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The condition under which a body is, literally, free to fall under the influence of the local gravitational field with no resistance to its acceleration.
The colloquial use of the term covers falling through air resistance but it isn't strictly correct.
Just pull the column out of the way, sideways. Or push the weight off the column (probably easier to do!)
I'm in strict pedant mode today.
1. It still isn't free fall. The acceleration of the object will depend on its shape.
2. An explosive charge will have some upward force component and the debris and expanding gas beneath the object will have a different composition from the air under the other mass, so its behaviour will be different depending on the nature of the trigger event.
3. Where did the second mass come from? Something must have been holding it up before the explosion!
any aerodynamic properties
You will recall (had you been awake in Physics 101!) that s= ut + 0.5at2where s = distance, t = time and a = accelerationin vacuo, say s = 15 and a = 32. u=0, so 0.5 x 32 x t2 = 15, t= sqrt(15/16) = 0.9682 secondsv = u + at, so speed on hitting the ground = 32 x .9682 = 30.98 ft/sec. This is a long way below the terminal speed of a cannon ball so you would find it difficult to measure the difference between in vacuo and in air arrival times. However http://arc.id.au/CannonballDrag.html shows some surprising results, including a sharp decrease in drag at relatively high Mach numbers - but it's all very dependent on the shape of the projectile, so you can't easily extrapolate from a cannon ball to any other lump of iron.In respect of Quoteany aerodynamic propertiesI repeat that a 100 lb glider will take a lot longer to hit the ground than a 100 lb cannon ball.