[Kryptid]

The Earth’s orbital speed is 30 degrees per month.
The orbital speed of the moon is 360 degrees per month.
E = 30/360 = 0.083

Your definition of a month appears to be exactly one-twelfth of a year (so 30.4375 days). With that in mind, why don't we see how well your equation works for another planet?

Mars' orbital period is 686.971 days (22.57 months), so each month it moves 360/22.57 = 15.95 degrees. Its satellite Phobos completes an orbit every 0.319 days (0.01048 months), so each month it moves 360/0.01048 = 34,351.15 degrees. So using your equation, the predicted eccentricity of Phobos' orbit is 34,351.15/15.95 = 2,153.68. That is an impossibly high eccentricity and is over 142,000 times larger than its actual orbital eccentricity.

We can safely say that your equation is solidly falsified.

[Bored chemist]

With that in mind, why don't we see how well your equation works for another planet?

It might work wherever the OP is, but it doesn't work on this planet; it's about 50% out.

[Yusup Hizirov (OP)]

The solar power of Coriolis participates in the formation of the ellipse of the moon.
When the Moon revolving around the Earth in the fourth quarter approaches the Sun at a speed of 1 km / s, and in the second quarter moves away from the Sun at a speed of 1 km / s, the Coriolis Solar Force stretches the moon’s orbit along the Earth’s orbit, which forms an ellipse of the Moon.
When the moon is in the phase of the new moon and the full moon, the Coriolis solar power does not affect the orbit of the moon, because in these phases, the moon does not approach or move away from the sun.
http://www.sat.belastro.net/glava2/glava2.php#p1.2.c
https://en.m.wikipedia.org/wiki/Orbital_eccentricity
The eccentricity of the orbit of the moon can be calculated by the following formula. E = Vz / Vl.
Where Vz - Orbital velocity of the Earth.
Vl - Orbital velocity of the moon.
 
The Earth’s orbital speed is 30 degrees per month.
The orbital speed of the moon is 360 degrees per month.
E = 30/360 = 0.083

The eccentricity of the orbit of the geostationary satellites can be calculated by the following formula. E = Vz / Vi
Where Vz - Orbital velocity of the Earth.
Vi - orbital velocity of the satellite.

The orbital speed of the Earth is 0.98 degrees per day.
The satellite’s orbital speed is 360 degrees per day.
E = 0.98 / 360 = 0.0027

[Bored chemist]

The eccentricity of the orbit of the geostationary satellites can be calculated by the following formula. E = Vz / Vi

Saying it again does not stop it being wrong.

There are satellites in orbit which are geosynchronous- so they have the same orbital period- but have different eccentricities.

https://en.wikipedia.org/wiki/Geosynchronous_orbit#Elliptical_and_inclined_geosynchronous_orbits

Why do you keep posting nonsense, when you could just google it and check?

Do you like looking foolish?
Are you just trolling?

[Yusup Hizirov (OP)]

The Earth’s orbital speed is 30 degrees per month.
The orbital speed of the moon is 360 degrees per month.
E = 30/360 = 0.083

Your definition of a month appears to be exactly one-twelfth of a year (so 30.4375 days). With that in mind, why don't we see how well your equation works for another planet?

Mars' orbital period is 686.971 days (22.57 months), so each month it moves 360/22.57 = 15.95 degrees. Its satellite Phobos completes an orbit every 0.319 days (0.01048 months), so each month it moves 360/0.01048 = 34,351.15 degrees. So using your equation, the predicted eccentricity of Phobos' orbit is 34,351.15/15.95 = 2,153.68. That is an impossibly high eccentricity and is over 142,000 times larger than its actual orbital eccentricity.

We can safely say that your equation is solidly falsified.

Check your calculations.

[Bored chemist]

Check your calculations.

I checked them; they look OK to me.
If you think there's an error, point it out.
Meanwhile...
Check your grasp of reality.

You seem to be still trying to pretend that

The eccentricity of the orbit of the geostationary satellites can be calculated by the following formula. E = Vz / Vi
Where Vz - Orbital velocity of the Earth.
Vi - orbital velocity of the satellite.

In reality, for  geostationary satellites, Vz and Vi are fixed, but E varies.

[Bored chemist]

Also:
https://space.stackexchange.com/questions/30735/why-do-gps-satellites-have-increasing-eccentricity-over-time

[Kryptid]

Check your calculations.

If you got a different result than me, then post your calculation so we can compare them.

[Yusup Hizirov (OP)]

The solar Coriolis effect is involved in the formation of the ellipse of the moon.
When the Moon revolving around the Earth in the fourth quarter approaches the Sun at a speed of 1 km / s, and in the second quarter moves away from the Sun at a speed of 1 km / s, the Coriolis Solar Force stretches the Moon’s orbit along the Earth’s orbit, due to which an ellipse of the Moon is formed.
When the moon is in the phase of the new moon and the full moon, the solar Coriolis effect does not affect the orbit of the moon, because in these phases the moon does not approach and does not move away from the sun.
https://en.m.wikipedia.org/wiki/Orbital_eccentricity

The eccentricity of the orbit of the moon can be calculated by the following formula. E = Vz / Vl.
Where Vz - Orbital velocity of the Earth.
Vl - Orbital velocity of the moon.
The Earth’s orbital speed is 30 degrees per month.
The orbital speed of the moon is 360 degrees per month.
E = 30/360 = 0.083
--------------
The eccentricity of the orbit of the geostationary satellites can be calculated by the following formula. E = Vz / Vi
Where Vz - Orbital velocity of the Earth.
Vi - orbital velocity of the satellite.
The orbital speed of the Earth is 0.98 degrees per day.
The satellite’s orbital speed is 360 degrees per day.
E = 0.98 / 360 = 0.0027
---------------
The eccentricity of the Earth’s orbit can be calculated using the following formula. E = Vs / Vz
Where Vs - "Orbital velocity of the Sun."
Vz - Orbital velocity of the Earth.
"The orbital speed of the Sun is 0.00000144 degrees per year."
The orbital speed of the Earth is 360 degrees per year.
E = 0.00000144 / 360
--------------
The statement that an elliptical orbit is formed as a result of the mutual disturbance of the planets contradicts reality. Venus moves almost in a circular orbit.
Perhaps the reason for the formation of the ellipse of the planets should be sought in the three-body problem. http://www.sat.belastro.net/glava2/glava2.php#p1.2.c

[The Spoon]

The solar Coriolis effect is involved in the formation of the ellipse of the moon.
When the Moon revolving around the Earth in the fourth quarter approaches the Sun at a speed of 1 km / s, and in the second quarter moves away from the Sun at a speed of 1 km / s, the Coriolis Solar Force stretches the Moon’s orbit along the Earth’s orbit, due to which an ellipse of the Moon is formed.
When the moon is in the phase of the new moon and the full moon, the solar Coriolis effect does not affect the orbit of the moon, because in these phases the moon does not approach and does not move away from the sun.
https://en.m.wikipedia.org/wiki/Orbital_eccentricity

The eccentricity of the orbit of the moon can be calculated by the following formula. E = Vz / Vl.
Where Vz - Orbital velocity of the Earth.
Vl - Orbital velocity of the moon.
The Earth’s orbital speed is 30 degrees per month.
The orbital speed of the moon is 360 degrees per month.
E = 30/360 = 0.083
--------------
The eccentricity of the orbit of the geostationary satellites can be calculated by the following formula. E = Vz / Vi
Where Vz - Orbital velocity of the Earth.
Vi - orbital velocity of the satellite.
The orbital speed of the Earth is 0.98 degrees per day.
The satellite’s orbital speed is 360 degrees per day.
E = 0.98 / 360 = 0.0027
---------------
The eccentricity of the Earth’s orbit can be calculated using the following formula. E = Vs / Vz
Where Vs - "Orbital velocity of the Sun."
Vz - Orbital velocity of the Earth.
"The orbital speed of the Sun is 0.00000144 degrees per year."
The orbital speed of the Earth is 360 degrees per year.
E = 0.00000144 / 360
--------------
The statement that an elliptical orbit is formed as a result of the mutual disturbance of the planets contradicts reality. Venus moves almost in a circular orbit.
The mystery of the formation of the orbits of the planets is in the task of three bodies. http://www.sat.belastro.net/glava2/glava2.php#p1.2.c

You keep repeatedly posting the same nonsense. This is just trolling.

[Kryptid]

E = 30/360 = 0.083

As has been pointed out before, this is incorrect. The correct answer is about 0.0549.

The eccentricity of the Earth’s orbit can be calculated using the following formula. E = Vs / Vz
Where Vs - "Orbital velocity of the Sun."
Vz - Orbital velocity of the Earth.
"The orbital speed of the Sun is 0.00000144 degrees per year."
The orbital speed of the Earth is 360 degrees per year.
E = 0.00000144 / 360

You didn't even bother to finish this calculation (which would be 4 x 10^-9). This is, as expected, extremely incorrect (the Earth's orbital eccentricity is actually 0.0167).

I actually do see the error in my previous calculation. I should have divided Mars' orbital period by Phobos' orbital period, no the other way around. This results in a predicted eccentricity of 0.000464. This is still highly incorrect (Phobos' orbital eccentricity is 0.0151).

Why don't I do another calculation to further seal the deal, this time for Pluto and Charon?

Pluto's orbital period is 90,560 days (2,975.28 months), so each month it moves 360/2,975.28 = 0.121 degrees. Its satellite Charon completes an orbit every 6.387 days (0.2098 months), so each month it moves 360/0.2098 = 1,715.92 degrees. So using your equation, the predicted eccentricity of Phobos' orbit is 0.121/1,715.92 = 0.0000705. The correct eccentricity for Charon is about 0.0002. That's yet another nail in your equation's coffin.

Your equation doesn't work. At all.

[Bored chemist]

The eccentricity of the orbit of the moon can be calculated by the following formula. E = Vz / Vl.
Where Vz - Orbital velocity of the Earth.
Vl - Orbital velocity of the moon.

Why tell such an obvious lie?

[Yusup Hizirov (OP)]

I actually do see the error in my previous calculation. I should have divided Mars' orbital period by Phobos' orbital period, no the other way around. This results in a predicted eccentricity of 0.000464. This is still highly incorrect (Phobos' orbital eccentricity is 0.0151).

Show your decision, this is too small a figure.

[Bored chemist]

I actually do see the error in my previous calculation. I should have divided Mars' orbital period by Phobos' orbital period, no the other way around. This results in a predicted eccentricity of 0.000464. This is still highly incorrect (Phobos' orbital eccentricity is 0.0151).

Show your decision, this is too small a figure.

Kryptid already showed their working.

Why don't you show your calculations for Vi/Vz and see what answers you get?

Mind you, it won't help your cause much.

I already pointed out that you can not be right.

In reality, for  geostationary satellites, Vz and Vi are fixed, but E varies.

[Kryptid]

Show your decision, this is too small a figure.

Mars' orbital period is 686.971 days (22.57 months), so each month it moves 360/22.57 = 15.95 degrees. Its satellite Phobos completes an orbit every 0.319 days (0.01048 months), so each month it moves 360/0.01048 = 34,351.15 degrees.

According to your formula, I should divide Mars' orbital velocity by that of Phobos, so 15.95/34,351.15 equals 0.000464. Get out your calculator if you don't believe me.

[Bored chemist]

Yusup,
There's a list of actual eccentricities here.
https://en.wikipedia.org/wiki/Orbital_eccentricity

Does any of them fit your equation?

[Yusup Hizirov (OP)]

Show your decision, this is too small a figure.

Mars' orbital period is 686.971 days (22.57 months), so each month it moves 360/22.57 = 15.95 degrees. Its satellite Phobos completes an orbit every 0.319 days (0.01048 months), so each month it moves 360/0.01048 = 34,351.15 degrees.

According to your formula, I should divide Mars' orbital velocity by that of Phobos, so 15.95/34,351.15 equals 0.000464. Get out your calculator if you don't believe me.

Everything is correct.
----------------
The eccentricity of the Phobos orbit can be calculated by the following formula. E = Vm / Vf
Where Vm - Orbital velocity of Mars.
Vf - Orbital velocity of Phobos.

The orbital speed of Mars is about 16488 hours.
The orbital speed of Phobos is about 7.4 hours.
E = 7.4 / 16488 = 0.000448

[Bored chemist]

Everything is correct.

no.
Not everything.
What you say is incorrect.


Do you understand that we can measure the orbital eccentricity?
We have measured it for Phobos and the real answer is 0.0151

So why are you trying to spin us some line where it's 0.000448

Don't you understand that if your calculation doesn't agree with reality, that doesn't mean that reality is mistaken?

[Yusup Hizirov (OP)]

Yusup,
There's a list of actual eccentricities here.
https://en.wikipedia.org/wiki/Orbital_eccentricity

Does any of them fit your equation?

The eccentricity of the Deimos orbit can be calculated by the following formula. E = Vm / Vd
Where Vm - Orbital velocity of Mars.
Vd - Orbital velocity of Deimos.

The orbital speed of Mars is about 16488 hours.
The orbital speed of Phobos is about 30 hours.

30/16488 = 0.0018

[Yusup Hizirov (OP)]

Everything is correct.

no.
Not everything.
What you say is incorrect.


Do you understand that we can measure the orbital eccentricity?
We have measured it for Phobos and the real answer is 0.0151

So why are you trying to spin us some line where it's 0.000448

Don't you understand that if your calculation doesn't agree with reality, that doesn't mean that reality is mistaken?

Prove that I'm wrong with your formulas.