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  4. Experiment to test W=mg
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Experiment to test W=mg

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Offline Kryptid

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Re: Experiment to test W=mg
« Reply #120 on: 20/11/2017 01:52:22 »
Quote from: Yaniv on 19/11/2017 08:09:55
A link between weight and temperature disproves F=ma

You haven't demonstrated a link between weight and temperature, so you haven't disproved anything. All you have done is speculate.

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and all mathematical physics based on this equation and requires re-evaluation of all forces and theories.

Given that F=ma has been well-substantiated by experiment, I'd say no.

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But a link between weight and temperature does.

There is no evidence in support of such a link.

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I did not imply a correlation between magnetic field and galactic recession.


Nor did I say that you did.

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The comparison with gravity was an analogy to how new discoveries change our perception of nature.

New discoveries don't change the results of past experiments and observations.

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Maybe. So do you propose to forget the experiment to test your theory ?

I don't have a theory.

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But it would need a really long antenna, would't it ?

Not necessarily. Here's a demonstration of wireless power transfer using a resonant inductive coupling:
.

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Could a link between weight and temperature be the first observation to support light/heat having a negative charge ?

There are no observations of a link between weight and temperature. There is only your speculation.

Here's another way we know that light has no charge: we know that magnetic fields do not have any negative charge. If they did, then positively-charged particles would be attracted to magnetic fields while negatively-charged particles would be repelled by them. In reality, a stationary electric charge is not affected by a magnetic field. A moving electric charge is deflected by a magnetic field such that it will travel in circles around the magnetic field lines (circling in different directions for different charges). That is, however, not attraction or repulsion.

It is also known that a changing magnetic field results in the emission of electromagnetic radiation. Light, of course, is just one set of wavelengths of electromagnetic radiation. Since magnetic fields are not negatively-charged, the electromagnetic radiation emitted by the field also cannot be negatively-charged. If it was, that would mean that negative charged popped up out of nowhere and thus conservation of electric charge has been violated.

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You come up with all the reasons you can think of to avoid doing an experiment to test your theory.

Again, I don't have a theory. This is existing scientific knowledge I'm talking about. I also don't have any means to do any high precision experiments. Besides, I kind of doubt you'd take my word for it if I did do the experiment and reported that you were wrong.

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Even if my theory is wrong this experiment should be carried out to test if your physics is wrong.

Experiments already exist to test modern theories.

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Why are you not interested to test your theory ?

Again I have no theory. Modern scientific theories like relativity have been validated by a myriad of tests already, like the orbital decay rate of the Hulse-Taylor binary neutron star system, time dilation experiments (both gravitational and velocity), gravitational wave detection by LIGO, the perihelion precession of Mercury, gravitational lensing of starlight around the Sun, and the observation of the geodetic effect and frame dragging by Gravity Probe B.

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Are you afraid to discover you are wrong ?

About as much as I'm afraid to discover that the Earth is flat.

Your model proposes that atoms have a net positive charge, but consider hydrogen atoms. The protium isotope of hydrogen atoms is composed of solely of one proton and one electron, so the net charge on such an atom would be the difference between the values of charge on those two particles. Past experiments have observed that, if there is a difference in charge between the proton and electron, it must be smaller in magnitude than 3.6 x 10-19 times the charge on an electron. So if hydrogen atoms have a net positive charge, it cannot be any greater than that value (making it less than 36 million million million times smaller than the charge on a single electron). It may as well not have any charge at all on such a minute scale.
« Last Edit: 20/11/2017 04:32:11 by Kryptid »
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Offline Yaniv (OP)

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Re: Experiment to test W=mg
« Reply #121 on: 20/11/2017 11:55:45 »
Quote from: Kryptid on 20/11/2017 01:52:22
You haven't demonstrated a link between weight and temperature, so you haven't disproved anything. All you have done is speculate.

I didn't get support from the scientific community to conclude the experiment. Only obstructions.

Quote from: Kryptid on 20/11/2017 01:52:22
Given that F=ma has been well-substantiated by experiment, I'd say no.

But not substantiated by the ultimate experiment.

Quote from: Kryptid on 20/11/2017 01:52:22
There is no evidence in support of such a link.

Glaser shows weight decreases at increasing temperature in air. In vacuum ?
Dmitriev also found a link between weight and temperature. But you don't believe it.

Quote from: Kryptid on 20/11/2017 01:52:22
New discoveries don't change the results of past experiments and observations.

New discoveries change explanations of past observations.



Quote from: Kryptid on 20/11/2017 01:52:22
Not necessarily. Here's a demonstration of wireless power transfer using a resonant inductive coupling:

My theory predicts negative particles (light, heat exc) radiated by the bulb should be replaced by negative particles from the environment.

Quote from: Kryptid on 20/11/2017 01:52:22
There are no observations of a link between weight and temperature. There is only your speculation.

Glaser, Dmitriev and my theory.

Quote from: Kryptid on 20/11/2017 01:52:22
Here's another way we know that light has no charge: we know that magnetic fields do not have any negative charge. If they did, then positively-charged particles would be attracted to magnetic fields while negatively-charged particles would be repelled by them. In reality, a stationary electric charge is not affected by a magnetic field. A moving electric charge is deflected by a magnetic field such that it will travel in circles around the magnetic field lines (circling in different directions for different charges). That is, however, not attraction or repulsion.

It is also known that a changing magnetic field results in the emission of electromagnetic radiation. Light, of course, is just one set of wavelengths of electromagnetic radiation. Since magnetic fields are not negatively-charged, the electromagnetic radiation emitted by the field also cannot be negatively-charged. If it was, that would mean that negative charged popped up out of nowhere and thus conservation of electric charge has been violated.

In my theory negative light particles travel too fast to be deflected by magnetic fields in laboratory experiments.


Quote from: Kryptid on 20/11/2017 01:52:22
Again, I don't have a theory. This is existing scientific knowledge I'm talking about.

Rephrase. Are you not interested to test existing scientific knowledge ?

Quote from: Kryptid on 20/11/2017 01:52:22
Experiments already exist to test modern theories.

My experiment is also designed to test modern theories.

Quote from: Kryptid on 20/11/2017 01:52:22
Again I have no theory. Modern scientific theories like relativity have been validated by a myriad of tests already, like the orbital decay rate of the Hulse-Taylor binary neutron star system, time dilation experiments (both gravitational and velocity), gravitational wave detection by LIGO, the perihelion precession of Mercury, gravitational lensing of starlight around the Sun, and the observation of the geodetic effect and frame dragging by Gravity Probe B.

Relativity should also be tested by the ultimate experiment.

Quote from: Kryptid on 20/11/2017 01:52:22
Your model proposes that atoms have a net positive charge, but consider hydrogen atoms. The protium isotope of hydrogen atoms is composed of solely of one proton and one electron, so the net charge on such an atom would be the difference between the values of charge on those two particles. Past experiments have observed that, if there is a difference in charge between the proton and electron, it must be smaller in magnitude than 3.6 x 10-19 times the charge on an electron. So if hydrogen atoms have a net positive charge, it cannot be any greater than that value (making it less than 36 million million million times smaller than the charge on a single electron). It may as well not have any charge at all on such a minute scale.

You are using mathematical physics to explain diverse physical observations. A link between weight and temperature, if exists, disproves F=ma and the basis of your explanations.
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Offline Colin2B

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Re: Experiment to test W=mg
« Reply #122 on: 20/11/2017 14:59:07 »
Quote from: Yaniv on 20/11/2017 11:55:45
[A link between weight and temperature, if exists, disproves F=ma and the basis of your explanations.
No it doesn’t. At best it would show a link between mass and temperature.
@Kryptid has given you many experimental results, consistently tested, that show your theory is incorrect. You need to study enough to understand why before you go any further.
The relationship between force, mass and acceleration are tested regularly in labs, spacecraft, etc, no one is going to publish the results because they are always as expected ie no surprise.
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Offline Yaniv (OP)

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Re: Experiment to test W=mg
« Reply #123 on: 20/11/2017 15:21:12 »
Quote from: Colin2B on 20/11/2017 14:59:07
[A link between weight and temperature, if exists, disproves F=ma and the basis of your explanations.
No it doesn’t. At best it would show a link between mass and temperature.
@Kryptid has given you many experimental results, consistently tested, that show your theory is incorrect. You need to study enough to understand why before you go any further.
The relationship between force, mass and acceleration are tested regularly in labs, spacecraft, etc, no one is going to publish the results because they are always as expected ie no surprise.

F=ma is like W=mg.
m is a constant.
g is a constant (under conditions of the experiment).
A reduction in W at increasing temperature implies a reduction in m or a reduction in g.
My theory predicts (and physics) hot and cold objects should fall at the same rate so g remains a constant.
So a reduction in W is a reduction in m.
#ResultsRequired
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Offline Colin2B

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Re: Experiment to test W=mg
« Reply #124 on: 20/11/2017 18:24:21 »
Quote from: Yaniv on 20/11/2017 15:21:12
My theory predicts (and physics) hot and cold objects should fall at the same rate so g remains a constant.
So a reduction in W is a reduction in m.
#ResultsRequired
Then provide the results.
I don’t intend to waste time on someone who can’t be bothered to look at the experimental evidence as provided by @Kryptid and understand why it disproves your theory.
I’m out.
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Offline Yaniv (OP)

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Re: Experiment to test W=mg
« Reply #125 on: 20/11/2017 18:37:24 »
Quote from: Colin2B on 20/11/2017 18:24:21
Then provide the results.
I don’t intend to waste time on someone who can’t be bothered to look at the experimental evidence as provided by @Kryptid and understand why it disproves your theory.
I’m out.

I understand why you can't be bothered to look at the experimental evidence to disprove conservation of mass.
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Offline Bored chemist

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Re: Experiment to test W=mg
« Reply #126 on: 20/11/2017 19:25:17 »
Quote from: Yaniv on 20/11/2017 18:37:24
Quote from: Colin2B on 20/11/2017 18:24:21
Then provide the results.
I don’t intend to waste time on someone who can’t be bothered to look at the experimental evidence as provided by @Kryptid and understand why it disproves your theory.
I’m out.

I understand why you can't be bothered to look at the experimental evidence to disprove conservation of mass.
Show us some.
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Offline Kryptid

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Re: Experiment to test W=mg
« Reply #127 on: 20/11/2017 20:18:22 »
Quote from: Yaniv on 20/11/2017 11:55:45
I didn't get support from the scientific community to conclude the experiment. Only obstructions.

There is no good reason to believe that the experiment should find anything and as such there's no reason to suspect anything of interest showing up in the experiment.

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But not substantiated by the ultimate experiment.

Your proposed experiment is not the "ultimate" experiment. The "ultimate" experiment would to test the equation directly to see if a given mass with a given acceleration exerts the expected amount of force. This is the kind of thing that is tested all the time in college physics classes. I remember in physics lab, we used to test the validity of equations all the time using experimental set-ups.

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Glaser shows weight decreases at increasing temperature in air. In vacuum ?
Dmitriev also found a link between weight and temperature. But you don't believe it.

Do you have some references for that? Were their experiments independently confirmed by others?

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New discoveries change explanations of past observations.

But not the results.

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My theory predicts negative particles (light, heat exc) radiated by the bulb should be replaced by negative particles from the environment.

Explain how a vacuum can give negative particles to a light bulb that is isolated from other matter and radiation.

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Glaser, Dmitriev and my theory.

Again, references?

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In my theory negative light particles travel too fast to be deflected by magnetic fields in laboratory experiments.

That has absolutely nothing to do with what I said.

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Rephrase. Are you not interested to test existing scientific knowledge ?

Sure, I'm interested in experimental tests of theories. It's being done constantly. So far, relativity has come out on top.

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My experiment is also designed to test modern theories.

It's unnecessary and founded upon faulty premises.

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Relativity should also be tested by the ultimate experiment.

What makes your experiment more "ultimate" than the others?

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You are using mathematical physics to explain diverse physical observations. A link between weight and temperature, if exists, disproves F=ma and the basis of your explanations.

A link between weight and temperature cannot violate conservation of charge, so my math is still very much valid. Heck, my magnetic field refutation didn't even involve math at all.

Here's another problem with your hypothesis: your proposed mechanism for what causes heat particles to move matter will not work. You say that atoms are positively charged and sit inside of positively-charged space which exerts a pressure on the atom from all sides. Then along comes a heat particle that makes one side of the atom slightly less positive than the other side. The first problem with that is that a heat particle cannot change the charge on just one side of an atom. Electrons are constantly moving around all sides of the atom, so any change in the charge of the electron will be distributed equally all around the atom as the electron moves. Even if you are proposing that only one side of the electron has a change in charge (which makes no sense, given that electrons don't have "sides"), then that still won't work because the electron would still be constantly moving around the atom, preventing any net polarization of the atom from occurring.

The second problem is that an atom with lopsided charge still will not be moved by a surrounding positively-charged space. Essentially, you are proposing that space is a scalar field (one which has magnitude but not direction) and therefore has the same value at all locations. It isn't like a vector field, where there is a potential gradient that an object can move through to release potential energy. An atom with lopsided charge will be in just as stable of a configuration at one location in this scalar space field as it would be in another location. It can't reach a lower state of energy by moving and as such it does not move at all.

Another way of looking at it is by thinking about an electric dipole (say, a rod of glass that is positively-charged on one tip and negatively-charged on the other). You take this dipole and submerge it in a positively-charged fluid. Do you think that the tip repelling the fluid and the tip attracting the fluid will cause the dipole to move? Unfortunately, it won't. Although the dipole will experience a force pushing it in the direction of the negative pole (since the negative pole is attracted to the fluid and the positive pole is repelled from it), there is an equal and opposite force pulling the fluid itself towards the negative pole. The fluid will push against the dipole just as strongly as the dipole is pushed against the fluid. This results in no net movement.

It's like a car sitting on the ground. The pressure on the bottom of the tires is much higher than the pressure on the roof of the car. Does this mean that the car should suddenly be propelled upwards because the pressure on the bottom is greater than on the top? No, because it's being matched by another force that is pushing it down: gravity. In your model, an atom with lopsided charge will simply change the configuration of the scalar field around it such that it's slightly more dense at the less-positive side and slightly less dense at the more-positive side. That's it, though. That change in density won't cause it to move any more than the glass dipole would move in the charged fluid.
« Last Edit: 20/11/2017 20:30:36 by Kryptid »
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Offline Yaniv (OP)

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Re: Experiment to test W=mg
« Reply #128 on: 21/11/2017 10:54:46 »
Quote from: Kryptid on 20/11/2017 20:18:22
There is no good reason to believe that the experiment should find anything and as such there's no reason to suspect anything of interest showing up in the experiment.

Not good reason to believe is not good enough for an aspiring scientist like me.

Quote from: Kryptid on 20/11/2017 20:18:22
Your proposed experiment is not the "ultimate" experiment. The "ultimate" experiment would to test the equation directly to see if a given mass with a given acceleration exerts the expected amount of force. This is the kind of thing that is tested all the time in college physics classes. I remember in physics lab, we used to test the validity of equations all the time using experimental set-ups.

Conservation of mass is the most fundamental axiom in physics. More fundamental than F=ma. Which makes my experiment more fundamental.

Quote from: Kryptid on 20/11/2017 20:18:22
Do you have some references for that? Were their experiments independently confirmed by others?

http://iopscience.iop.org/article/10.1088/0026-1394/27/2/008/pdf
http://bourabai.kz/aldmitriev/.
I am not aware of other papers testing a link between weight and temperature.

Quote from: Kryptid on 20/11/2017 20:18:22
New discoveries change explanations of past observations.

But not the results.

New discoveries could change the explanation given to past results.

Quote from: Kryptid on 20/11/2017 20:18:22
Explain how a vacuum can give negative particles to a light bulb that is isolated from other matter and radiation.

Negative light particles radiated from the bulb could be replaced by radio particles from the transmitter ?

 
Quote from: Kryptid on 20/11/2017 20:18:22
Sure, I'm interested in experimental tests of theories. It's being done constantly. So far, relativity has come out on top.

But yet to pass my experiment weighing a heated metal in vacuum.

Quote from: Kryptid on 20/11/2017 20:18:22
It's unnecessary and founded upon faulty premises.

In your opinion.

Quote from: Kryptid on 20/11/2017 20:18:22
Here's another problem with your hypothesis: your proposed mechanism for what causes heat particles to move matter will not work. You say that atoms are positively charged and sit inside of positively-charged space which exerts a pressure on the atom from all sides. Then along comes a heat particle that makes one side of the atom slightly less positive than the other side. The first problem with that is that a heat particle cannot change the charge on just one side of an atom. Electrons are constantly moving around all sides of the atom, so any change in the charge of the electron will be distributed equally all around the atom as the electron moves. Even if you are proposing that only one side of the electron has a change in charge (which makes no sense, given that electrons don't have "sides"), then that still won't work because the electron would still be constantly moving around the atom, preventing any net polarization of the atom from occurring.

I don't understand this paragraph.

Quote from: Kryptid on 20/11/2017 20:18:22
The second problem is that an atom with lopsided charge still will not be moved by a surrounding positively-charged space. Essentially, you are proposing that space is a scalar field (one which has magnitude but not direction) and therefore has the same value at all locations. It isn't like a vector field, where there is a potential gradient that an object can move through to release potential energy. An atom with lopsided charge will be in just as stable of a configuration at one location in this scalar space field as it would be in another location. It can't reach a lower state of energy by moving and as such it does not move at all.

Another way of looking at it is by thinking about an electric dipole (say, a rod of glass that is positively-charged on one tip and negatively-charged on the other). You take this dipole and submerge it in a positively-charged fluid. Do you think that the tip repelling the fluid and the tip attracting the fluid will cause the dipole to move? Unfortunately, it won't. Although the dipole will experience a force pushing it in the direction of the negative pole (since the negative pole is attracted to the fluid and the positive pole is repelled from it), there is an equal and opposite force pulling the fluid itself towards the negative pole. The fluid will push against the dipole just as strongly as the dipole is pushed against the fluid. This results in no net movement.

I can think of an experiment. Place the rod inside a circular anode. My theory predicts the rod will move and settle negative pole in contact with the anode.

Quote from: Kryptid on 20/11/2017 20:18:22
It's like a car sitting on the ground. The pressure on the bottom of the tires is much higher than the pressure on the roof of the car. Does this mean that the car should suddenly be propelled upwards because the pressure on the bottom is greater than on the top? No, because it's being matched by another force that is pushing it down: gravity. In your model, an atom with lopsided charge will simply change the configuration of the scalar field around it such that it's slightly more dense at the less-positive side and slightly less dense at the more-positive side. That's it, though. That change in density won't cause it to move any more than the glass dipole would move in the charged fluid.

I also don't understand relevance of this paragraph.
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Offline Kryptid

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Re: Experiment to test W=mg
« Reply #129 on: 21/11/2017 15:01:35 »
Quote from: Yaniv on 21/11/2017 10:54:46
Not good reason to believe is not good enough for an aspiring scientist like me.

In a world where funds, time and access to technology are unlimited, I'd be all for everyone testing every notion that they want to. However, if you expect scientists to use their (expensive) equipment and valuable time to test your hypothesis, then you'd better be able to convince them that the experiment is worth the effort.

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Conservation of mass is the most fundamental axiom in physics. More fundamental than F=ma. Which makes my experiment more fundamental.

Conservation of mass has already been thoroughly tested and has never once been found to be violated.

Quote
http://iopscience.iop.org/article/10.1088/0026-1394/27/2/008/pdf
http://bourabai.kz/aldmitriev/.
I am not aware of other papers testing a link between weight and temperature.

That first article is behind a paywall, so I cannot see the details. I'll have to read the other papers later when I have more time. However, if these experiments have not been replicated by others, then the results are questionable. I'll know more when I have done some reading there. If these experiments were conducted in an atmosphere, then it's possible that turbulent airflow from convection (due to the increased temperature of the body heating the air around it), could be a complicating factor for the measurements. Even if it did turn out to be correct, it could not possibly be based on your proposed mechanism, since your mechanism violates the laws of physics.

Quote
New discoveries could change the explanation given to past results.

And, like I said before, they can't actually change what the results were.

Quote
Negative light particles radiated from the bulb could be replaced by radio particles from the transmitter ?
The power is being sent in the form of a fluctuating magnetic field. If radio waves produced by that fluctuating field are negatively-charged, then that violates conservation of electric charge because magnetic fields are not charged.

Quote
But yet to pass my experiment weighing a heated metal in vacuum.

There are literally an infinite number of potential experiments that have not been conducted, but that doesn't mean that we should say "Well, we've done dozens of intricate experiments to test relativity and it's passed them all, but there are still more experiments we could do so we might as well say that we don't know anything and put no confidence in relativity (or any other theory in the history of science).

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In your opinion.

No, it's objectively true that it's founded upon faulty premises: your hypothesis violates both conservation of charge and conservation of mass, which have been repeatedly backed up by experiment again and again.

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I don't understand this paragraph.

I also don't understand relevance of this paragraph.

Come to think of it, I may have misunderstood your diagram in reply #6. Just ignore that part.

Quote
I can think of an experiment. Place the rod inside a circular anode. My theory predicts the rod will move and settle negative pole in contact with the anode.

So does existing physics.
« Last Edit: 21/11/2017 15:15:25 by Kryptid »
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Offline Yaniv (OP)

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Re: Experiment to test W=mg
« Reply #130 on: 21/11/2017 16:12:44 »
Quote from: Kryptid on 21/11/2017 15:01:35
In a world where funds, time and access to technology are unlimited, I'd be all for everyone testing every notion that they want to. However, if you expect scientists to use their (expensive) equipment and valuable time to test your hypothesis, then you'd better be able to convince them that the experiment is worth the effort.

My experiment is as much about testing conservation of mass as about testing a prediction of my theory and could save money wasted on faulty theories.

Quote from: Kryptid on 21/11/2017 15:01:35
Conservation of mass has already been thoroughly tested and has never once been found to be violated.

Conservation of mass has not been tested by my experiment.

Quote from: Kryptid on 21/11/2017 15:01:35
That first article is behind a paywall, so I cannot see the details. I'll have to read the other papers later when I have more time. However, if these experiments have not been replicated by others, then the results are questionable. I'll know more when I have done some reading there. If these experiments were conducted in an atmosphere, then it's possible that turbulent airflow from convection (due to the increased temperature of the body heating the air around it), could be a complicating factor for the measurements. Even if it did turn out to be correct, it could not possibly be based on your proposed mechanism, since your mechanism violates the laws of physics.

Glaser claims air currents are responsible for reduction in weight but a 'control' experiment showing weight does not change at increasing temperature in vacuum is missing from his papers.

Quote from: Kryptid on 21/11/2017 15:01:35
And, like I said before, they can't actually change what the results were.

Results remain but explanation of results could change.

Quote from: Kryptid on 21/11/2017 15:01:35
Negative light particles radiated from the bulb could be replaced by radio particles from the transmitter ?
The power is being sent in the form of a fluctuating magnetic field. If radio waves produced by that fluctuating field are negatively-charged, then that violates conservation of electric charge because magnetic fields are not charged.

Could negative particles emitted from the transmitter replaced by negative particles from a battery or the ground ?

Quote from: Kryptid on 21/11/2017 15:01:35
There are literally an infinite number of potential experiments that have not been conducted, but that doesn't mean that we should say "Well, we've done dozens of intricate experiments to test relativity and it's passed them all, but there are still more experiments we could do so we might as well say that we don't know anything and put no confidence in relativity (or any other theory in the history of science).

No other experiment is more fundamental and simple in concept than my experiment.

Quote from: Kryptid on 21/11/2017 15:01:35
No, it's objectively true that it's founded upon faulty premises: your hypothesis violates both conservation of charge and conservation of mass, which have been repeatedly backed up by experiment again and again.

Conservation of mass has not passed my experiment. Could all of physics based on faulty premises ?
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Offline Bored chemist

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Re: Experiment to test W=mg
« Reply #131 on: 21/11/2017 18:01:19 »
Until you come up with a plausible reason why the mas might change, or an experiment that shows that the mass changes, nobody is going to waste significant resources on you.

Quote from: Yaniv on 21/11/2017 16:12:44
My experiment is as much about testing conservation of mass as about testing a prediction of my theory and could save money wasted on faulty theories.

Do you have the slightest idea how accurately the conservation of mass has already been tested?
Quote from: Yaniv on 21/11/2017 16:12:44
Could negative particles emitted from the transmitter replaced by negative particles from a battery or the ground ?
No
Quote from: Yaniv on 21/11/2017 16:12:44
Conservation of mass has not passed my experiment. Could all of physics based on faulty premises ?
It has passe countless other tests- some of which can be done on a bigger scale, and to better precision that yours could.
It's possible that physics is based on faulty ground, but your experiment wouldn't tell us if it was.
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Offline Kryptid

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Re: Experiment to test W=mg
« Reply #132 on: 21/11/2017 21:05:27 »
Quote from: Yaniv on 21/11/2017 16:12:44
My experiment is as much about testing conservation of mass as about testing a prediction of my theory and could save money wasted on faulty theories.

You could make the exact same argument about any proposed experiment.

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Conservation of mass has not been tested by my experiment.

It hasn't passed a hypothetical infinite number of other potential experiments either. Does that mean we can't know that it's true until we've done an infinite number of different experiments?
 
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Glaser claims air currents are responsible for reduction in weight but a 'control' experiment showing weight does not change at increasing temperature in vacuum is missing from his papers.

So he didn't do a control experiment? That's a no-no in science.

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Results remain but explanation of results could change.

So I see we are going in circles here.

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Could negative particles emitted from the transmitter replaced by negative particles from a battery or the ground ?

The light bulb is floating in space, so it's at least hundreds of miles above the ground. The transmitter isn't emitting negative particles. All it's "emitting" is a changing magnetic field (which cannot be negatively-charged). Even if the transmitter was somehow emitting heat particles, how is it going to replenish its supply of lost heat particles? The vast majority of the heat particles are being lost to space by the hot light bulb. The system has to run out of negative heat particles eventually.

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No other experiment is more fundamental and simple in concept than my experiment.

Actually, dropping a weight in a vacuum and letting it hit a high-precision pressure plate would be a simpler experiment to test F=ma.

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Conservation of mass has not passed my experiment. Could all of physics based on faulty premises ?

Like I said before, there are an infinite number of experiments that conservation of mass has not passed (just like there are an infinite number of experiments for the Earth's roundness that have not been passed).

According to the papers you linked, the basis for the "higher temperature equals lower mass" idea is that velocity itself is connected with lower mass (i.e. since hot materials have faster moving particles, their mass is proposed to decrease). I have just realized that there already is experimental equipment that has tested to see how velocity is connected with mass: particle accelerators. Particle accelerators accelerate particles to near the speed of light and have them collide with either other particles or a target material.

If mass decreased with increasing velocity, then these particles should weigh much less at relativistic velocities than they do at rest. This, in turn, would mean significantly less force than expected when they hit their targets and therefore a considerable anomaly in the aftermath of the collision. Given the extreme sensitivity of particle accelerator instruments, such a major deviation from predicted values would easily be picked up and send shockwaves through the physics community. The fact that accelerators have been running for many decades without a single report of anomalous particle weight loss solidly demonstrates that greater velocity does not correlate with reduced mass. There you go. An experimental falsification of this hypothesis.
« Last Edit: 21/11/2017 21:08:09 by Kryptid »
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Offline Yaniv (OP)

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Re: Experiment to test W=mg
« Reply #133 on: 22/11/2017 07:33:06 »
Quote from: Kryptid on 21/11/2017 21:05:27
So he didn't do a control experiment? That's a no-no in science.

Without a 'control' experiment showing weight does not change at increasing temperature in vacuum you can't tell if the air was responsible to the entire loss of weight.

Quote from: Kryptid on 21/11/2017 21:05:27
The light bulb is floating in space, so it's at least hundreds of miles above the ground. The transmitter isn't emitting negative particles. All it's "emitting" is a changing magnetic field (which cannot be negatively-charged). Even if the transmitter was somehow emitting heat particles, how is it going to replenish its supply of lost heat particles? The vast majority of the heat particles are being lost to space by the hot light bulb. The system has to run out of negative heat particles eventually.

The transmitter generates alternating electric currents and every time current is accelerated negative radio particles are emitted and could be replaced by negative particles from a chemical or a nuclear battery or by negative light particles from a solar cell ?

Quote from: Kryptid on 21/11/2017 21:05:27
Actually, dropping a weight in a vacuum and letting it hit a high-precision pressure plate would be a simpler experiment to test F=ma.

I think dropping a weight heated to different temperatures in vacuum onto a pressure plate is a good experiment.

Quote from: Kryptid on 21/11/2017 21:05:27
According to the papers you linked, the basis for the "higher temperature equals lower mass" idea is that velocity itself is connected with lower mass (i.e. since hot materials have faster moving particles, their mass is proposed to decrease). I have just realized that there already is experimental equipment that has tested to see how velocity is connected with mass: particle accelerators. Particle accelerators accelerate particles to near the speed of light and have them collide with either other particles or a target material.

If mass decreased with increasing velocity, then these particles should weigh much less at relativistic velocities than they do at rest. This, in turn, would mean significantly less force than expected when they hit their targets and therefore a considerable anomaly in the aftermath of the collision. Given the extreme sensitivity of particle accelerator instruments, such a major deviation from predicted values would easily be picked up and send shockwaves through the physics community. The fact that accelerators have been running for many decades without a single report of anomalous particle weight loss solidly demonstrates that greater velocity does not correlate with reduced mass. There you go. An experimental falsification of this hypothesis.

In my theory hot and cold objects should fall at the same rate and a reduction in weight at increasing temperature is Not linked to velocity.
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Re: Experiment to test W=mg
« Reply #134 on: 22/11/2017 22:49:44 »
Quote from: Yaniv on 22/11/2017 07:33:06
Without a 'control' experiment showing weight does not change at increasing temperature in vacuum you can't tell if the air was responsible to the entire loss of weight.

So we don't know the cause. That doesn't mean that temperature was what caused the weight decrease, it means that we literally don't know what caused it.

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The transmitter generates alternating electric currents and every time current is accelerated negative radio particles are emitted and could be replaced by negative particles from a chemical or a nuclear battery or by negative light particles from a solar cell ?

Photons, be they radio wave photons or otherwise, cannot be negatively-charged. Electrons and positrons have equal and opposite charges and they can annihilate to create a pair of photons. Since the sum of charge on the electron and positron is zero, the resulting photons must also have zero charge.

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I think dropping a weight heated to different temperatures in vacuum onto a pressure plate is a good experiment.

My experiment doesn't require different temperatures, so it's simpler. It would be awfully convenient if F=ma at room temperature but not at 10 degrees above or below room temperature, don't you think? Why should the Universe think there is anything particularly special about room temperature as defined by humans?

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In my theory hot and cold objects should fall at the same rate and a reduction in weight at increasing temperature is Not linked to velocity.

You do realize that the very thing that makes one object hotter than another is the kinetic energy contained in (and accordingly the velocity of) its component particles, right? Does that mean that you think Dmitriev's experiment showing a supposed loss of mass with increasing temperature was valid but his experiments showing a supposed loss of mass with increasing velocity was not?
« Last Edit: 22/11/2017 23:53:22 by Kryptid »
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Offline Yaniv (OP)

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Re: Experiment to test W=mg
« Reply #135 on: 23/11/2017 01:24:35 »
Quote from: Kryptid on 22/11/2017 22:49:44
Does that mean that you think Dmitriev's experiment showing a supposed loss of mass with increasing temperature was valid but his experiments showing a supposed loss of mass with increasing velocity was not?

I now realize Dmitriev peculiar method of heating is not like normal heating and is complicating my argument. Thanks. In my theory temperature is not related to velocity.

Quote from: Kryptid on 22/11/2017 22:49:44
So we don't know the cause. That doesn't mean that temperature was what caused the weight decrease, it means that we literally don't know what caused it.

That doesn't mean temperature is responsible for a reduction in weight but this should be tested and my theory predicts weight reduction at increasing temperature.

Quote from: Kryptid on 22/11/2017 22:49:44
Photons, be they radio wave photons or otherwise, cannot be negatively-charged.

A simple direct current circuit showing three light bulbs in series (video below). The first bulb is the brightest and the third bulb is the dimmest. In my theory a fraction of electrons are lost as negative light particle in each bulb explaining reduced brightness. How sequential dimming of bulbs is explained by physics ?


Quote from: Kryptid on 22/11/2017 22:49:44
Electrons and positrons have equal and opposite charges and they can annihilate to create a pair of photons. Since the sum of charge on the electron and positron is zero, the resulting photons must also have zero charge.

Not in my physics.

Quote from: Kryptid on 22/11/2017 22:49:44
My experiment doesn't require different temperatures, so it's simpler. It would be awfully convenient if F=ma at room temperature but not at 10 degrees above or below room temperature, don't you think? Why should the Universe think there is anything particularly special about room temperature as defined by humans?

My theory predicts a cold object should register higher pressure than when heated. Heat only the object and keep room temperature normal.



Quote from: Kryptid on 22/11/2017 22:49:44
You do realize that the very thing that makes one object hotter than another is the kinetic energy contained in (and accordingly the velocity of) its component particles, right?

I don't think so. Particles in solids have fixed positions and particles in liquids move around. If temperature was a measure of velocity the temperature at the beginning of the melting process (solid) should be significantly lower than temperature at the end of the melting process (liquid). A typical graph showing temperature remains constant during the melting process.
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Re: Experiment to test W=mg
« Reply #136 on: 23/11/2017 02:21:51 »
Quote from: Yaniv on 23/11/2017 01:24:35
I now realize Dmitriev peculiar method of heating is not like normal heating and is complicating my argument.

A piece of copper heated up by ultrasound is the same as a piece of copper heated up by conduction, radiation or any other method.

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Thanks. In my theory temperature is not related to velocity.

When you start changing the definition of words, you can make anything mean anything.

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That doesn't mean temperature is responsible for a reduction in weight but this should be tested and my theory predicts weight reduction at increasing temperature.

It's not necessary to test your hypothesis because it's already been falsified by existing data. I've shown via many different methods that photons cannot have any appreciable electric charge. Since your model requires light to be charged, your model has already been falsified.

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A simple direct current circuit showing three light bulbs in series (video below). The first bulb is the brightest and the third bulb is the dimmest. In my theory a fraction of electrons are lost as negative light particle in each bulb explaining reduced brightness.

Then your model is incompatible with reality because electrons can't turn into light particles. That would violate conservation laws. If it was possible to convert an electron into a photon, then that would automatically imply that the photon has just as strong of a negative charge as the electron it came from (due to conservation of charge). Since you can create a pair of photons from an electron-positron annihilation, that would mean that you somehow got twice as much negative charge out of the reaction as the electron supplied. That violates conservation of charge. It also violates conservation of lepton number since photons are not leptons.

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How sequential dimming of bulbs is explained by physics ?

The first and second bulb look equally bright to me. I suspect there is something either wrong with the circuit or with the third bulb. I've seen other videos where all of the light bulbs in the series are equally bright, which supports the idea of the third bulb either being nearly burned out, having a damaged contact or some other problem:

Example 1: https://www.youtube.com/watch?v=1t0smFyRj4g
Example 2: https://www.youtube.com/watch?v=LETOaC4ao-E
Example 3: https://www.youtube.com/watch?v=WgfAsAUyEws

So it looks like you've just shot your model in the foot. Since your model predicts that light bulbs normally become sequentially dimmer on a series circuit whereas in reality they normally don't, then you've falsified your own model.

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Not in my physics.

Then your physics is wrong. We know that positrons and electrons have the same magnitude of charge and we know that they can annihilate to produce gamma rays. If your model cannot accommodate those facts, then you either need to change your model or abandon it.

Actually, it turns out that an electron and positron annihilation can sometimes produce three photons instead of two. If a photon had any amount of electric charge at all, then three photons would have to have a different total charge than two photons. Since the starting particles (the positron and electron) are the same in either case, then the only possible charge value that a photon can have without violating charge conservation would be zero (two times zero is zero and three times zero is zero).

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My theory predicts a cold object should register higher pressure than when heated. Heat only the object and keep room temperature normal.

Wait a minute... why are you saying that a change in mass of a heated object would have anything to do with falsifying F=ma? If the mass is different, then that would merely imply that it will yield a different force on impact with a given acceleration. That wouldn't make F=ma wrong.

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I don't think so. Particles in solids have fixed positions and particles in liquids move around.

Particles in solids are not completely fixed: they can rotate and vibrate. The hotter the material is, the faster the particles rotate and vibrate. That's ultimately a manifestation of an increase in internal kinetic energy.

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If temperature was a measure of velocity the temperature at the beginning of the melting process (solid) should be significantly lower than temperature at the end of the melting process (liquid).

The molecules in the liquid at the melting point and the molecules in the solid at the melting point are moving/vibrating/rotating at the same speed, but the molecules in the liquid are free to move around because the intermolecular bonds between the molecules in the solid have been broken by the extra added energy.

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A typical graph showing temperature remains constant during the melting process.


Indeed it does, because the extra energy put into the solid in order to melt it at its melting point is used to break the bonds that hold the solid particles together in a lattice. Breaking the bonds requires energy.
« Last Edit: 23/11/2017 06:19:33 by Kryptid »
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Offline Yaniv (OP)

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Re: Experiment to test W=mg
« Reply #137 on: 23/11/2017 07:05:35 »
Quote from: Kryptid on 23/11/2017 02:21:51
A piece of copper heated up by ultrasound is the same as a piece of copper heated up by conduction, radiation or any other method.

I suspect Dmitriev method of heating is not the same as Glaser normal heating because Dmitriev recorded larger changes in weight (milligrams compared to micrograms).

 
Quote from: Kryptid on 23/11/2017 02:21:51
It's not necessary to test your hypothesis because it's already been falsified by existing data. I've shown via many different methods that photons cannot have any appreciable electric charge. Since your model requires light to be charged, your model has already been falsified.

But it is necessary to test your physics.

Quote from: Kryptid on 23/11/2017 02:21:51
Then your model is incompatible with reality because electrons can't turn into light particles. That would violate conservation laws. If it was possible to convert an electron into a photon, then that would automatically imply that the photon has just as strong of a negative charge as the electron it came from (due to conservation of charge). Since you can create a pair of photons from an electron-positron annihilation, that would mean that you somehow got twice as much negative charge out of the reaction as the electron supplied. That violates conservation of charge. It also violates conservation of lepton number since photons are not leptons.

Weight reduction at increasing temperature certainly violates at least one conservation law.



Quote from: Kryptid on 23/11/2017 02:21:51
The first and second bulb look equally bright to me. I suspect there is something either wrong with the circuit or with the third bulb.

Here is another video showing first bulb brighter and second dimmer.


Quote from: Kryptid on 23/11/2017 02:21:51
Wait a minute... why are you saying that a change in mass of a heated object would have anything to do with falsifying F=ma? If the mass is different, then that would merely imply that it will yield a different force on impact with a given acceleration. That wouldn't make F=ma wrong.

If you believe mass is conserved weight reduction at increasing temperature disproves F=ma.

Quote from: Kryptid on 23/11/2017 02:21:51
The molecules in the liquid at the melting point and the molecules in the solid at the melting point are moving/vibrating/rotating at the same speed, but the molecules in the liquid are free to move around because the intermolecular bonds between the molecules in the solid have been broken by the extra added energy.

I think if temperature was a measure of motion the added free movement of molecules in liquids should have been registered as higher temperature.
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Offline Kryptid

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Re: Experiment to test W=mg
« Reply #138 on: 23/11/2017 07:31:28 »
Quote from: Yaniv on 23/11/2017 07:05:35
I suspect Dmitriev method of heating is not the same as Glaser normal heating because Dmitriev recorded larger changes in weight (milligrams compared to micrograms).

Such a large discrepancy alone strongly suggests experimental error and therefore unreliable results. A piece of copper at, say, 30 degrees C isn't going to "know" how it got to that temperature. It's going to be physically identical regardless of the method of heating.

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But it is necessary to test your physics.

You make it sound like it hasn't already been tested. It has. Many times. Particle accelerators do it all the time. Charge is always conserved.

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Weight reduction at increasing temperature certainly violates at least one conservation law.

Ah, so we're finally in agreement about the violation of charge conservation. As if violating conservation of mass wasn't bad enough on its own. This is exactly why we can put your model to rest now.

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Here is another video showing first bulb brighter and second dimmer.


He explained in the video why the second bulb was dimmer...

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If you believe mass is conserved weight reduction at increasing temperature disproves F=ma.

How? Even if a block of copper at 100 degrees C weighed less than a block at 0 degrees C, why would that automatically mean that you couldn't calculate the force of impact of that copper block using F=ma by dropping it on a pressure plate? All it would mean is that the hot copper block should produce less force on impact than the cold one because it weighs less.

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I think if temperature was a measure of motion the added free movement of molecules in liquids should have been registered as higher temperature.

Temperature is not a measure of how much molecules are allowed to move, it's a measure of their average kinetic energy. That would be like saying that a gas in a 1 milliliter container can't be as hot as a gas in a 1 liter container because the gas molecules in the smaller container don't have as much freedom of movement as those in the large container.
« Last Edit: 23/11/2017 07:39:24 by Kryptid »
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Offline Yaniv (OP)

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Re: Experiment to test W=mg
« Reply #139 on: 23/11/2017 08:58:03 »
Quote from: Kryptid on 23/11/2017 07:31:28
Such a large discrepancy alone strongly suggests experimental error and therefore unreliable results. A piece of copper at, say, 30 degrees C isn't going to "know" how it got to that temperature. It's going to be physically identical regardless of the method of heating.

All this is no excuse not to conclude my experiment to test conservation of mass.

Quote from: Kryptid on 23/11/2017 07:31:28
You make it sound like it hasn't already been tested. It has. Many times. Particle accelerators do it all the time. Charge is always conserved.

You are talking about different experiments to weighing a heated metal in vacuum.

Quote from: Kryptid on 23/11/2017 07:31:28
He explained in the video why the second bulb was dimmer...

He says something about increasing resistance of the whole circuit. This should dim all light bulbs equally ?

Quote from: Kryptid on 23/11/2017 07:31:28
How? Even if a block of copper at 100 degrees C weighed less than a block at 0 degrees C, why would that automatically mean that you couldn't calculate the force of impact of that copper block using F=ma by dropping it on a pressure plate? All it would mean is that the hot copper block should produce less force on impact than the cold one because it weighs less.

If you accept conservation of mass disproved then F=ma can be used to describe several macroscopic phenomena and any extensions to this equation based on conservation of mass falsified. In my theory the whole concept of mass is replaced with charge.

Quote from: Kryptid on 23/11/2017 07:31:28
Temperature is not a measure of how much molecules are allowed to move, it's a measure of their average kinetic energy. That would be like saying that a gas in a 1 milliliter container can't be as hot as a gas in a 1 liter container because the gas molecules in the smaller container don't have as much freedom of movement as those in the large container.

I don't really understand relevance of this paragraph.
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