[Kryptid]

The W- boson contains negative charge, but this negative change is only affective at very close range.

Citation needed.

[puppypower]

The W- boson contains negative charge, but this negative change is only affective at very close range.

Citation needed.

The W- boson is connected to the weak nuclear force which only works at close range. If not that negative charge would reduce the number of orbital electrons for charge neutrality.

I copied and pasted the W- boson reaction formula, from WikiPedia, based on the search criteria, "free Neutron".  I went back a few minuted ago to post a link and all traces of W-, in neutron decay, has been purged from the write up. Check quick before it come back. The thieves of science are at work. This idea could make a cool weapon or energy source.

[Kryptid]

The W- boson is connected to the weak nuclear force which only works at close range.

I'm not asking about the range of the weak nuclear force. I'm asking for a citation that supports your assertion that the electric field of the W- is "short-ranged", unlike every other electric field we know of.

[puppypower]

The W- boson is connected to the weak nuclear force which only works at close range.

I'm not asking about the range of the weak nuclear force. I'm asking for a citation that supports your assertion that the electric field of the W- is "short-ranged", unlike every other electric field we know of.

This was based on inference. The W- boson is connected to the weak nuclear force. The weak nuclear force is short range. Innovation comes from looking at the old data in new ways.

https://home.fnal.gov/~cheung/rtes/RTESWeb/LQCD_site/pages/weakforce.htm

The weak force is so named because although it is stronger than gravity, it is only effective at very short distances (10-18 m).  Technically, it is one of the strongest forces, but because the particles involved are so big, their travel is limited to the short distance listed above.  The W and Z bosons that make the weak force weigh in at 80 GeV and 91 GeV respectively.  This is in comparison to the proton, which weighs .9 GeV.

The short range force, connected to the W- boson intermediary of neutron decay, only works short range. This negative charge helps to stabilize positive charge repulsion within the nucleus. However, being short range, the W-  has no impact on the electrons within atomic orbitals. However, electrons within orbitals should be able to impact the W- bosons, since the negative  charges of electron are long range. We should be able to tweak nuclei with exotic electrons orbitals such as oxidation states of -5 or thereabouts. 

[Kryptid]

This was based on inference. The W- boson is connected to the weak nuclear force. The weak nuclear force is short range.

Non-sequitur. You can't say that its electric field is short-ranged because the weak force is short-ranged. That would make no sense.

This negative charge helps to stabilize positive charge repulsion within the nucleus.

No it doesn't, because there aren't normally W- bosons in the nucleus. Well, except for virtual W- bosons. But that's irrelevant because there would also be virtual W+ bosons there as well. Those virtual particles have no effect on the net charge of the nucleus, so they cannot contribute to its stability against electric repulsion.

However, being short range, the W-  has no impact on the electrons within atomic orbitals. However, electrons within orbitals should be able to impact the W- bosons, since the negative  charges of electron are long range.

That claim violates Newton's third law. If the W- bosons can feel the electric repulsion of the electrons' negative charge, then the electrons must also feel that same repulsion from the W- bosons.

[puppypower]

This was based on inference. The W- boson is connected to the weak nuclear force. The weak nuclear force is short range.

Non-sequitur. You can't say that its electric field is short-ranged because the weak force is short-ranged. That would make no sense.

This negative charge helps to stabilize positive charge repulsion within the nucleus.

No it doesn't, because there aren't normally W- bosons in the nucleus. Well, except for virtual W- bosons. But that's irrelevant because there would also be virtual W+ bosons there as well. Those virtual particles have no effect on the net charge of the nucleus, so they cannot contribute to its stability against electric repulsion.

However, being short range, the W-  has no impact on the electrons within atomic orbitals. However, electrons within orbitals should be able to impact the W- bosons, since the negative  charges of electron are long range.

That claim violates Newton's third law. If the W- bosons can feel the electric repulsion of the electrons' negative charge, then the electrons must also feel that same repulsion from the W- bosons.

In terms of your last point, of Newtons third law of action and reaction, let me give you an example of how decoupling is possible.

Consider the twin paradox. I am going to modify this thought experiment, slightly. Say we have two twins, one remains on earth, and the other takes off in a rocket ship traveling close to the speed of light. Because of SR, the moving twin will age slower.

The experiment I will do with this foundation, is have the two twins meet at a restaurant at 7PM. The twin in motion, since his time frame is moving slower, he will see 7PM appear on his watch, later than his stationary brother.  The stationary brother gets to the restaurant at exactly 7PM earth time. His moving brother, who is late by earth time, nevertheless, also gets there at exactly 7PM, but on his watch.

The stationary brother never crosses paths with his moving brother, since the moving brother is late and therefore indeterminate as he waits. The stationary brother, as he waits, is not sure if his brother ever will get there or not.

The moving brother, when he finally does arrive, knows his brother was there, by a artifacts such as a message he gets from the waiter, that came from his brother. The moving brother has proof of the past, and the present, that show both brothers showed up; a rational inference can be made.

On the other hand, when the first brother shows up, all the way to when it  he leaves, he is stuck at a level of  uncertainty; Schrödinger's cat. As he leaves his message ,with the waiter, he is still not sure if his brother is going to be  late, or be a no show. There is no rational way to extrapolate from the lack of data he has. Only the moving brother can do this.

The massive W- boson's negative charge is closer to the analogy of the stationary twin. The election's negative charge as it moves about the atom, is like the moving twin. To interact they need to meet at 7PM. The electron can sense the past of the W- boson's negative charge, but not the W- boson is uncertain of the both past and the future of the electron. It  has no gauging logic since it is always to early to meet or get artifacts.

If you know the past and present for a cyclic affect, you also know the present and future. But if you do not know the past or future, the present connections are inconclusive. Newton's third laws assumes one reference, and not two time references. The cause and affect can decouple but will still be under energy conservation.

If you consider, the singularity of the BB, with space-time all contacted to this point, this is absolute (0,0,0,0) in terms of space-time reference. This is as stationary as you can get. Deviation from there; expansion, adds changes in reference from (0,0,0,0). The huge mass/energy of bosons, relative to protons and then electrons, will create velocity and then time reference difference and decoupling.

[Kryptid]

That is complete nonsense. One particle feeling the field of the other but not vice versa would result in violation of conservation of momentum. So we know that your conclusion on it is wrong. Not to mention that your idea that the electric field of the W- boson is short-ranged because the weak force is short-ranged is as ridiculous as saying that a car's headlight beams must only be able to go as far as the car itself can. The electromagnetic force is not limited in the way that the weak force is.

[puppypower]

That is complete nonsense. One particle feeling the field of the other but not vice versa would result in violation of conservation of momentum. So we know that your conclusion on it is wrong. Not to mention that your idea that the electric field of the W- boson is short-ranged because the weak force is short-ranged is as ridiculous as saying that a car's headlight beams must only be able to go as far as the car itself can. The electromagnetic force is not limited in the way that the weak force is.

Say we assume, for the sake of argument, the negative charge of the W- is long range. The weak nuclear force would not only bind the positive charge of the nucleus protons, but it will impact the electrons via long range interactions. Wouldn't atomic charge balance require fewer orbital electrons?

On the other hand, if the W- was only short range, it only purpose would be to help overcome the positive charge repulsion within the nucleus, while not impacting the electrons due to their distance. The electrons would only feel  the positive charge of the protons and balance is achieved one for one.

My explanation for how this is possible is based on space-time reference and time dilation. Two references, with two different time propagation, cannot synchronize properly. This is similar to the twin paradox and one twin aging faster. His watch is never the same as his brother's watch. They cannot meet using time in their own references.The W- and electron are in different time zones and cannot coordinate affects in real time. Time is how you explain the Heisenberg Uncertainty Principle; Occam's razor. 

In terms of the expansion of the universe, the primordial atom is analogous to the mother of all black holes in terms of space-time reference (0,0,0,0,). It is close to a speed of light reference. Expansion from this singularity, changes the reference,  time begins to speed up. This impacts the W- and Z bosons less due to their massive size. Now we have the time paradox forming that is needed to decouple charge.This interferes with W- charge synchronicity in time and space. The election phase is needed to reduce the inflation period due to positive charge having decoupled from negative charge, via two time references in space-time. The electron is closer in time to the proton but not exact. It does apply the brakes, but with a probably function instead of pure action and reaction; Heisenberg Uncertainty.

[Kryptid]

Wouldn't atomic charge balance require fewer orbital electrons?

No, because (1) they are virtual W- bosons, and (2) an equal amount of virtual W+ bosons would be present. That makes the net charge zero.

[puppypower]

Wouldn't atomic charge balance require fewer orbital electrons?

No, because (1) they are virtual W- bosons, and (2) an equal amount of virtual W+ bosons would be present. That makes the net charge zero.

Bosons have the property of being able to occupy the same quantum state, with no limit as to how many bosons can occur that same quantum state. Bosons are not governed by the Pauli Exclusion principle, which is most commonly applied to election orbitals.

Electrons cannot occupy the same quantum state. Rather each orbital pair of electrons has to have opposite spin, to occupy the same orbital state. Something has to be different for the boson and its charge/integral spin, since it acts neutral, instead of charged, when many similar bosons occupy the same quantum state.

Mass is important in terms of space-time. Mass cannot move at the speed of light, but rather mass can only exist at below the speed light. Mass appears to be a key requirement for space-time. SR or GR both make lots of hoopla over mass and space-time reference, but they do not talk much in terms of charge being needed for space-time references. There is no relativistic charge differences between references.

To go from the pure c-reference, to allow inertial references and space-time, mass needs to appear. Only then do GR and SR apply. SR does not apply to photons as evidence in finite wavelengths and the speed of light.  Mass creates a stable discontinuity between the c-reference and all possible inertial states.

Energy/photons move at the speed of light, but they also show finite characteristics associated with inertial states; wavelength and frequency. These will red and blue shift based on movement between inertial references. Photons define a bridge state between the c-reference and inertial states. The show characteristics of both disconnected references.

The logical sequence of events for universe formation is initially only the c-reference, where space and time can act independent of each other.  Next, there is an bridge state, partly anchored in the c-reference and partly in inertial reference. Then mass appears so it can separate inertial from the c-reference. It is when mass appears that space-time becomes persistent. Energy, without mass for gravity, does not what to self cluster and persist in a definitive way of space, needed for persistent space-time. Energy prefers to occupy new space,keeping space-time in flux.

This is why I start my BB primordial atom analysis with mass; neutron, and then something similar to neutron decay. We need mass to appear, so space-time is able to separate and persistent. The decay produces of the neutron are protons and W- bosons. This will cause inflation, due to positive charge repulsion and since protons cannot occupy the same quantum state. They need elbow room in a hurry.

The other decay product or the heavier W- bosons can occupy the same quantum state, and will get left behind.  The W- then decays into the election and electron neutrino, with the electrons also unable to remain in the same quantum state, as their parent W- . They then expand, even faster, to catch up to the protons. 

The interaction of protons and electrons applies the brakes, giving off lots of energy from which matter and anti-matter appear. Now we can get even more particle variety,  based on this matter foundation.

If you put the brakes on space-time, that was initially inflating faster than the speed of light, one is not dealing with inertial reference during braking, but rather one is really dealing with the c-reference. Only there are space and time independent of each other. If one can move in space without the constraint of time, one can quantum skip forward in space, independent of time. appear to move faster than c, without violating c in space-time.

The brake affect, in terms of the inertial reference, is associated with an entropic potential appearing within the c-reference as reference changes back to inertial. In other words, going from c-reference; inflation, to inertial expansion, will result in a huge loss c-reference entropy, and an increase in inertial reference entropy. This creates diversity and absorbs brake energy. The matter and anti-matter appearance reflects the inertial entropy increase, while the endothermic affect, results in the elections, protons and some neutrons left standing.

In other words, if you increase entropy, this will increase diversity and complexity. It will also absorb an equivalent amount of free energy and make that energy unusable. The second law requires entropy has to increase, which means some energy is no longer net useable. This sets limits on the steady state that can appear.

[Bored chemist]

Mass creates a stable discontinuity between the c-reference and all possible inertial states.

The thread was bad enough without adding  that sort of tosh.

[talanum1]

As a consequence, the hydrogen atom with its spin up proton and spin down electron, can be viewed from its opposite side as an anti-hydrogen atom with a spin-down proton and a spin-up electron.

This is incorrect: an anti-hydrogen atom doesn't just have opposite spins in their constituent parts.