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  4. What makes Riemann's Hypothesis Hard to Prove?
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What makes Riemann's Hypothesis Hard to Prove?

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Offline hamdani yusuf (OP)

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Re: What makes Riemann's Hypothesis Hard to Prove?
« Reply #140 on: 25/05/2024 13:01:10 »
In real life, we can often get useful information without knowing the absolute value of something. The difference or ratio between two or more related things are sometimes enough for us to solve our problems at hand.
That's what the functions I introduced previously are offering to prove Riemann's hypothesis.
« Last Edit: 25/05/2024 13:26:34 by hamdani yusuf »
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Offline hamdani yusuf (OP)

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Re: What makes Riemann's Hypothesis Hard to Prove?
« Reply #141 on: 25/05/2024 13:59:05 »
https://www.wolframalpha.com/input?i=plot+s+%2B+10+sin%282+s%29+from+-20+to+20

https://www.wolframalpha.com/input?i=plot+s+%2B+10+sin%284+s%29%2Fs+from+-20+to+20

https://www.wolframalpha.com/input?i=plot+s+%2B+10+sin%28tan%28s%29%29+from+-20+to+20

These are some other analogies to describe the problem. The functions are combination between a simple pattern and a more complex pattern. But we can see that at high input value,  the plot never crosses 0 again, because the simple pattern greatly outweighs the more complex pattern.
« Last Edit: 26/05/2024 08:42:01 by hamdani yusuf »
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Offline hamdani yusuf (OP)

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Re: What makes Riemann's Hypothesis Hard to Prove?
« Reply #142 on: 27/05/2024 17:58:00 »
Quote from: hamdani yusuf on 22/05/2024 13:30:27
Quote from: hamdani yusuf on 11/05/2024 01:19:45
After watching a video about elliptic curve, I suspected that trivial zeros of Zeta function must somehow be related to non-trivial zeros. This video shows how they are related.
The video shows that non-trivial zeros of Riemann's Zeta function must somehow be correlated to its trivial zeros. I think it's worth exploring if other points on the critical line are also correlated to points on the real line through some sort of mapping or projection.
Imagine that smallest non-trivial zero, around (0.5+14.13i) is corresponding to smallest negative even integer, ie (-2,0i). Larger non-trivial zeros are corresponding to larger negative even integers. Every non-trivial zero exists where S function has negative slope. That's when |im(s)| > (2+β) π i, which is the inflection point of S function. The role of that point on critical line is likely corresponding to (0, 0) for real line, as the edge of critical strip closest to trivial zeros.
« Last Edit: 28/05/2024 22:20:22 by hamdani yusuf »
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Offline hamdani yusuf (OP)

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Re: What makes Riemann's Hypothesis Hard to Prove?
« Reply #143 on: 27/05/2024 18:12:05 »
In transition zone between 2 π i and (2+β) πi, S function crosses zero more than once. It is corresponding to critical strip. Below 2 π i, S function in critical strip has positive slope. It's corresponding to real line >1. Critical line between 2 π i and 0 is corresponding to real line between 1 and +~.
This correlation is interesting because e^(2 π i) = 1.

Quote from: hamdani yusuf on 21/05/2024 05:01:56
Quote from: hamdani yusuf on 19/05/2024 09:57:19
Exploration of backslash function (aka S function) around its inflection point can be exciting in its own right, but does not have much effect on the determination of Riemann hypothesis, which for now has narrowed down to critical strip with extremely high imaginary part.
The behavior of S function around its inflection point reminds me of Riemann sphere.
Quote
https://en.wikipedia.org/wiki/Riemann_sphere
In mathematics, the Riemann sphere, named after Bernhard Riemann,[1] is a model of the extended complex plane (also called the closed complex plane): the complex plane plus one point at infinity. This extended plane represents the extended complex numbers, that is, the complex numbers plus a value ∞ for infinity. With the Riemann model, the point ∞ is near to very large numbers, just as the point 0 is near to very small numbers.


Here's an online simulator.
https://www.geogebra.org/m/gD7Rygd2
« Last Edit: 27/05/2024 22:56:40 by hamdani yusuf »
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Offline hamdani yusuf (OP)

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Re: What makes Riemann's Hypothesis Hard to Prove?
« Reply #144 on: 28/05/2024 13:07:45 »
Let's recap the proof or Riemann's hypothesis using S function.
For every non-trivial zero, ζ(s) = ζ(1-s*) = 0.
S function at that point must be 0.
Results of S function can be divided into three zones.
First is where S function inside the critical strip has positive slope as it crosses zero. It spans from 0i to 2πi.
Second is where S function inside the critical strip has both positive and negative slope as it crosses zero. It spans from 2πi to (2+β)πi.
Third is where S function inside the critical strip has negative slope as it crosses zero. It spans from (2+β)πi to ∞i.
In the first and third zones, the curve only crosses zero exactly once, ie at re(s) =1/2. While in the second zone, it crosses zero three times, ie at re(s) =1/2 and 2 others which are symmetrical about the critical line.
Violation of Riemann's hypothesis implies that S function can cross zero more than once in the third zone, which is contradicting the observations.
« Last Edit: 28/05/2024 13:49:09 by hamdani yusuf »
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Re: What makes Riemann's Hypothesis Hard to Prove?
« Reply #145 on: 28/05/2024 14:04:33 »
Quote from: hamdani yusuf on 25/05/2024 07:44:04
Plotted symmetrically, it looks like the letter V. So, I'll just call it V function.
Outside of critical strip, it looks more like a letter V.
https://www.wolframalpha.com/input?i=plot+re+%28log%28%28zeta%28-15.5%2B+s+i%29%29+%2F+%28Zeta%281%2B15.5%2B+s+i%29%29%29%29+from+-9+to+9
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Re: What makes Riemann's Hypothesis Hard to Prove?
« Reply #146 on: 29/05/2024 12:04:01 »
Quote from: hamdani yusuf on 19/05/2024 06:22:53
Quote from: hamdani yusuf on 17/05/2024 05:14:38
We get a nice full wave when the imaginary part is exactly 2*pi
https://www.wolframalpha.com/input?i=plot+re%28log%28zeta%28x%2B+2+pi+i%29+%2F%28Zeta%281-x%2B+2+pi+i%29%29%29%29from+0+to+1

This curve is very similar to a cubic equation 1/1887.68 * (2x-1)(1-(2x-1)^2).
Here's the plot of both curves in the same graph (the cubic equation is multiplied by i).

https://www.wolframalpha.com/input?i=plot+re%28log%28%28zeta%28x%2B2+pi+i%29%29+%2F+%28Zeta%281-x%2B2+pi+i%29%29%29%29+%2B+i%2F1887.68+%282x-1%29%281-%282x-1%29%5E2%29+from+0+to+1

Although when zoomed in, there is still visible difference.
https://www.wolframalpha.com/input?i=plot+re%28log%28%28zeta%28x%2B2+pi+i%29%29+%2F+%28Zeta%281-x%2B2+pi+i%29%29%29%29+%2Bi%2F1887.68+%282x-1%29%281-%282x-1%29%5E2%29+from+0.784+to+0.793
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Offline hamdani yusuf (OP)

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Re: What makes Riemann's Hypothesis Hard to Prove?
« Reply #147 on: 30/05/2024 03:23:16 »
https://www.wolframalpha.com/input?i=plot+re%28log%28%28zeta%28x%2B2+pi+i%29%29+%2F+%28Zeta%281-x%2B2+pi+i%29%29%29%29+-+1%2F1887.68++%282x-1%29%281-%282x-1%29%5E2%29+from+0+to+1
The difference between S function and the cubic equation looks like a quintic equation.

At a glance, it looks like this
https://www.wolframalpha.com/input?i=plot+%282x-1%29%281-%282x-1%29%5E2%29+%281-%281.7%282x-1%29%29%5E2%29from+0+to+1
« Last Edit: 30/05/2024 06:57:05 by hamdani yusuf »
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Re: What makes Riemann's Hypothesis Hard to Prove?
« Reply #148 on: 30/05/2024 07:16:08 »
A more precise constants can be obtained by showing both curves in the same plot.
https://www.wolframalpha.com/input?i=plot+3.38+i++10%5E-7%282x-1%29%281-%282x-1%29%5E2%29+%281-%281.727%282x-1%29%29%5E2%29+%2B+re%28log%28%28zeta%28x%2B2+pi+i%29%29+%2F+%28Zeta%281-x%2B2+pi+i%29%29%29%29+-+1%2F1887.68++%282x-1%29%281-%282x-1%29%5E2%29+from+0+to+1

And we can plot the difference.
https://www.wolframalpha.com/input?i=plot+-3.38+++10%5E-7%282x-1%29%281-%282x-1%29%5E2%29+%281-%281.727%282x-1%29%29%5E2%29+%2B+re%28log%28%28zeta%28x%2B2+pi+i%29%29+%2F+%28Zeta%281-x%2B2+pi+i%29%29%29%29+-+1%2F1887.68++%282x-1%29%281-%282x-1%29%5E2%29+from+0+to+1

Slightly changing a constant can reduce the number of peaks.
https://www.wolframalpha.com/input?i=plot+-3.41+10%5E-7%282x-1%29%281-%282x-1%29%5E2%29+%281-%281.727%282x-1%29%29%5E2%29+%2B+re%28log%28%28zeta%28x%2B2+pi+i%29%29+%2F+%28Zeta%281-x%2B2+pi+i%29%29%29%29+-+1%2F1887.68++%282x-1%29%281-%282x-1%29%5E2%29+from+0+to+1
« Last Edit: 30/05/2024 07:18:23 by hamdani yusuf »
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Offline hamdani yusuf (OP)

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Re: What makes Riemann's Hypothesis Hard to Prove?
« Reply #149 on: 01/06/2024 08:20:23 »
https://www.wolframalpha.com/input?i=plot+%28log%28%28zeta%28x%2Bi%29%29+-+%28Zeta%28x-i%29%29%29%29from+-20+to+21
The plot shows the log of difference between ζ(s) and its complex conjugate.

https://www.wolframalpha.com/input?i=plot+%28log%28%28zeta%28x%2B0.001i%29%29+-+%28Zeta%28x-0.001i%29%29%29%29from+-10+to+2
And this is for smaller imaginary parts.

https://www.wolframalpha.com/input?i=plot+%28log%28%28zeta%28x%2Bi%29%29+%2F+%28Zeta%28x-i%29%29%29%29from+-20+to+21
While this one shows the ratio

https://www.wolframalpha.com/input?i=plot+%28log%28%28zeta%28x%2Bi%29%29+%2F+%28Zeta%28x-i%29%29%29%29from+-20+to+2
This one is more focused on the negative real of s.

https://www.wolframalpha.com/input?i=plot+%28log%28%28zeta%28x%2B0.001i%29%29+%2F+%28Zeta%28x-0.001i%29%29%29%29from+-10+to+5
And this is for smaller imaginary parts, which reveals where the trivial zeros are, ie negative even integers.
« Last Edit: 08/07/2024 23:21:27 by hamdani yusuf »
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Re: What makes Riemann's Hypothesis Hard to Prove?
« Reply #150 on: 01/06/2024 11:46:39 »
Some geometry behind the Basel problem

This Basel problem is a special case of Zeta function with historical significance. The video shows how to solve it by involving some geometry. It also involves some steps which seem to come out of nowhere, and only becomes clear after further calculations got the problem simplified later on.
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Re: What makes Riemann's Hypothesis Hard to Prove?
« Reply #151 on: 01/06/2024 15:26:03 »
Quote from: hamdani yusuf on 01/06/2024 08:20:23
https://www.wolframalpha.com/input?i=plot+%28log%28%28zeta%28x%2B0.001i%29%29+%2F+%28Zeta%28x-0.001i%29%29%29%29from+-10+to+5
And this is for smaller imaginary parts, which reveals where the trivial zeros are, ie negative integers
https://www.wolframalpha.com/input?i=plot+re%28log%28%28zeta%28x%2B0.001i%29%29+%2F+%28Zeta%28x-0.001i%29%29%29%29from+-10+to+5

https://www.wolframalpha.com/input?i=plot+re%28log%28%28zeta%28x%2B10.00i%29%29+%2F+%28Zeta%28x-10.00i%29%29%29%29from+-10+to+5

When only the real part is shown, the plot seems to have exceeded the precision limit of Wolfram Alpha.
« Last Edit: 01/06/2024 15:28:47 by hamdani yusuf »
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Offline hamdani yusuf (OP)

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Re: What makes Riemann's Hypothesis Hard to Prove?
« Reply #152 on: 02/06/2024 13:06:47 »

Quote
As the degree of the Taylor polynomial rises, it approaches the correct function. This image shows sin x and its Taylor approximations by polynomials of degree 1, 3, 5, 7, 9, 11, and 13 at x = 0.

Example.
The Maclaurin series of the exponential function e^x is

https://en.m.wikipedia.org/wiki/Taylor_series

« Last Edit: 02/06/2024 13:34:21 by hamdani yusuf »
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Re: What makes Riemann's Hypothesis Hard to Prove?
« Reply #153 on: 02/06/2024 13:42:24 »
I'm pretty sure that Riemann Hypothesis can be proven by expressing S function, especially at high imaginary part, in terms of Taylor-MaClaurin series. It will demonstrate that S function can only be zero at critical line, while the imaginary part of its input is higher than (2+β) π i.

Quote from: hamdani yusuf on 29/05/2024 12:04:01
Quote from: hamdani yusuf on 19/05/2024 06:22:53
Quote from: hamdani yusuf on 17/05/2024 05:14:38
We get a nice full wave when the imaginary part is exactly 2*pi
https://www.wolframalpha.com/input?i=plot+re%28log%28zeta%28x%2B+2+pi+i%29+%2F%28Zeta%281-x%2B+2+pi+i%29%29%29%29from+0+to+1

This curve is very similar to a cubic equation 1/1887.68 * (2x-1)(1-(2x-1)^2).
Here's the plot of both curves in the same graph (the cubic equation is multiplied by i).

https://www.wolframalpha.com/input?i=plot+re%28log%28%28zeta%28x%2B2+pi+i%29%29+%2F+%28Zeta%281-x%2B2+pi+i%29%29%29%29+%2B+i%2F1887.68+%282x-1%29%281-%282x-1%29%5E2%29+from+0+to+1

Although when zoomed in, there is still visible difference.
https://www.wolframalpha.com/input?i=plot+re%28log%28%28zeta%28x%2B2+pi+i%29%29+%2F+%28Zeta%281-x%2B2+pi+i%29%29%29%29+%2Bi%2F1887.68+%282x-1%29%281-%282x-1%29%5E2%29+from+0.784+to+0.793

Quote from: hamdani yusuf on 30/05/2024 03:23:16
https://www.wolframalpha.com/input?i=plot+re%28log%28%28zeta%28x%2B2+pi+i%29%29+%2F+%28Zeta%281-x%2B2+pi+i%29%29%29%29+-+1%2F1887.68++%282x-1%29%281-%282x-1%29%5E2%29+from+0+to+1
The difference between S function and the cubic equation looks like a quintic equation.

At a glance, it looks like this
https://www.wolframalpha.com/input?i=plot+%282x-1%29%281-%282x-1%29%5E2%29+%281-%281.7%282x-1%29%29%5E2%29from+0+to+1

« Last Edit: 03/06/2024 01:10:51 by hamdani yusuf »
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Offline hamdani yusuf (OP)

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Re: What makes Riemann's Hypothesis Hard to Prove?
« Reply #154 on: 02/06/2024 14:12:11 »
https://www.wolframalpha.com/input?i=plot+%28log%28zeta%28x%2B999i%29+%2F%28Zeta%281-x%2B999+i%29%29%29%29from+0+to+1

At higher imaginary part, the first degree (a straight line) overwhelmingly dominate the result. It implies that S function can only be zero at critical line, and proves that Riemann hypothesis is true.
« Last Edit: 02/06/2024 14:15:52 by hamdani yusuf »
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Re: What makes Riemann's Hypothesis Hard to Prove?
« Reply #155 on: 02/06/2024 23:16:52 »
Quote from: hamdani yusuf on 02/06/2024 13:42:24
This curve is very similar to a cubic equation 1/1887.68 * (2x-1)(1-(2x-1)^2).
In expanded form, it's
-0.002119 x + 0.00635701 x^2 - 0.00423801 x^3

While the quintic equation is
0.000032259 x^5 - 0.0000806476 x^4 + 0.0000698788 x^3 - 0.0000241707 x^2 + 0.00000268038 x
« Last Edit: 02/06/2024 23:26:47 by hamdani yusuf »
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Re: What makes Riemann's Hypothesis Hard to Prove?
« Reply #156 on: 05/06/2024 09:36:00 »
Quote from: hamdani yusuf on 21/05/2024 04:32:31
Let's observe how S function progresses from 2 pi i down to 0.
https://www.wolframalpha.com/input?i=plot+re%28log%28zeta%28x%2B+2+pi+i%29+%2F%28Zeta%281-x%2B+2+pi+i%29%29%29%29from+-20+to+21

https://www.wolframalpha.com/input?i=plot+re%28log%28zeta%28x%2B++pi+i%29+%2F%28Zeta%281-x%2B++pi+i%29%29%29%29from+-20+to+21

https://www.wolframalpha.com/input?i=plot+re%28log%28zeta%28x%2B++pi+i%29+%2F%28Zeta%281-x%2B++pi+i%29%29%29%29from+-20+to+21

https://www.wolframalpha.com/input?i=plot+re%28log%28zeta%28x%2B+1%2F2+pi+i%29+%2F%28Zeta%281-x%2B+1%2F2+pi+i%29%29%29%29from+-20+to+21

https://www.wolframalpha.com/input?i=plot+re%28log%28zeta%28x%2B+1%2F6+pi+i%29+%2F%28Zeta%281-x%2B+1%2F6+pi+i%29%29%29%29from+-20+to+21

https://www.wolframalpha.com/input?i=plot+re%28log%28zeta%28x%2B+1%2F60+pi+i%29+%2F%28Zeta%281-x%2B+1%2F60+pi+i%29%29%29%29from+-20+to+21

https://www.wolframalpha.com/input?i=plot+re%28log%28zeta%28x%2B+0+i%29+%2F%28Zeta%281-x%2B+0+i%29%29%29%29from+-20+to+21

When the imaginary part is not omitted:
https://www.wolframalpha.com/input?i=plot+%28log%28zeta%28x%2B+0.0+i%29+%2F%28Zeta%281-x%2B+0.0+i%29%29%29%29from+-20+to+21

At high value of x the program seem to exceed its operability range.
https://www.wolframalpha.com/input?i=plot+%28log%28zeta%28x%2B+0.0+i%29+%2F%28Zeta%281-x%2B+0.0+i%29%29%29%29from+-50+to+51
When Im(s)=0, the function shows infinitely tall spikes down on negative real side, and infinitely tall spikes up on positive real side.
With increased imaginary part, the spikes are quickly reduced and smoothed out
Here's the spike around Re(s)=1.
https://www.wolframalpha.com/input?i=plot+re%28log%28zeta%28x%2B+0+i%29+%2F%28Zeta%281-x%2B+0+i%29%29%29%29from+0.5+to+1.5

https://www.wolframalpha.com/input?i=plot+re%28log%28zeta%28x%2B+0.1+i%29+%2F%28Zeta%281-x%2B+0.1+i%29%29%29%29from+0.5+to+1.5

https://www.wolframalpha.com/input?i=plot+re%28log%28zeta%28x%2B+0.2+i%29+%2F%28Zeta%281-x%2B+0.2+i%29%29%29%29from+0.5+to+1.5
We're getting close to inflection point.

https://www.wolframalpha.com/input?i=plot+re%28log%28zeta%28x%2B+0.222892341+i%29+%2F%28Zeta%281-x%2B+0.222892341+i%29%29%29%29from+1.2305+to+1.23075
Here's the more precise inflection point.
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Re: What makes Riemann's Hypothesis Hard to Prove?
« Reply #157 on: 05/06/2024 10:03:35 »
This is the same as the last curve, just zoomed out.
https://www.wolframalpha.com/input?i=plot+re%28log%28zeta%28x%2B+0.222892341+i%29+%2F%28Zeta%281-x%2B+0.222892341+i%29%29%29%29from+0+to+2

https://www.wolframalpha.com/input?i=plot+re%28log%28zeta%28x%2B+0.222892341+i%29+%2F%28Zeta%281-x%2B+0.222892341+i%29%29%29%29from+0+to+20

https://www.wolframalpha.com/input?i=plot+re%28log%28zeta%28x%2B+0.222892341+i%29+%2F%28Zeta%281-x%2B+0.222892341+i%29%29%29%29from+-20+to+21

The peaks are still popping out elsewhere, other than Re(s)=0 and Re(s)=1
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Offline hamdani yusuf (OP)

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Re: What makes Riemann's Hypothesis Hard to Prove?
« Reply #158 on: 05/06/2024 10:17:15 »
https://www.wolframalpha.com/input?i=plot+re%28log%28zeta%28x%2B+0.222892341+i%29+%2F%28Zeta%281-x%2B+0.222892341+i%29%29%29%29from+4+to+10
Let's focus on the highest peak, around Re(s)=7, and the through preceding it, around Re(s)=6.

https://www.wolframalpha.com/input?i=plot+re%28log%28zeta%28x%2B+0.222892341+i%29+%2F%28Zeta%281-x%2B+0.222892341+i%29%29%29%29from+4+to+8

https://www.wolframalpha.com/input?i=plot+re%28log%28zeta%28x%2B+1+i%29+%2F%28Zeta%281-x%2B+1+i%29%29%29%29from+4+to+10
increasing the imaginary part to i smooths the curve further, but some indentations are still visible.

https://www.wolframalpha.com/input?i=plot+re%28log%28zeta%28x%2B+1.5+i%29+%2F%28Zeta%281-x%2B+1.5+i%29%29%29%29from+4+to+10

https://www.wolframalpha.com/input?i=plot+re%28log%28zeta%28x%2B+2+i%29+%2F%28Zeta%281-x%2B+2+i%29%29%29%29from+4+to+10
at 2i, the indentations can't be seen anymore.

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Offline hamdani yusuf (OP)

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Re: What makes Riemann's Hypothesis Hard to Prove?
« Reply #159 on: 07/06/2024 00:45:07 »
https://www.wolframalpha.com/input?i=plot+re%28log%28%28zeta%28x%2B2++i%29%29+%2F+%28Zeta%281-x%2B2++i%29%29%29%29+-+i%2F300%28x%2B13.5%29+%28x-0.5%29+%28x-14%29++from+-20+to+21
Here's a cubic curve with the same zero overlaid in the same plot. They are quite different elsewhere.
« Last Edit: 07/06/2024 01:20:51 by hamdani yusuf »
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