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  4. Can black body radiation be represented as a vector?
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Can black body radiation be represented as a vector?

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Offline Richard777 (OP)

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Can black body radiation be represented as a vector?
« on: 23/08/2017 16:29:22 »
If a vector of force represents black body radiation, then the components of force may be associated with energies of heat, light, and rotation.

Assume a particle in circular motion may emit radiation. The rotational energy is associated with emissive power. The definition of emissive power gives the Stefan-Boltzmann constant.

Can a vector of force represent radiation?
* Reference.pdf (157.47 kB - downloaded 155 times.)
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Offline chris

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Re: Can black body radiation be represented as a vector?
« Reply #1 on: 26/08/2017 22:31:39 »
Any takers who can help with this one?
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Offline evan_au

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Re: Can black body radiation be represented as a vector?
« Reply #2 on: 27/08/2017 04:57:38 »
Quote from: Richard777
a vector of force represents black body radiation
This is exactly what happened with the Pioneer Anomaly - black-body radiation from the spacecraft electronics was reflected by the space probe's radio dish, which acted like a Solar Sail.

This caused a tiny force vector pointing towards the Sun, which built up to a measurable velocity change as the space probe traveled billions of miles in the outer solar system. It was only detectable because the spacecraft position and velocity were being continuously measured to extraordinary precision by means of radio telescopes.

Initially, some physicists suspected something exotic (like a divergence from Einstein's gravitation), but it turned out to be something much more ordinary: Black Body Radiation.

See: https://en.wikipedia.org/wiki/Pioneer_anomaly

But most often, for an object with a uniform temperature and a uniform surface coating, the black body radiation will be the same in every direction, and there will be no net force.

Quote
Assume a particle in circular motion may emit radiation.
It is true that to bend the path of a particle into a circular orbit, you must continually accelerate it at right-angles to the direction of motion.
- If you accelerate a charged particle, it will emit radiation in the form of electromagnetic waves
- If you accelerate a massive particle, it will emit radiation in the form of gravitational waves

So you do not want to be in the LHC tunnel when it is operating, as it emits dangerous radiation.

However, the OP seems to assume that electrons are little particles which travel in a circular path around an atom.
This "solar system" model of the atom is useful for beginners, but it's not entirely accurate.
In particular, the electron is not really a little particle traveling in a circle
- It surrounds the nucleus on all sides, in 3D (not a flat 2D structure)
- The electron is not in a particular place at any time, but is "smeared out" around the nucleus.
- The electron is not being accelerated, otherwise it would radiate continuously, and plunge into the nucleus, resulting in all our atoms collapsing almost instantly.

This is best described by Quantum Theory.

See: https://en.wikipedia.org/wiki/Ultraviolet_catastrophe

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The rotational energy is associated with emissive power. The definition of emissive power gives the Stefan-Boltzmann constant.
Black Body radiation, and its relationship with temperature does not require rotational energy of particles.
It is best described by quantum theory.
For Stefan-Boltzmann constant, you could start here: https://en.wikipedia.org/wiki/Stefan%E2%80%93Boltzmann_constant
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Offline jeffreyH

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Re: Can black body radiation be represented as a vector?
« Reply #3 on: 27/08/2017 11:22:58 »
The degree of coherence of the radiation will relate to its entropy.

This is not a straightforward area of research as may first be assumed.
https://arxiv.org/abs/1502.05286
« Last Edit: 27/08/2017 11:30:37 by jeffreyH »
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