But they are too chaotic to collect useful patterns or information.
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Re: What makes Riemann's Hypothesis Hard to Prove?
« Reply #95 on: 09/05/2024 02:26:33 »
At first, plotting the difference of zeta function and its reflection by the critical line on real axis doesn't seem to show simple and convincing patterns.

https://www.wolframalpha.com/input?i=plot+%28++%28zeta%28x%2B0.00i%29%29+-++%28Zeta%281-x%2B0.00i%29%29%29from+-30+to+31

https://www.wolframalpha.com/input?i=plot+%28++%28zeta%28x%2B20.00i%29%29+-++%28Zeta%281-x%2B20.00i%29%29%29from+-30+to+31

https://www.wolframalpha.com/input?i=plot+%28++%28zeta%28x%2B2000.00i%29%29+-++%28Zeta%281-x%2B2000.00i%29%29%29from+-30+to+31

But if logarithmic function is applied, the patterns emerge.
https://www.wolframalpha.com/input?i=plot+log%28++%28zeta%28x%2B0.00i%29%29+-+%28Zeta%281-x%2B0.00i%29%29%29from+-30+to+31

https://www.wolframalpha.com/input?i=plot+log%28++%28zeta%28x%2B20.00i%29%29+-+%28Zeta%281-x%2B20.00i%29%29%29from+-30+to+31

https://www.wolframalpha.com/input?i=plot+log%28++%28zeta%28x%2B2000.00i%29%29+-+%28Zeta%281-x%2B2000.00i%29%29%29from+-30+to+31

* Screenshot 2024-05-16 170840.png (27.7 kB, 536x426 - viewed 137 times.)

* Screenshot 2024-05-16 170800.png (33.51 kB, 555x422 - viewed 120 times.)

* Screenshot 2024-05-16 170707.png (29.06 kB, 555x428 - viewed 115 times.)

* Screenshot 2024-05-16 170942.png (35.53 kB, 563x455 - viewed 128 times.)

* Screenshot 2024-05-16 171053.png (38.43 kB, 562x450 - viewed 114 times.)

* Screenshot 2024-05-16 171240.png (33.31 kB, 587x451 - viewed 126 times.)
« Last Edit: 16/05/2024 11:15:46 by hamdani yusuf »
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Offline hamdani yusuf (OP)

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Re: What makes Riemann's Hypothesis Hard to Prove?
« Reply #96 on: 09/05/2024 09:12:27 »
We need to be aware of numerical artefacts of computer generated images, like this ones.
https://www.wolframalpha.com/input?i=plot+log%28++%28zeta%28x%2B0.00i%29%29+-+%28Zeta%281-x%2B0.00i%29%29%29from+-30+to+31
https://www.wolframalpha.com/input?i=plot+im%28++%28zeta%28x%2B0.00i%29%29+-+%28Zeta%281-x%2B0.00i%29%29%29from+-56+to+-46
It seems like they come from rounding errors, especially when adding extremely large numbers and extremely small numbers.
« Last Edit: 09/05/2024 09:43:21 by hamdani yusuf »
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Re: What makes Riemann's Hypothesis Hard to Prove?
« Reply #97 on: 09/05/2024 10:19:13 »
Quote
The Riemann zeta function ζ(s) is a function whose argument s may be any complex number other than 1, and whose values are also complex. It has zeros at the negative even integers; that is, ζ(s) = 0 when s is one of −2, −4, −6, .... These are called its trivial zeros. The zeta function is also zero for other values of s, which are called nontrivial zeros.

The Riemann hypothesis is concerned with the locations of these nontrivial zeros, and states that:
The real part of every nontrivial zero of the Riemann zeta function is 1/2
Thus, if the hypothesis is correct, all the nontrivial zeros lie on the critical line consisting of the complex numbers 1/2 + i t, where t is a real number and i is the imaginary unit.
https://en.wikipedia.org/wiki/Riemann_hypothesis
The equivalent statement for the trivial zero is:
The imaginary part of every trivial zero of the Riemann zeta function is 0
The trivial zeros of the Riemann zeta function don't seem to attract much attention because they don't seem to be related to prime numbers. They don't seem to contain elements of "surprise".
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Re: What makes Riemann's Hypothesis Hard to Prove?
« Reply #98 on: 09/05/2024 17:32:28 »
Y function shows that in the critical strip, Zeta (s) can only equal to Zeta (1-s*), ie it's reflection by the critical line, if Re(s) =1/2, which means they are both occupy the same spot on the critical line.
On the other hand, violations of Riemann's hypothesis require zero out of the critical line. It implies that Zeta (s) can equal to zero, and equal to Zeta (1-s*) while not occupying the same point. It's in direct contradiction with the property of Y function.
Whenever two statements contradict each other, at least one of them must be false. If they are complementary to each other, ie. there's no third option, then one must be true, and the other false.
« Last Edit: 10/05/2024 05:51:29 by hamdani yusuf »
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Re: What makes Riemann's Hypothesis Hard to Prove?
« Reply #99 on: 10/05/2024 16:41:57 »

Quote
Corrections to an estimate of the prime-counting function using zeros of the zeta function. The magnitude of the correction term is determined by the real part of the zero being added in the correction.
https://en.m.wikipedia.org/wiki/Riemann_hypothesis
Instead of real part, it should say imaginer part.
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